Python获取一段日期内的工作日和所有日期

Pandas

1、获取工作日：bdate_range

 

import pandas as pd
e = pd.bdate_range('8/7/2019', '8/31/2019')
e.date #获取日期列表

array([datetime.date(2019, 8, 7), datetime.date(2019, 8, 8),
       datetime.date(2019, 8, 9), datetime.date(2019, 8, 12),
       datetime.date(2019, 8, 13), datetime.date(2019, 8, 14),
       datetime.date(2019, 8, 15), datetime.date(2019, 8, 16),
       datetime.date(2019, 8, 19), datetime.date(2019, 8, 20),
       datetime.date(2019, 8, 21), datetime.date(2019, 8, 22),
       datetime.date(2019, 8, 23), datetime.date(2019, 8, 26),
       datetime.date(2019, 8, 27), datetime.date(2019, 8, 28),
       datetime.date(2019, 8, 29), datetime.date(2019, 8, 30)],
      dtype=object)

2、获取所有日期：date_range

e = pd.date_range('8/7/2019', '8/31/2019')
e.date

array([datetime.date(2019, 8, 7), datetime.date(2019, 8, 8),
       datetime.date(2019, 8, 9), datetime.date(2019, 8, 10),
       datetime.date(2019, 8, 11), datetime.date(2019, 8, 12),
       datetime.date(2019, 8, 13), datetime.date(2019, 8, 14),
       datetime.date(2019, 8, 15), datetime.date(2019, 8, 16),
       datetime.date(2019, 8, 17), datetime.date(2019, 8, 18),
       datetime.date(2019, 8, 19), datetime.date(2019, 8, 20),
       datetime.date(2019, 8, 21), datetime.date(2019, 8, 22),
       datetime.date(2019, 8, 23), datetime.date(2019, 8, 24),
       datetime.date(2019, 8, 25), datetime.date(2019, 8, 26),
       datetime.date(2019, 8, 27), datetime.date(2019, 8, 28),
       datetime.date(2019, 8, 29), datetime.date(2019, 8, 30),
       datetime.date(2019, 8, 31)], dtype=object)

　　

转载于:https://www.cnblogs.com/qinghuaL/p/11316434.html