LeetCode best-time-to-buy-and-sell-stock-iii

题目描述


Say you have an array for which the i th element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete at most two transactions.

Note: 
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).



解题思路: 这道题借鉴了别人的一些思想, 建立 b1, s1, b2, s2

其中b1表示第一次买入, s1表示第一次卖出; b2表示第二次买入, s2表示第二次卖出;

初始b1 = Integer.MIN_VALUE, b2 = Integer.MIN_VALUE;  s1 = s2 = 0;

遍历整个数组,然后对这四个值进行重新的比较


public class Solution {
  public int maxProfit(int[] prices) {
		int b1 = Integer.MIN_VALUE;
		int s1 = 0;
		int b2 = Integer.MIN_VALUE;
		int s2 = 0;
		for (int i = 0; i < prices.length; i++) {
			b1 = Math.max(b1, - prices[i]);
			s1 = Math.max(b1 + prices[i], s1);
			b2 = Math.max(b2, s1 - prices[i]);
			s2 = Math.max(b2 + prices[i], s2);
		}
		return s2;
	}
}


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