HDOJ1001 Sum Problem

HDOJ1001

题目

Input
The input will consist of a series of integers n, one integer per line.

Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer. 【输出包括SUM和空行！】

Sample Input1
100

Sample Output1
5050

代码

//C代码
#include
int main()
{
	 int n, i, sum;
 	 sum = 0;
	 while(~scanf("%d", &n))
	 {
  		sum = 0;
  		for(i=1;i<=n;i++)
  		{
   			sum+=i;
  		}
 	 	printf("%d\n\n", sum);      //注意是两个\n
	 }
} 

Conclusion
这一题没有什么难度，就是求从1到n的和。但简单的题目同样要注意要求，否则在OJ上无法通过。