Java实现：LeetCode负二进制数相加

• 题目：
• 
• 代码：

• public class text4 {
      public static void main(String[] args) {
          int[] arr1={1};
          int[] arr2={1};
          int[] arr = addNegabinary(arr1, arr2);
          for (int i=0;i arr1.length) {
              int[] temp = arr1;
              arr1 = arr2;
              arr2 = temp;
          }
  
          int temp,i,j;
          //从每个数组的末尾元素开始
          for(i = arr1.length - 1, j = arr2.length - 1; j > -1; j--, i--) {
              //对应位置的元素+1
              temp = arr1[i] + arr2[j];
              if(temp == 2) {
                  arr1[i] = 0;
                  if(i > 0 && arr1[i - 1] == 1) {
                      arr1[i - 1] = 0;
                      continue;
                  } else if(j > 0 && arr2[j - 1] == 1) {
                      arr2[j - 1] = 0;
                      continue;
                  }
                  temp = arr1.length - i;
                  arr1 = addOne(arr1, i - 1);
                  i = arr1.length - temp;
                  arr1 = addOne(arr1, i - 2);
                  i = arr1.length - temp;
              } else if(temp == 1) {
                  arr1[i] = 1;
              }
          }
          i = 0;
          while(i < arr1.length) {
              if(arr1[i++] != 0) {
                  break;
              }
          }
          //copyOfRange(): 将指定数组的指定范围复制到新数组中
          return Arrays.copyOfRange(arr1, i - 1, arr1.length);
      }
  
      private static int[] addOne(int[] arr, int index) {
          if(index < 0) {
              int[] result = new int[arr.length + 1];
              //arraycopy(): 将指定源数组中的数组从指定位置复制到目标数组的指定位置
              System.arraycopy(arr, 0, result, 1, arr.length);
              result[0] = 1;
              return result;
          }
  
          if(arr[index] == 0) {
              arr[index] = 1;
          } else {
              arr[index] = 0;
              if(index > 0 && arr[index - 1] == 1) {
                  arr[index - 1] = 0;
                  return arr;
              }
              int temp = arr.length - index;
              arr = addOne(arr, index - 1);
              index = arr.length - temp;
              arr = addOne(arr, index - 2);
          }
          return arr;
      }
  }
  

• 结果：
•