切水果游戏曾经是一款风靡手机的休闲游戏，今天要介绍的就是一款网页版的切水果游戏， 由JavaSript和HTML5实现，虽然功能和原版的相差太大，但是基本的功能还是具备了，还是模仿的挺逼真，有一定的JavaSript水平的朋友，可以看看源代码，相信你的JavaSript水平会有很大的提升。
/**
* this file was compiled by jsbuild 0.9.6
* @date Fri, 20 Jul 2012 16:21:18 UTC
* @author dron
* @site 网页链接
*/
void function(global){
var mapping = {}, cache = {};
global.startModule = function(m){
require(m).start();
};
global.define = function(id, func){
mapping[id] = func;
};
global.require = function(id){
if(!/\.js$/.test(id))
id += '.js';
if(cache[id])
return cache[id];
else
return cache[id] = mapping[id]({});
};
}(this);
/**
* @source D:\hosting\demos\fruit-ninja\output\scripts\collide.js
*/
define("scripts/collide.js", function(exports){
var fruit = require("scripts/factory/fruit");
var Ucren = require("scripts/lib/ucren");
var fruits = fruit.getFruitInView();
/**
* 碰撞检测
*/
exports.check = function( knife ){
var ret = [], index = 0;
fruits.forEach(function( fruit ){
var ck = lineInEllipse(
knife.slice( 0, 2 ),
knife.slice( 2, 4 ),
[ fruit.originX, fruit.originY ],
fruit.radius
);
if( ck )
ret[ index ++ ] = fruit;
});
return ret;
};
function sqr(x){
return x * x;
}
function sign(n){
return n < 0 ? -1 : ( n > 0 ? 1 : 0 );
}
function equation12( a, b, c ){
if(a == 0)return;
var delta = b * b - 4 * a * c;
if(delta == 0)
return [ -1 * b / (2 * a), -1 * b / (2 * a) ];
else if(delta > 0)
return [ (-1 * b + Math.sqrt(delta)) / (2 * a), (-1 * b - Math.sqrt(delta)) / (2 * a) ];
}
// 返回线段和椭圆的两个交点，如果不相交，返回 null
function lineXEllipse( p1, p2, c, r, e ){
// 线段：p1, p2 圆心：c 半径：r 离心率：e
if (r <= 0) return;
e = e === undefined ? 1 : e;
var t1 = r, t2 = r * e, k;
a = sqr( t2) * sqr(p1[0] - p2[0]) + sqr(t1) * sqr(p1[1] - p2[1]);
if (a <= 0) return;
b = 2 * sqr(t2) * (p2[0] - p1[0]) * (p1[0] - c[0]) + 2 * sqr(t1) * (p2[1] - p1[1]) * (p1[1] - c[1]);
c = sqr(t2) * sqr(p1[0] - c[0]) + sqr(t1) * sqr(p1[1] - c[1]) - sqr(t1) * sqr(t2);
if (!( k = equation12(a, b, c, t1, t2) )) return;
var result = [
[ p1[0] + k[0] * (p2[0] - p1[0]), p1[1] + k[0] * (p2[1] - p1[1]) ],
[ p1[0] + k[1] * (p2[0] - p1[0]), p1[1] + k[1] * (p2[1] - p1[1]) ]
];
if ( !( ( sign( result[0][0] - p1[0] ) * sign( result[0][0] - p2[0] ) <= 0 ) &&
( sign( result[0][1] - p1[1] ) * sign( result[0][1] - p2[1] ) <= 0 ) ) )
result[0] = null;
if ( !( ( sign( result[1][0] - p1[0] ) * sign( result[1][0] - p2[0] ) <= 0 ) &&
( sign( result[1][1] - p1[1] ) * sign( result[1][1] - p2[1] ) <= 0 ) ) )
result[1] = null;
return result;
}
// 判断计算线段和椭圆是否相交
function lineInEllipse( p1, p2, c, r, e ){
var t = lineXEllipse( p1, p2, c, r, e );
return t && ( t[0] || t[1] );
};
return exports;
});