1059. Prime Factors (25)-PAT

1059. Prime Factors (25)

时间限制

50 ms

内存限制

32000 kB

代码长度限制

16000 B

判题程序

Standard

作者

HE, Qinming

Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p₁^k₁* p₂^k₂ *…*p_m^k_m.

Input Specification:

Each input file contains one test case which gives a positive integer N in the range of long int.

Output Specification:

Factor N in the format N = p₁^k₁ * p₂^k₂ *…*p_m^k_m, where p_i's are prime factors of N in increasing order, and the exponent k_i is the number of p_i -- hence when there is only one p_i, k_i is 1 and must NOT be printed out.

Sample Input:

97532468

Sample Output:

97532468=2^2*11*17*101*1291

推荐指数：※

来源：http://pat.zju.edu.cn/contests/pat-a-practise/1059

这道题目主要是分解质因子。

1.考虑1的情况。

#include
#include
#include
using namespace std;
bool is_prime(long n){
	long i,tmp;
	tmp=sqrt(n)+1;
	for(i=3;i<=tmp;i++){
		if(n%i==0)
			return false;
	}
	return true;
}
int main()
{
	long n,i,tmp,k;
	cin>>n;
	cout<1){
			cout<=1)
			cout<<"*";
		else if(n==1)
			break;
	}
	return 0;
}