SPOJ ONP 简单中缀变后缀 (13.07.07)

Problem code: ONP

Transform the algebraic expression with brackets into RPN form (Reverse Polish Notation). Two-argument operators: +, -, *, /, ^ (priority from the lowest to the highest), brackets ( ). Operands: only letters: a,b,...,z. Assume that there is only one RPN form (no expressions like a*b*c).

Input

t [the number of expressions <= 100]
expression [length <= 400]
[other expressions]

Text grouped in [ ] does not appear in the input file.

Output

The expressions in RPN form, one per line.

Example

Input:
3
(a+(b*c))
((a+b)*(z+x))
((a+t)*((b+(a+c))^(c+d)))

Output:
abc*+
ab+zx+*
at+bac++cd+^*

#include
#include
#include

char stack1[400];
char stack2[400];
int top1, top2;

void deal(char *p) {
    int i, len;
    memset(stack1, 0, sizeof(stack1));
    memset(stack2, 0, sizeof(stack2));
    top1 = 0;
    top2 = 0;
    len = strlen(p);
    for(i = 0; i < len; i++) {
        if(p[i] >= 'a' && p[i] <= 'z')
            printf("%c", p[i]);
        if(p[i] == '(')
            stack1[top1++] = p[i];
        if(p[i] == '+' || p[i] == '-' || p[i] == '*' || p[i] == '/' || p[i] == '^')
            stack2[top2++] = p[i];
        if(p[i] == ')' && stack1[top1-1] == '(') {
            printf("%c", stack2[--top2]);
            top1--;
        }
    }
}

int main() {
    int t;
    scanf("%d", &t);
    getchar();
    while(t--) {
        char str[600];
        gets(str);
        deal(str);
        printf("\n");
    }
}