二叉树 （Z型层次遍历）递归

为什么80%的码农都做不了架构师？>>>   

#include 
using namespace std;

// binary tree node
struct Node
{
    int data;
    Node *left,*right;
    Node(int x)
    {
        data = x;
        left = right = NULL;
    }
};

int height(Node *root)
{
    if (!root)
        return 0;

    int hLeft  = height(root->left);
    int hRight = height(root->right);

    return ((hLeft > hRight) ? (hLeft + 1) : (hRight + 1));
}

void printGivenLevel(Node *root, int level, bool z)
{
    if (!root) return;
    if (level == 1)  cout << root->data << "\t";
    else {
        if (z) {
            printGivenLevel(root->left,  level - 1, z); 
            printGivenLevel(root->right, level - 1, z);
        } else {
            printGivenLevel(root->right, level - 1, z);
            printGivenLevel(root->left,  level - 1, z); 
        }
    }
}

void printLevelOrder(Node *root)
{
    int  h = height(root);
    bool z = true; 
    for (int i = 1; i <= h; i++) {
        printGivenLevel(root, i, z);
        z = !z;
        cout<left = new Node(3);
    root->left->left = new Node(2);
    root->left->right = new Node(1);
    root->left->right->left = new Node(1);
    root->right = new Node(-1);
    root->right->left = new Node(4);
    root->right->left->left = new Node(1);
    root->right->left->right = new Node(2);
    root->right->right = new Node(5);
    root->right->right->right = new Node(2);
    
    cout << "\n------------------------------\n";
    printLevelOrder(root);
    cout << "\n------------------------------\n";

    return 0;
}

输出结果:

------------------------------
1	
-1	3	
2	1	4	5	
2	2	1	1	

------------------------------

 

转载于:https://my.oschina.net/tsh/blog/860917