杭电oj 1001 记录一下

今天因为自己不知道在做什么，然后拖到晚上才做的

 1001题目

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.

 

Input

The input will consist of a series of integers n, one integer per line.

 

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

 

Sample Input

1 100

 

Sample Output

1 5050

 

Author

DOOM III

刚开始，英文不好，然后刚开始以为是输入两个数，先输入第一个起始数字，结果提交发现错误啊，我也是醉了，后来搞百度了一下，发现原来这里不是输入两个数，一个数就好了，刚开始应该是没有难度的题，坚持才是胜利

我的代码是这样的

#include

int main()
{
	int a,b,sum = 0,i=1;
	while(scanf("%d",&b)!=EOF)
	{
		for(i =1;i<=b;i++)
		sum+=i;
		printf("%d\n\n",sum);
		sum=0;
	}
	return 0;
}

    继续坚持，坚持才是胜利。加油