算法打卡，用于自律

题目一

解法

class Solution {
    public int thirdMax(int[] nums) {
        Arrays.sort(nums);
        if(nums.length<3){
            return nums[nums.length-1];
        }
        int p = 1;
        for(int i =nums.length-2;i>=0;i--){
            if(nums[i]==nums[i+1]){
            }else{
                ++p;
                if(p==3){
                    return nums[i];
                }
            }
        }
        return nums[nums.length-1];
    }
}

题目二

 

解法

class Solution {
    public List fizzBuzz(int n) {
        ArrayList list =new ArrayList();
        for(int i = 1;i<=n;i++){
            if(i%3==0&&i%5==0){
                list.add("FizzBuzz");
            }else if(i%3==0){
                list.add("Fizz");
            }else if(i%5==0){
                list.add("Buzz");
            }else{
                list.add(""+i);
            }
        }
        return list;
    }
}

题目三

解法

class Solution {
    public char findTheDifference(String s, String t) {
        int[] q = new int[500];
        for(int i = 0;i

题目四

解法

class Solution {
    public int firstUniqChar(String s) {
        int[] w = new int[60];
        for(int i=0;i

题目五

解法

class Solution {
    public int findMaxConsecutiveOnes(int[] nums) {
        int maxCount = 0, count = 0;
        int n = nums.length;
        for (int i = 0; i < n; i++) {
            if (nums[i] == 1) {
                count++;
            } else {
                maxCount = Math.max(maxCount, count);
                count = 0;
            }
        }
        maxCount = Math.max(maxCount, count);
        return maxCount;
    }
}