在单链表中删除指定值的节点－解法一（Java）

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package live.every.day.CodingInterviewGuide.List;

import java.util.Stack;

/**
 * 题目：
 * 在单链表中删除指定值的节点。
 *
 * 思路：
 * 利用栈或其他容器收集节点。
 *
 * @author Created by LiveEveryDay
 */

public class RemoveNodeInListSolution1 {

    public static class Node {
        public int data;
        public Node next;

        public Node(int data) {
            this.data = data;
        }
    }

    public static Node removeNode(Node head, int data) {
        Stack stack = new Stack<>();
        while (head != null) {
            if (head.data != data) {
                stack.push(head);
            }
            head = head.next;
        }
        while (!stack.isEmpty()) {
            stack.peek().next = head;
            head = stack.pop();
        }
        return head;
    }

    public static void main(String[] args) {
        Node node1 = new Node(1);
        Node node2 = new Node(3);
        Node node3 = new Node(2);
        Node node4 = new Node(3);
        Node node5 = new Node(1);
        node1.next = node2;
        node2.next = node3;
        node3.next = node4;
        node4.next = node5;
        removeNode(node1, 3);
        Node n = node1;
        while (n != null) {
            System.out.printf("%d ", n.data);
            n = n.next;
        }

    }
}

// ------ Output ------
/*
1 2 1
*/