字符串分割成一维数组、二维数组，一维数组与二维数组之间的转换
指定格式的字符串截成一维数组(二维数组)的操作类
做项目时经常会遇到将"1,3,a,b,d"截成一维数组或将"1,a;2,b;3,c;4,d"截成二维数组。虽然String.Split()可以实现，但我感觉在遍历取值时还不是很方便。
所以写下clsArrayList类,专门做这方面的处理。
注：myClass.clsLogHelper 为写错误日志类，在我的博客中有写，有兴趣的朋友可能看一下。
using
System;
using
System.Text;
namespace
myClass
{
class
clsArrayList
{
public
int
p_Count
=-
1
;
//
数据组数
private
string
[] myArray1;
//
一维矩阵
private
string
[,] myArray2;
//
二维矩阵
///
<summary>
///
一维字符串分隔,初始化.例: clsArrayList myArray1List=new clsArrayList("1;2;3;4;5",';')
///
</summary>
///
<param name="strStringSource"></param>
///
<remarks>
gx 2010-04-25
</remarks>
public
clsArrayList(
string
strStringSource,
char
charSepartor)
{
try
{
myArray1
=
strStringSource.Split(charSepartor);
//
截取
p_Count
=
myArray1.Length;
}
catch
(Exception ex)
{
myClass.clsLogHelper.m_CreateErrorLogTxt(
"
clsArrayList(
"
+
strStringSource
+
"
,
"
+
charSepartor
+
"
)
"
,
""
, ex.Message.ToString());
}
}
///
<summary>
///
二维字符串分隔,初始化. 例: clsArrayList myArray1List=new clsArrayList("1,A;2,B;3,C;4,D;5,E" , ';' , ',')
///
</summary>
///
<param name="strStringSource"></param>
///
<param name="strColumnSepartor"></param>
///
<param name="strRowSepartor"></param>
///
<remarks>
gx 2010-04-25
</remarks>
public
clsArrayList(
string
strStringSource,
char
charColumnSepartor,
char
charRowSepartor)
{
try
{
string
[] strColumn;
//
第一次截取 ";"
string
[] strRow;
//
第二次截取 ","
strColumn
=
strStringSource.Split(charColumnSepartor);
//
第一次截取
p_Count
=
strColumn.Length;
myArray2
=
new
string
[p_Count,
2
];
for
(
int
i
=
0
; i
<=
p_Count
-
1
; i
++
)
//
将数据保存 数组 myArray1 中
{
strRow
=
strColumn[i].Split(charRowSepartor);
//
第二次截取
myArray2[i,
0
]
=
strRow[
0
];
myArray2[i,
1
]
=
strRow[
1
];
}
}
catch
(Exception ex)
{
myClass.clsLogHelper.m_CreateErrorLogTxt(
"
clsArrayList(
"
+
strStringSource
+
"
,
"
+
charColumnSepartor
+
"
,
"
+
charRowSepartor
+
"
)
"
,
""
, ex.Message.ToString());
}
}
///
<summary>
///
一维字符串,取值
///
</summary>
///
<param name="intIndex"></param>
///
<returns></returns>
public
string
m_GetItem(
int
intIndex)
{
if
(myArray1
==
null
)
{
return
""
;
}
if
(p_Count
==
-
1
)
{
return
""
;
}
if
(intIndex
>
p_Count
-
1
)
{
return
""
;
}
else
{
return
myArray1[intIndex];
}
}
///
<summary>
///
二维字符串,取值
///
</summary>
///
<param name="intKeyIndex"></param>
///
<param name="intValueIndex"></param>
///
<returns></returns>
///
<remarks>
gx 2010-04-25
</remarks>
public
string
m_GetItem(
int
intKeyIndex,
int
intValueIndex)
{
if
(myArray2
==
null
)
{
return
""
;
}
if
(p_Count
==
-
1
)
{
return
""
;
}
if
(intKeyIndex
>
p_Count
-
1
||
intValueIndex
>
1
)
//
Value为列,二维
{
return
""
;
}
else
{
return
myArray2[intKeyIndex, intValueIndex];
}
}
///
<summary>
///
二维字符串,通过Value 获取Key ,例: m_GetKey("1")
///
</summary>
///
<param name="strValue"></param>
///
<returns></returns>
///
<remarks>
gx 2010-04-25
</remarks>
public
string
m_GetKey(
string
strValue)
{
try
{
if
(myArray2
==
null
)
{
return
""
;
}
if
(p_Count
==
-
1
)
{
return
""
;
}
for
(
int
i
=
0
; i
<=
p_Count
-
1
; i
++
)
//
通过value查找key
{
if
(myArray2[i,
1
]
==
strValue)
{
return
myArray2[i,
0
];
//
返回key的值
}
}
return
""
;
}
catch
(Exception ex)
{
myClass.clsLogHelper.m_CreateErrorLogTxt(
"
clsArrayList(
"
+
strValue
+
"
)
"
,
""
, ex.Message.ToString());
return
""
;
}
}
///
<summary>
///
二维字符串,通过Key 获取Value
///
</summary>
///
<param name="strKey"></param>
///
<returns></returns>
///
<remarks>
gx 2010-04-25
</remarks>
public
string
m_GetValue(
string
strKey)
{
try
{
if
(myArray2
==
null
)
{
return
""
;
}
if
(p_Count
==
-
1
)
{
return
""
;
}
for
(
int
i
=
0
; i
<=
p_Count
-
1
; i
++
)
//
通过key查找value
{
if
(myArray2[i,
0
]
==
strKey)
{
return
myArray2[i,
1
];
//
返回value的值
}
}
return
""
;
}
catch
(Exception ex)
{
myClass.clsLogHelper.m_CreateErrorLogTxt(
"
m_GetValue(
"
+
strKey
+
"
)
"
,
""
, ex.Message.ToString());
return
""
;
一维数组和二维数组的转换表示(C#)
关键:下标的计算
一维->二维
一个n个元素的一维数组，转换为r行c列的二维数组
对于一维数组中任意一个元素的下标i(0 <= i < n)
其对应的二维数组下标为 (i / c, i % c), 显然, 只与列数c有关，而与行数r无关
code like this
int
[] a
=
new
int
[n];
int [,] b = new int [r, c];
for ( int i = 0 ; i < n; i ++ )
b[i / c, i % c] = a[i];
int [,] b = new int [r, c];
for ( int i = 0 ; i < n; i ++ )
b[i / c, i % c] = a[i];
also can write like this
for
(
int
i
=
0
; i
<
r; i
++
)
{
for ( int j = 0 ; j < c; j ++ )
{
b[i, j] = a[i * c + j];
}
}
{
for ( int j = 0 ; j < c; j ++ )
{
b[i, j] = a[i * c + j];
}
}
二维->一维
int
[,] a
=
new
int
[r, c];
int [] b = new int [r * c];
for ( int i = 0 ; i < b.Length; i ++ )
b[i] = a[i / c, i % c];
int [] b = new int [r * c];
for ( int i = 0 ; i < b.Length; i ++ )
b[i] = a[i / c, i % c];