python中如何比较日期大小_python 日期大小比较

输入的日期跟当前日期比较大小

日期在python中 存在time,datetime,string三种形式转化如下

#str转time

time.strptime('2018-09-28',"%Y-%m-%d")

#str转datetime

datetime.datetime.striptime('2018-09-28',"%Y-%m-%d")

#time 转string

time.strftime("%y-%m-%d",time.localtime())

需求实现:

import datetime

import time

#将日期字符串转为时间再比较,time,datetime,str

def valid_date(timestr):

#获取当前时间日期

nowTime_str = datetime.datetime.now().strftime('%Y-%m-%d')

print(nowTime_str)

#mktime参数为struc_time,将日期转化为秒,

e_time = time.mktime(time.strptime(nowTime_str,"%Y-%m-%d"))

print(e_time)

try:

s_time = time.mktime(time.strptime(timestr, '%Y-%m-%d'))

print(s_time)

#日期转化为int比较

diff = int(s_time)-int(e_time)

print(diff)

if diff >= 0:

return 1

else:

print('所查日期不能小于当前时间!!!')

return 0

except Exception as e:

print(e)

return 0

if __name__=='__main__':

valid_date("2018-10-07")

执行结果:

python中如何比较日期大小_python 日期大小比较_第1张图片

你可能感兴趣的:(python中如何比较日期大小)