实现一个 LazyMan

http://web.jobbole.com/89626/

实现一个LazyMan，可以按照以下方式调用:
LazyMan(“Hank”)输出:
Hi! This is Hank!

LazyMan(“Hank”).sleep(10).eat(“dinner”)输出
Hi! This is Hank!
//等待10秒..
Wake up after 10
Eat dinner~

LazyMan(“Hank”).eat(“dinner”).eat(“supper”)输出
Hi This is Hank!
Eat dinner~
Eat supper~

LazyMan(“Hank”).sleepFirst(5).eat(“supper”)输出
//等待5秒
Wake up after 5
Hi This is Hank!
Eat supper

以此类推。

思路如下：首先创建一个任务队列，然后利用next()函数来控制任务的顺序执行。值得注意的还有setTimeout()，因为是采用链式调用，所以代码一直在同一个作用域中执行, 最终导致了消息阻塞。

function _LazyMan(name) {
    this.tasks = [];   
    var self = this;
    var fn =(function(n){
        var name = n;
        return function(){
            console.log("Hi! This is " + name + "!");
            self.next();
        }
    })(name);
    this.tasks.push(fn);
    setTimeout(function(){
        self.next();
    }, 0); // 在下一个事件循环启动任务
}
/* 事件调度函数 */
_LazyMan.prototype.next = function() { 
    var fn = this.tasks.shift();
    fn && fn();
}
_LazyMan.prototype.eat = function(name) {
    var self = this;
    var fn =(function(name){
        return function(){
            console.log("Eat " + name + "~");
            self.next()
        }
    })(name);
    this.tasks.push(fn);
    return this; // 实现链式调用
}
_LazyMan.prototype.sleep = function(time) {
    var self = this;
    var fn = (function(time){
        return function() {
            setTimeout(function(){
                console.log("Wake up after " + time + "s!");
                self.next();
            }, time * 1000);
        }
    })(time);
    this.tasks.push(fn);
   return this;
}
_LazyMan.prototype.sleepFirst = function(time) {
    var self = this;
    var fn = (function(time) {
        return function() {
            setTimeout(function() {
                console.log("Wake up after " + time + "s!");
                self.next();
            }, time * 1000);
        }
    })(time);
    this.tasks.unshift(fn);
    return this;
}
/* 封装 */
function LazyMan(name){
    return new _LazyMan(name);
}