Type:medium
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted from left to right.
The first integer of each row is greater than the last integer of the previous row.
在一个矩阵中找某个数。
bool searchMatrix(vector
if(matrix.empty() || matrix[0].empty()) return false;
int m = matrix.size();
int n = matrix[0].size();
int row = 0;
if(matrix[0][0] > target) return false;
for(int i=0; i if(matrix[i][0] == target) return true; if(matrix[i][0] > target){ row = i - 1; break; }else row = i; } for(int i=0; i if(matrix[row][i] == target) return true; } return false; }