HDOJ2141（Can you find it?）

Can you find it?

Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/10000 K (Java/Others)
Total Submission(s): 888    Accepted Submission(s): 182

Problem Description

Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X.

 

Input

There are many cases. Every data case is described as followed: In the first line there are three integers L, N, M, in the second line there are L integers represent the sequence A, in the third line there are N integers represent the sequences B, in the forth line there are M integers represent the sequence C. In the fifth line there is an integer S represents there are S integers X to be calculated. 1<=L, N, M<=500, 1<=S<=1000. all the integers are 32-integers.

 

Output

For each case, firstly you have to print the case number as the form "Case d:", then for the S queries, you calculate if the formula can be satisfied or not. If satisfied, you print "YES", otherwise print "NO".

 

Sample Input

3 3 3

1 2 3

1 2 3

1 2 3

3

1

4

10

 

Sample Output

Case 1:

NO

YES

NO

 

#include <iostream>
#include <algorithm>
using namespace std;

const int N = 502;

__int64 A[N],B[N],AB[N * N],C[N];
int ca, cb, cab, cc;

bool cmp(__int64 a, __int64 b)
{
    return a < b;
}
void meso()
{
    int i, j, k = 0;
    cab = ca * cb;
    for(i = 0; i < ca; i++)
        for(j = 0; j < cb; j++)
            AB[k++] = A[i] + B[j];
    sort(AB, AB + cab, cmp);
}

bool search(__int64 TX)
{
    int low = 0, high = cab - 1, mid;
    while(low <= high)
    {
        mid = (low + high) / 2;
        if(TX == AB[mid])
            return true;
        else if(TX  < AB[mid])
            high = mid - 1;
        else low = mid + 1;
    }
    return false;
}

int main()
{
    int i,S, kk = 1;
    bool flag;
    __int64 X, TX;
    while(cin>>ca>>cb>>cc)
    {
        for(i = 0; i < ca; i++)
            scanf("%I64d",A + i);
        for(i = 0; i < cb; i++)
            scanf("%I64d",B + i);
        for(i = 0; i < cc; i++)
            scanf("%I64d",C + i);
        meso();
        cout<<"Case "<<kk++<<":"<<endl;
        cin>>S;
        while(S--)
        {
            scanf("%I64d", &X);
            flag = false;
            for(i = 0; i < cc; i++)
            {
                TX = X - C[i];
                if(search(TX))
                {
                    flag = true;
                    break;
                }
            }
            if(flag)
                cout<<"YES"<<endl;
            else
                cout<<"NO"<<endl;
        }
    }
    return 0;
}