例如,访问某个网站一直不通,需要确定此地址是否可访问,服务器返回什么,进而确定问题在于什么。完成这个任务,如果一味希望采用编译型语言来编写这样的代码,实践中的时间和精力是不够的,这个时候就需要发挥脚本的神奇作用!
这里还要注意:不管你是为了Python就业还是兴趣爱好,记住:项目开发经验永远是核心,如果你没有2020最新python入门到高级实战视频教程,可以去小编的Python交流.裙 :七衣衣九七七巴而五(数字的谐音)转换下可以找到了,里面很多新python教程项目,还可以跟老司机交流讨教!
好不夸张的说,能否写出高效实用的脚本代码,直接影响着一个程序员的幸福生活[下班时间]。下面整理 8 个实用的 Python 脚本,需要的时候改改直接用,建议收藏!
1.解决 linux 下 unzip 乱码的问题。
import os
import sys
import zipfile
import argparse
s = '\x1b[%d;%dm%s\x1b[0m'
def unzip(path):
file = zipfile.ZipFile(path,"r")
if args.secret:
file.setpassword(args.secret)
for name in file.namelist():
try:
utf8name=name.decode('gbk')
pathname = os.path.dirname(utf8name)
except:
utf8name=name
pathname = os.path.dirname(utf8name)
#print s % (1, 92, ' >> extracting:'), utf8name
#pathname = os.path.dirname(utf8name)
if not os.path.exists(pathname) and pathname != "":
os.makedirs(pathname)
data = file.read(name)
if not os.path.exists(utf8name):
try:
fo = open(utf8name, "w")
fo.write(data)
fo.close
except:
pass
file.close()
def main(argv):
######################################################
# for argparse
p = argparse.ArgumentParser(description='解决unzip乱码')
p.add_argument('xxx', type=str, nargs='*', \
help='命令对象.')
p.add_argument('-s', '--secret', action='store', \
default=None, help='密码')
global args
args = p.parse_args(argv[1:])
xxx = args.xxx
for path in xxx:
if path.endswith('.zip'):
if os.path.exists(path):
print s % (1, 97, ' ++ unzip:'), path
unzip(path)
else:
print s % (1, 91, ' !! file doesn\'t exist.'), path
else:
print s % (1, 91, ' !! file isn\'t a zip file.'), path
if __name__ == '__main__':
argv = sys.argv
main(argv)
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2.统计当前根目录代码行数。
# coding=utf-8
import os
import time
# 设定根目录
basedir = './'
filelists = []
# 指定想要统计的文件类型
whitelist = ['cpp', 'h']
#遍历文件, 递归遍历文件夹中的所有
def getFile(basedir):
global filelists
for parent,dirnames,filenames in os.walk(basedir):
for filename in filenames:
ext = filename.split('.')[-1]
#只统计指定的文件类型,略过一些log和cache文件
if ext in whitelist:
filelists.append(os.path.join(parent,filename))
#统计一个的行数
def countLine(fname):
count = 0
# 把文件做二进制看待,read.
for file_line in open(fname, 'rb').readlines():
if file_line != '' and file_line != '\n': #过滤掉空行
count += 1
print (fname + '----' , count)
return count
if __name__ == '__main__' :
startTime = time.clock()
getFile(basedir)
totalline = 0
for filelist in filelists:
totalline = totalline + countLine(filelist)
print ('total lines:',totalline)
print ('Done! Cost Time: %0.2f second' % (time.clock() - startTime))
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3.扫描当前目录和所有子目录并显示大小。
import os
import sys
try:
directory = sys.argv[1]
except IndexError:
sys.exit("Must provide an argument.")
dir_size = 0
fsizedicr = {'Bytes': 1,
'Kilobytes': float(1) / 1024,
'Megabytes': float(1) / (1024 * 1024),
'Gigabytes': float(1) / (1024 * 1024 * 1024)}
for (path, dirs, files) in os.walk(directory):
for file in files:
filename = os.path.join(path, file)
dir_size += os.path.getsize(filename)
fsizeList = [str(round(fsizedicr[key] * dir_size, 2)) + " " + key for key in fsizedicr]
if dir_size == 0: print ("File Empty")
else:
for units in sorted(fsizeList)[::-1]:
print ("Folder Size: " + units)
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4.将源目录240天以上的所有文件移动到目标目录。
import shutil
import sys
import time
import os
import argparse
usage = 'python move_files_over_x_days.py -src [SRC] -dst [DST] -days [DAYS]'
description = 'Move files from src to dst if they are older than a certain number of days. Default is 240 days'
args_parser = argparse.ArgumentParser(usage=usage, description=description)
args_parser.add_argument('-src', '--src', type=str, nargs='?', default='.', help='(OPTIONAL) Directory where files will be moved from. Defaults to current directory')
args_parser.add_argument('-dst', '--dst', type=str, nargs='?', required=True, help='(REQUIRED) Directory where files will be moved to.')
args_parser.add_argument('-days', '--days', type=int, nargs='?', default=240, help='(OPTIONAL) Days value specifies the minimum age of files to be moved. Default is 240.')
args = args_parser.parse_args()
if args.days < 0:
args.days = 0
src = args.src # 设置源目录
dst = args.dst # 设置目标目录
days = args.days # 设置天数
now = time.time() # 获得当前时间
if not os.path.exists(dst):
os.mkdir(dst)
for f in os.listdir(src): # 遍历源目录所有文件
if os.stat(f).st_mtime < now - days * 86400: # 判断是否超过240天
if os.path.isfile(f): # 检查是否是文件
shutil.move(f, dst) # 移动文件
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5.扫描脚本目录,并给出不同类型脚本的计数。
import os
import shutil
from time import strftime
logsdir="c:\logs\puttylogs"
zipdir="c:\logs\puttylogs\zipped_logs"
zip_program="zip.exe"
for files in os.listdir(logsdir):
if files.endswith(".log"):
files1=files+"."+strftime("%Y-%m-%d")+".zip"
os.chdir(logsdir)
os.system(zip_program + " " + files1 +" "+ files)
shutil.move(files1, zipdir)
os.remove(files)
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6.下载Leetcode的算法题。
import sys
import re
import os
import argparse
import requests
from lxml import html as lxml_html
try:
import html
except ImportError:
import HTMLParser
html = HTMLParser.HTMLParser()
try:
import cPickle as pk
except ImportError:
import pickle as pk
class LeetcodeProblems(object):
def get_problems_info(self):
leetcode_url = 'https://leetcode.com/problemset/algorithms'
res = requests.get(leetcode_url)
if not res.ok:
print('request error')
sys.exit()
cm = res.text
cmt = cm.split('tbody>')[-2]
indexs = re.findall(r'
(\d+)', cmt)problem_urls = ['https://leetcode.com' + url \
for url in re.findall(
r'
levels = re.findall(r"
(.+?)", cmt)tinfos = zip(indexs, levels, problem_urls)
assert (len(indexs) == len(problem_urls) == len(levels))
infos = []
for info in tinfos:
res = requests.get(info[-1])
if not res.ok:
print('request error')
sys.exit()
tree = lxml_html.fromstring(res.text)
title = tree.xpath('//meta[@property="og:title"]/@content')[0]
description = tree.xpath('//meta[@property="description"]/@content')
if not description:
description = tree.xpath('//meta[@property="og:description"]/@content')[0]
else:
description = description[0]
description = html.unescape(description.strip())
tags = tree.xpath('//div[@id="tags"]/following::a[@class="btn btn-xs btn-primary"]/text()')
infos.append(
{
'title': title,
'level': info[1],
'index': int(info[0]),
'description': description,
'tags': tags
}
)
with open('leecode_problems.pk', 'wb') as g:
pk.dump(infos, g)
return infos
def to_text(self, pm_infos):
if self.args.index:
key = 'index'
elif self.args.title:
key = 'title'
elif self.args.tag:
key = 'tags'
elif self.args.level:
key = 'level'
else:
key = 'index'
infos = sorted(pm_infos, key=lambda i: i[key])
text_template = '## {index} - {title}\n' \
'~{level}~ {tags}\n' \
'{description}\n' + '\n' * self.args.line
text = ''
for info in infos:
if self.args.rm_blank:
info['description'] = re.sub(r'[\n\r]+', r'\n', info['description'])
text += text_template.format(**info)
with open('leecode problems.txt', 'w') as g:
g.write(text)
def run(self):
if os.path.exists('leecode_problems.pk') and not self.args.redownload:
with open('leecode_problems.pk', 'rb') as f:
pm_infos = pk.load(f)
else:
pm_infos = self.get_problems_info()
print('find %s problems.' % len(pm_infos))
self.to_text(pm_infos)
def handle_args(argv):
p = argparse.ArgumentParser(description='extract all leecode problems to location')
p.add_argument('--index', action='store_true', help='sort by index')
p.add_argument('--level', action='store_true', help='sort by level')
p.add_argument('--tag', action='store_true', help='sort by tag')
p.add_argument('--title', action='store_true', help='sort by title')
p.add_argument('--rm_blank', action='store_true', help='remove blank')
p.add_argument('--line', action='store', type=int, default=10, help='blank of two problems')
p.add_argument('-r', '--redownload', action='store_true', help='redownload data')
args = p.parse_args(argv[1:])
return args
def main(argv):
args = handle_args(argv)
x = LeetcodeProblems()
x.args = args
x.run()
if __name__ == '__main__':
argv = sys.argv
main(argv)
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7.将 Markdown 转换为 HTML。
import sys
import os
from bs4 import BeautifulSoup
import markdown
class MarkdownToHtml:
headTag = '
'def __init__(self,cssFilePath = None):
if cssFilePath != None:
self.genStyle(cssFilePath)
def genStyle(self,cssFilePath):
with open(cssFilePath,'r') as f:
cssString = f.read()
self.headTag = self.headTag[:-7] + ''.format(cssString) + self.headTag[-7:]
def markdownToHtml(self, sourceFilePath, destinationDirectory = None, outputFileName = None):
if not destinationDirectory:
# 未定义输出目录则将源文件目录(注意要转换为绝对路径)作为输出目录
destinationDirectory = os.path.dirname(os.path.abspath(sourceFilePath))
if not outputFileName:
# 未定义输出文件名则沿用输入文件名
outputFileName = os.path.splitext(os.path.basename(sourceFilePath))[0] + '.html'
if destinationDirectory[-1] != '/':
destinationDirectory += '/'
with open(sourceFilePath,'r', encoding='utf8') as f:
markdownText = f.read()
# 编译出原始 HTML 文本
rawHtml = self.headTag + markdown.markdown(markdownText,output_format='html5')
# 格式化 HTML 文本为可读性更强的格式
beautifyHtml = BeautifulSoup(rawHtml,'html5lib').prettify()
with open(destinationDirectory + outputFileName, 'w', encoding='utf8') as f:
f.write(beautifyHtml)
if __name__ == "__main__":
mth = MarkdownToHtml()
# 做一个命令行参数列表的浅拷贝,不包含脚本文件名
argv = sys.argv[1:]
# 目前列表 argv 可能包含源文件路径之外的元素(即选项信息)
# 程序最后遍历列表 argv 进行编译 markdown 时,列表中的元素必须全部是源文件路径
outputDirectory = None
if '-s' in argv:
cssArgIndex = argv.index('-s') +1
cssFilePath = argv[cssArgIndex]
# 检测样式表文件路径是否有效
if not os.path.isfile(cssFilePath):
print('Invalid Path: '+cssFilePath)
sys.exit()
mth.genStyle(cssFilePath)
# pop 顺序不能随意变化
argv.pop(cssArgIndex)
argv.pop(cssArgIndex-1)
if '-o' in argv:
dirArgIndex = argv.index('-o') +1
outputDirectory = argv[dirArgIndex]
# 检测输出目录是否有效
if not os.path.isdir(outputDirectory):
print('Invalid Directory: ' + outputDirectory)
sys.exit()
# pop 顺序不能随意变化
argv.pop(dirArgIndex)
argv.pop(dirArgIndex-1)
# 至此,列表 argv 中的元素均是源文件路径
# 遍历所有源文件路径
for filePath in argv:
# 判断文件路径是否有效
if os.path.isfile(filePath):
mth.markdownToHtml(filePath, outputDirectory)
else:
print('Invalid Path: ' + filePath)
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8.文本文件编码检测与转换。
import sys
import os
import argparse
from chardet.universaldetector import UniversalDetector
parser = argparse.ArgumentParser(description = '文本文件编码检测与转换')
parser.add_argument('filePaths', nargs = '+',
help = '检测或转换的文件路径')
parser.add_argument('-e', '--encoding', nargs = '?', const = 'UTF-8',
help = '''
目标编码。支持的编码有:
ASCII, (Default) UTF-8 (with or without a BOM), UTF-16 (with a BOM),
UTF-32 (with a BOM), Big5, GB2312/GB18030, EUC-TW, HZ-GB-2312, ISO-2022-CN, EUC-JP, SHIFT_JIS, ISO-2022-JP,
ISO-2022-KR, KOI8-R, MacCyrillic, IBM855, IBM866, ISO-8859-5, windows-1251, ISO-8859-2, windows-1250, EUC-KR,
ISO-8859-5, windows-1251, ISO-8859-1, windows-1252, ISO-8859-7, windows-1253, ISO-8859-8, windows-1255, TIS-620
''')
parser.add_argument('-o', '--output',
help = '输出目录')
# 解析参数,得到一个 Namespace 对象
args = parser.parse_args()
# 输出目录不为空即视为开启转换, 若未指定转换编码,则默认为 UTF-8
if args.output != None:
if not args.encoding:
# 默认使用编码 UTF-8
args.encoding = 'UTF-8'
# 检测用户提供的输出目录是否有效
if not os.path.isdir(args.output):
print('Invalid Directory: ' + args.output)
sys.exit()
else:
if args.output[-1] != '/':
args.output += '/'
# 实例化一个通用检测器
detector = UniversalDetector()
print()
print('Encoding (Confidence)',':','File path')
for filePath in args.filePaths:
# 检测文件路径是否有效,无效则跳过
if not os.path.isfile(filePath):
print('Invalid Path: ' + filePath)
continue
# 重置检测器
detector.reset()
# 以二进制模式读取文件
for each in open(filePath, 'rb'):
# 检测器读取数据
detector.feed(each)
# 若检测完成则跳出循环
if detector.done:
break
# 关闭检测器
detector.close()
# 读取结果
charEncoding = detector.result['encoding']
confidence = detector.result['confidence']
# 打印信息
if charEncoding is None:
charEncoding = 'Unknown'
confidence = 0.99
print('{} {:>12} : {}'.format(charEncoding.rjust(8),
'('+str(confidence*100)+'%)', filePath))
if args.encoding and charEncoding != 'Unknown' and confidence > 0.6:
# 若未设置输出目录则覆盖源文件
outputPath = args.output + os.path.basename(filePath) if args.output else filePath
with open(filePath, 'r', encoding = charEncoding, errors = 'replace') as f:
temp = f.read()
with open(outputPath, 'w', encoding = args.encoding, errors = 'replace') as f:
f.write(temp)
最后两个脚本内容选至实验楼的课程《使用 Python3 编写系列实用脚本》课程对这两个脚本有详细的实现过程讲解,最后注意:不管你是为了Python就业还是兴趣爱好,记住:项目开发经验永远是核心,如果你没有2020最新python入门到高级实战视频教程,可以去小编的Python交流.裙 :七衣衣九七七巴而五(数字的谐音)转换下可以找到了,里面很多新python教程项目,还可以跟老司机交流讨教!
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