三子棋游戏--C语言

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一、三子棋

平时生活中玩的三子棋游戏。

二、实现

1.玩家和电脑端进行对战

（1）头文件：game.h
（2）测试类：test.c
（3）具体实现类：game.h

test()：

#include "game.h"

void menue() {
	printf("*******************************************\n");
	printf("*************    1. play     **************\n");
	printf("*************    0. exit     **************\n");
	printf("*******************************************\n");
}

//判断输赢
//1、玩家赢 2、电脑赢 3、平局
static void if_win(char board[ROW][COL], int row, int col) {
	int flag = 1;
	for (int i = 0; i <= row; i++) {
		for (int j = 0; j < col; j++) {
			if (board[i][j] != '*') {
				flag = 0;
				break;
			}
		}
	}
}


void game() {
	
	char board[ROW][COL] = {0};
	//初始化数组
	InitBoard(board, ROW, COL);
	//打印棋盘
	//DisplayBoard(board, ROW, COL);
	
	char ret = 0;
	while (1) {
		//玩家下棋
		player_move(board, ROW, COL);
		DisplayBoard(board, ROW, COL);

		//判断输赢
		ret = is_win(board, ROW, COL);
		if (ret != 'C') {
			break;
		}
		//电脑下棋
		computer_move(board, ROW, COL);
		DisplayBoard(board, ROW, COL);

		//判断输赢
		ret = is_win(board, ROW, COL);
		if (ret != 'C') {
			break;
		}
	}
	if (ret == '*') {
		printf("玩家赢！\n");
	}
	else if (ret == '#') {
		printf("电脑赢！\n");
	}
	else {
		printf("平局！\n");
	}
}

void test() {
	int input = 0;
	srand ((unsigned int)time(NULL));
	do {
		menue();
		int command;
		printf("请选择->");
		scanf("%d", &command);
		switch (command) {
		case 1:
			game();
			break;
		case 0:
			printf("退出游戏\n");
			break;
		default:
			printf("请重新输入\n");
		}
	} while (input);
}

int main() {
	test();

	return 0;
}

game()：

#include "game.h"

//初始化棋盘
void InitBoard(char board[ROW][COL], int row, int col) {
	for (int i = 0; i < row; i++) {
		for (int j = 0; j < col; j++) {
			board[i][j] = ' ';
		}
	}
}

//打印棋盘
void DisplayBoard(char board[ROW][COL], int row, int col) {
	for (int i = 0; i < row; i++) {
		for (int j = 0; j < col; j++) {
			printf(" %c ", board[i][j]);
			if (j < col - 1) {
				printf("|");
			}
		}
		printf("\n");
		if (i < row - 1) {
			for (int j = 0; j < col; j++) {
				if (j < col - 1) {
					printf("---|");
				}
				else {
					printf("---");
				}
			}
			printf("\n");
		}
	}
}

//玩家下棋
void player_move(char board[ROW][COL], int row, int col) {
	int x, y;
	printf("*************    玩家下棋     **************\n");
	while (1) {
		printf("请输入坐标->");
		scanf("%d %d", &x, &y);
		if (x >= 1 && y >= 1 && x <= row && y <= col) {
			if (board[x-1][y-1] == ' ') {
				board[x-1][y-1] = '*';
				break;
			}
			else {
				printf("您输入的坐标已被占用，请重新输入\n");
			}
		}
		else {
			printf("非法坐标，请重新输入\n");
		}
	}

}

//电脑下棋
void computer_move(char board[ROW][COL], int row, int col) {
	while (1) {
		int x = rand() % row;
		int y = rand() % col;
		if (board[x][y] == ' ') {
			board[x][y] = '#';
			break;
		}
	}
}

//判断棋格是否满了
int if_full(char board[ROW][COL], int row, int col) {

	for (int i = 0; i < row; i++) {
		for (int j = 0; j < col; j++) {
			if (board[i][j] == ' ') {
				return 0;
			}
		}
	}
	return 1;
}

//判断输赢
char is_win(char board[ROW][COL], int row, int col) {
	//三种情况赢：行、列、对角线 一种平局：棋盘满了
	//判断行
	for (int i = 0; i < row; i++) {
		
		if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ' ') {
			return board[i][0];
		}
	}

	//判断列
	for (int j = 0; j < col; j++) {
		if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[0][j] != ' ') {
			return board[0][j];
		}
	}

	//判断对角线
	if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[0][0] != ' ') {
		return board[0][0];
	}
	if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[0][2] != ' ') {
		return board[0][2];
	}

	//判断平局
	if (if_full(board, row, col) == 1) {
		return 'Q';
	}
	else {
		return 'C';
	}
}

2.展示

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总结

多个数的情况下判断行列对角线的情况暂时还没写出来！！！