获取文件属性简单的方法

$file_path = 'image/123.jpg';

$fileInfo = getimagesize($file_path);

if ($fileInfo !== false){
$imageType = strtolower(substr(image_type_to_extension($fileInfo[2]), 1));

$info = array(
    'windth' => $fileInfo[0],
    'height' => $fileInfo[1],
    'type' => $imageType,
    'size' => filesize($file_path),
    'mime' => $fileInfo['mime']
);

print_r($info);

}

输出

Array
(
[windth] => 1200
[height] => 800
[type] => jpeg
[size] => 171751
[mime] => image/jpeg
)

image.png