problems of planetary model:
to solve the prablom of planetary model:
Old Quantum Theory: Planck, Einstein, Bohr, de Broglie
from de Broglie’s Hypothesis, the motion of a particle is governed by the wave propagation properties of matter wave, which means wave function.
In method of Quantum Mechanics, we should get the Schrodinger Equation and solve it, then find the wave function ψ \psi ψ.
Schrodinger Equation (very important):
i ℏ ∂ Ψ ∂ t = − ℏ 2 2 m ∇ 2 Ψ + U Ψ i\hbar \frac{\partial \Psi}{\partial t}=-\frac{\hbar^2}{2m}\nabla^2 \Psi+U\Psi iℏ∂t∂Ψ=−2mℏ2∇2Ψ+UΨ
KaTeX parse error: Undefined control sequence: \pPsi at position 24: …\frac{\partial \̲p̲P̲s̲i̲}{\partial t}= …
wave function of free particle: ψ ( r ⃗ , t ) = A e − i ℏ ( E t − p ⋅ r ) \psi (\vec r, t)=A e^{-\frac{i}{\hbar} (Et-p \cdot r)} ψ(r,t)=Ae−ℏi(Et−p⋅r)
E ⟶ i ℏ ∂ ∂ t E \longrightarrow i \hbar \frac{\partial}{\partial t} E⟶iℏ∂t∂
p ⟶ − i ℏ ∇ \mathbf{p} \longrightarrow - i\hbar \nabla p⟶−iℏ∇
i ℏ ∂ Ψ ∂ t = − ℏ 2 2 m ∇ 2 Ψ + U Ψ i \hbar \frac{\partial \Psi}{\partial t}= - \frac{\hbar^2}{2m}\nabla^2\Psi + U \Psi iℏ∂t∂Ψ=−2mℏ2∇2Ψ+UΨ
We consider time-independent Schrodinger Equation:
U ( r , t ) ⟶ U ( r ) U(\mathbf{r},t) \longrightarrow U(\mathbf{r}) U(r,t)⟶U(r)
then separation of variables: KaTeX parse error: Undefined control sequence: \math at position 28: …f{r} ,t)= \psi(\̲m̲a̲t̲h̲{r})f(t)
Halmiton operator: H ^ = − ℏ 2 2 m ∇ 2 + U \hat H = -\frac{\hbar^2}{2m} \nabla^2+U H^=−2mℏ2∇2+U
so the Schrodinger Equ becomes a new style:
H ^ ψ = E ψ \hat H \psi = E \psi H^ψ=Eψ
H ^ Ψ = i ℏ ∂ ∂ t Ψ \hat H \Psi = i\hbar \frac{\partial }{\partial t} \Psi H^Ψ=iℏ∂t∂Ψ
− ( ℏ 2 2 m d 2 d x 2 + U ( x ) ) ψ ( x ) = E ψ ( x ) -(\frac{\hbar^2}{2m}\frac{d^2}{dx^2}+U(x))\psi (x) = E \psi(x) −(2mℏ2dx2d2+U(x))ψ(x)=Eψ(x)
ψ ( x ) = 2 a s i n n π a x \psi (x) = \sqrt{\frac{2}{a}}sin{\frac{n \pi}{a}x} ψ(x)=a2sinanπx
E = E n = π 2 ℏ 2 2 m a 2 n 2 , n = 1 , 2 , 3 , … E=E_n = \frac{\pi^2 \hbar^2}{2ma^2}n^2, n = 1, 2, 3, \dots E=En=2ma2π2ℏ2n2,n=1,2,3,…
− ( ℏ 2 2 m d 2 d x 2 + 1 2 m ω 2 x 2 ) ψ ( x ) = E ψ ( x ) -(\frac{\hbar^2}{2m}\frac{d^2}{dx^2}+\frac{1}{2}m\omega^2 x^2)\psi (x) = E \psi(x) −(2mℏ2dx2d2+21mω2x2)ψ(x)=Eψ(x)
E n = ( n + 1 2 ) ℏ ω = ( n + 1 2 ) h ν , n = 0 , 1 , 2 , 3 , … E_n = (n + \frac{1}{2})\hbar \omega = (n+\frac{1}{2})h \nu, n = 0, 1, 2, 3, \dots En=(n+21)ℏω=(n+21)hν,n=0,1,2,3,…
( − ℏ 2 2 m d 2 d x 2 + U ( x ) ) ψ ( x ) = E ψ ( x ) (-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}+U(x))\psi(x) = E\psi(x) (−2mℏ2dx2d2+U(x))ψ(x)=Eψ(x)
Quantum Tunneling
( − ℏ 2 2 m ∇ 2 + U ) ψ = E ψ , ∇ 2 = ∂ 2 ∂ x 2 + ∂ 2 ∂ y 2 + ∂ 2 ∂ z 2 (-\frac{\hbar^2}{2m}\nabla^2 + U)\psi = E\psi, \nabla^2 = \frac{\partial^2}{\partial x^2}+\frac{\partial^2}{\partial y^2}+\frac{\partial^2}{\partial z^2} (−2mℏ2∇2+U)ψ=Eψ,∇2=∂x2∂2+∂y2∂2+∂z2∂2
Schrodinger equ. becomes:
1 r 2 ∂ ∂ r ( r 2 ∂ ψ ∂ r ) + 1 r 2 sin θ ∂ ∂ θ ( sin θ ∂ ψ ∂ θ ) + 1 r 2 sin 2 θ ∂ 2 θ ∂ ϕ 2 + 2 m ℏ ( E − U ) ψ = 0 \frac{1}{r^2} \frac{\partial}{\partial r}(r^2 \frac{\partial \psi}{\partial r}) +\frac{1}{r^2 \sin{\theta}} \frac{\partial}{\partial \theta}(\sin{\theta} \frac{\partial \psi}{\partial \theta}) + \frac{1}{r^2\sin^2{\theta}}\frac{\partial^2\theta}{\partial \phi^2} +\frac{2m}{\hbar}(E-U)\psi = 0 r21∂r∂(r2∂r∂ψ)+r2sinθ1∂θ∂(sinθ∂θ∂ψ)+r2sin2θ1∂ϕ2∂2θ+ℏ2m(E−U)ψ=0
use seperation of variables: ψ ( r , θ , ϕ ) = R ( r ) Θ ( θ ) Φ ( ϕ ) \psi(r, \theta, \phi) = R(r) \Theta(\theta) \Phi(\phi) ψ(r,θ,ϕ)=R(r)Θ(θ)Φ(ϕ)
Schrodinger equ. becomes:
− sin 2 θ R d d r ( r 2 d R d r ) − 2 m ℏ 2 r 2 sin 2 θ ( E − U ) − sin θ Θ = 0 \frac{-\sin^2{\theta}}{R} \frac{d}{dr}(r^2\frac{dR}{dr}) -\frac{2m}{\hbar^2} r^2 \sin^2{\theta} (E-U) -\frac{\sin{\theta}}{\Theta} = 0 R−sin2θdrd(r2drdR)−ℏ22mr2sin2θ(E−U)−Θsinθ=0
Both Equal to a constant
{ 1 Φ d 2 Φ d ϕ 2 = − m l 2 m l 2 sin 2 θ − 1 Θ 1 sin θ d d θ ( sin θ d Θ d t h e t a ) = l ( l + 1 ) 1 R d d r ( r 2 d R d r ) + 2 m ℏ 2 r 2 ( E − U ) = l ( l + 1 ) \begin{cases} \frac{1}{\Phi} \frac{d^2\Phi}{d\phi^2} = -m_l^2 \\ \frac{m_l^2}{\sin^2{\theta}} -\frac{1}{\Theta} \frac{1}{\sin{\theta}} \frac{d}{d\theta} (\sin{\theta} \frac{d\Theta}{dtheta}) =l(l+1) \\ \frac{1}{R} \frac{d}{dr}(r^2 \frac{dR}{dr})+\frac{2m}{\hbar^2} r^2(E-U) = l(l+1) \end{cases} ⎩ ⎨ ⎧Φ1dϕ2d2Φ=−ml2sin2θml2−Θ1sinθ1dθd(sinθdthetadΘ)=l(l+1)R1drd(r2drdR)+ℏ22mr2(E−U)=l(l+1)
(1) ϕ \phi ϕ must be single-valued: m l = 0 , ± 1 , ± 2 , … m_l = 0, \pm 1, \pm2, \dots ml=0,±1,±2,…
(2) Θ \Theta Θ must be finite: l = 0 , 1 , 2 , … a n d l ≥ ∣ m l ∣ l = 0, 1, 2, \dots and \ \ l \ge |m_l| l=0,1,2,…and l≥∣ml∣
(3) R must be finite: E = E n = − Z 2 e 4 m 8 ϵ 0 2 h 2 1 n 2 , n = 1 , 2 , 3 , … a n d l < n E=E_n = -\frac{Z^2e^4 m}{8 \epsilon_0^2 h^2}\frac{1}{n^2}, \ n= 1, 2, 3, \dots \ \ and \ \ l
{ 主量子数 n : p r i n c i p l e q u a n t u m n u m b e r ⟶ d e c i d e E n 角量子数 l : o r b i t a l q u a n t u m n u m b e r ⟶ 0 , 1 , 2 , … , n − 1 磁量子数 m l : m a g n e t i c q u a n t u m n u m b e r ⟶ 0 , ± 1 , ± 2 , ± 3 , … , ± l \begin{cases} 主量子数 \ \ n:\ principle\ quantum\ number\ \longrightarrow\ decide\ E_n\\ 角量子数 \ \ l:\ orbital\ quantum\ number\ \longrightarrow\ 0, 1, 2, \dots , n-1 \\ 磁量子数 \ \ m_l: \ magnetic\ quantum\ number\ \longrightarrow\ 0, \pm 1, \pm2, \pm 3, \dots, \pm l \end{cases} ⎩ ⎨ ⎧主量子数 n: principle quantum number ⟶ decide En角量子数 l: orbital quantum number ⟶ 0,1,2,…,n−1磁量子数 ml: magnetic quantum number ⟶ 0,±1,±2,±3,…,±l
不考虑自旋,量子数=波函数个数=量子态数=轨道数
Pauli’s Exclusion Principle: not 2 electrons in a system ( an atom or a solid ) can be in the same quantum state ( have the same n, l, m l m_l ml, m s m_s ms)
A system with N identical micro-particles, without either generation of new particles or vanishing of existed particles, without energy exchange—an isolated system
energy level: E 1 , E 2 , E 3 , … , E l , … E_1, E_2, E_3, \dots,E_l, \dots E1,E2,E3,…,El,…
degeneracy: ω 1 , ω 2 , ω 3 , … . ω l , … \omega_1, \omega_2,\omega_3,\dots.\omega_l,\dots ω1,ω2,ω3,….ωl,…
particle number: a 1 , a 2 , a 3 , … , a l , … a_1, a_2, a_3, \dots,a_l,\dots a1,a2,a3,…,al,…
全同性原理给量子统计和经典统计带来重要差别;
泡利不相容原理又给费米子和玻色子的统计带来重要差别。
自旋为 ± 1 2 \pm\frac{1}{2} ±21的粒子服从泡利不相容原理。
Every particle is identified, the number of particles in an quantum state is unlimited.
标号可分辨,能级上粒子数无限制
a l = ω l e α + β E l a_l = \frac{\omega_l}{e^{\alpha+\beta E_l}} al=eα+βElωl
Boltzmann statistics: f l = a l ω l = 1 e α + β E l = 1 e E l − μ k B T f_l = \frac{a_l}{\omega_l} = \frac{1}{e^{\alpha+\beta E_l}} = \frac{1}{e^{ \frac{E_l-\mu}{k_B T} }} fl=ωlal=eα+βEl1=ekBTEl−μ1
Every particle is unidentified, the number of particles in an quantum state is unlimited.
(photon,phonon…) - Boson
玻色子:声子、光子
不可分辨,能级上粒子无限
a l = ω l e α + β E l − 1 a_l = \frac{\omega_l}{e^{\alpha+\beta E_l} -1} al=eα+βEl−1ωl
Bose-Einstein statistics: f l = a l ω l = 1 e α + β E l − 1 = 1 e E l − μ k B T − 1 f_l = \frac{a_l}{\omega_l} = \frac{1}{e^{\alpha+\beta E_l}-1} = \frac{1}{e^{ \frac{E_l-\mu}{k_B T} } -1} fl=ωlal=eα+βEl−11=ekBTEl−μ−11
Every particle is unidentified, the number of particles in an quantum state is limited by Pauli repulsive principle.
(electron, proton…) - Fermion
费米子:电子、质子
不可分辨,能级上粒子个数有限
a l = ω l e α + β E l + 1 a_l = \frac{\omega_l}{e^{\alpha+\beta E_l} +1} al=eα+βEl+1ωl
Fermi-Dirac statistics: f l = a l ω l = 1 e α + β E l + 1 = 1 e E l − μ k B T + 1 f_l = \frac{a_l}{\omega_l} = \frac{1}{e^{\alpha+\beta E_l}+1} = \frac{1}{e^{ \frac{E_l-\mu}{k_B T} } +1} fl=ωlal=eα+βEl+11=ekBTEl−μ+11
α = − μ k B T , β = 1 k B t \alpha = - \frac{\mu}{k_B T},\ \ \ \beta = \frac{1}{k_B t} α=−kBTμ, β=kBt1
potential between two atoms: U ( R ) = − a R m + b R n U(R)=\frac{-a}{R^m}+\frac{b}{R^n} U(R)=Rm−a+Rnb
A higher binding energy means a higher melting point!
Ionic bond is formed between atoms with large differences in electronegativity. (电负性相差较大)
binding energy: 150~370 kcal/mol
Cohesive Energy in Ionic Crystal
U ( r ) = − N a q 2 4 π ϵ 0 2 r + N B ′ r n U(r) = - \frac{Naq^2}{4\pi \epsilon_0^2 r} +\frac{NB'}{r^n} U(r)=−4πϵ02rNaq2+rnNB′
Madelung constant: B ′ = ∑ j = 1 2 N − 1 b l j n , α = ∑ j = 1 2 N − 1 δ j l j B' = \sum_{j=1}^{2N-1} \frac{b}{l_j^n}, \ \ \ \ \alpha = \sum_{j=1}^{2N-1} \frac{\delta_j}{l_j} B′=j=1∑2N−1ljnb, α=j=1∑2N−1ljδj
The bigger the cell, the more exactness the Madelung constant is.
basic concept:
Crystal Structure = Lattice + Basis
primitive vectors 基矢
position vectors 格矢
primitive unit cell 原胞
conventional unit cell 晶胞
Bravais Lattice 布拉伐点阵:The geometric pattern of basis’ arrangement; all points of the lattice is identical.
Bravais lattice only summarizes the geometry of crystals, regardless of what the actual units may be.
The basis consists of the atoms, their spaces and bond angles.
Bravais lattice:
number of atoms per unit cell: n
the number of nearest neighbors, or Coordination Number: CN 配位数
Atomic Packing Factor: APF 原子堆积因数
A P F = v o l u m e o f a t o m s i n u n i t c e l l v o l u m e o f u n i t c e l l APF = \frac{volume\ \ of \ \ atoms \ \ in \ \ unit \ \ cell}{volume \ \ of \ \ unit\ \ cell} APF=volume of unit cellvolume of atoms in unit cell
Atomic Radius: 原子半径
晶体衍射得到的图象(衍射斑点)是倒易点阵的二维投影空间放大。
Fourier series: 傅里叶级数
f ( x + 2 π ) = f ( x ) f(x+2\pi) = f(x) f(x+2π)=f(x)
f ( x ) = a 0 2 + ∑ n = 1 ∞ ( a n cos n x + b n sin n x ) f(x) = \frac{a_0}{2}+\sum_{n=1}^{\infty}(a_n \cos {nx} +b_n \sin{nx}) f(x)=2a0+n=1∑∞(ancosnx+bnsinnx)
f ( x ) = ∑ n c n e i n x , c n = 1 2 π ∫ − π π f ( x ) e − i n x d x f(x) =\sum_n c_n e^{inx},\ \ \ c_n = \frac{1}{2\pi} \int_{-\pi}^{\pi} f(x)e^{-inx}dx f(x)=n∑cneinx, cn=2π1∫−ππf(x)e−inxdx
Reciprocal lattice (space): 倒易点阵,晶体空间周期性
reciprocal space & wave-vector space (k-space): 倒易空间和波矢空间(k空间)
u ( x , t ) = A cos ( ω t − k x + ϕ 0 ) u(x,t) = A \cos (\omega t - k x +\phi_0) u(x,t)=Acos(ωt−kx+ϕ0)
u ~ ( x , t ) = A ~ e i ( ω t − k x ) \widetilde{u}(x,t) =\widetilde{A} e^{i(\omega t - k x)} u (x,t)=A ei(ωt−kx)
k = 2 π λ n ^ , b = 2 π a i ^ , G = 2 π p a i ^ \mathbf{k} = \frac{2 \pi}{\lambda} \hat n ,\ \ \mathbf{b} = \frac{2\pi}{a} \hat i ,\ \ \mathbf{G} = \frac{2\pi p}{a}\hat i k=λ2πn^, b=a2πi^, G=a2πpi^
The Bragg Law:将晶体视作平行等距的晶面,将晶体对电磁波的衍射看作一组组晶面对电磁波的反射
2 d sin θ = n λ 2d \sin{\theta} = n\lambda 2dsinθ=nλ
入射和散射的电磁波波程差:
KaTeX parse error: Undefined control sequence: \mathcf at position 35: …cos \theta ' = \̲m̲a̲t̲h̲c̲f̲{d} \cdot (\mat…$
Laue Equ (与布拉格定律等价的晶体衍射关系): k ′ − k = G , Δ k = G \mathbf{ k' - k = G, \ \ \ \Delta k = G} k′−k=G, Δk=G
2 k ⋅ G = G 2 2 \mathbf{k} \cdot \mathbf{G} = G^2 2k⋅G=G2
晶体衍射的实际过程真实存在的:电子束,样品台(晶体),接收屏上的衍射斑点。
其他的(倒易点阵、Laue Equ、Ewald球)都是虚拟的,但是它们可以帮助分析衍射的过程和原理、以及衍射斑点的位置。
以一个格点为原点O,找到原点O与其他格点的连线的中垂面,这些中垂面形成许多封闭区域,即布里渊区。
包围原点且最近的叫做第一布里渊区,此后称为第二、第三,以此类推。
Brillouin Zone Interface & Crystal diffraction
发生晶体衍射的条件: