Given two binary trees, write a function to check if they are the
same or not.
Two binary trees are considered the same if they are structurally
identical and the nodes have the same value.
Input: 1 1
/ \ / \
2 3 2 3
[1,2,3], [1,2,3]
Output: true
Input: 1 1
/ \
2 2
[1,2], [1,null,2]
Output: false
Input: 1 1
/ \ / \
2 1 1 2
[1,2,1], [1,1,2]
Output: false
class Solution {
public:
bool isSameTree(TreeNode *p, TreeNode *q) {
if (p == NULL || q == NULL) return (p == q);
return (p->val == q->val && isSameTree(p->left, q->left) && isSameTree(p->right, q->right));
}
};
每个二叉树分为左子树与右子树,天然的递归···
我一直被树的空节点有点搞晕了。其实对于node,只用判断他是不是为空,不为空就可以访问node->left, 与node->right。但如果要访问node->left->val, 或者node->right->val的话,就要判断对应的node->left与node->right是否为空。