将大量的文件平均分配到子文件夹下的python代码

应用举例：有10000个表格文件（都用规则的名称命名，但是有的编号可能有遗漏），平均分配给n个人
如下的代码可以自动生成子文件夹（sub1，sub2，。。。，subn）

#!/usr/bin/env python
# -*- coding: utf-8 -*-

 
"""
    This script splits multiple files into segregated folders averagely.
    Usage: python seperate.py source destination groupNumber folderFormat
    Example: python seperate.py /source /destination 3 sub, which groups files in /source into /destination/sub001/, /destination/sub002/ and /destination/sub003/
    Notice subdirectories should be avoided in /source/
"""

import sys
import os
import math

def normalisePath(path):
    '''
    Add a slash at the end of path if not end with a slash 
    '''
    if path.endswith('/'):
        return path
    else:
        return (path + '/')

def copy(source, des):
    '''
    Copy file from source to destination
    '''
    if os.path.exists(source):
        os.system("cp " + source + " " + des)

path_source = normalisePath(sys.argv[1])
path_des = normalisePath(sys.argv[2])
group_number = int(sys.argv[3])
folderFormat = sys.argv[4]

files = os.listdir(path_source)
files.sort() # Sort the files by their name
N = len(files)
group_length = math.ceil(N / group_number)

group = 1
flag = 0 # create a new sub directory when flag is zero
for i in range(1, N + 1):
    path_des_subdir = normalisePath(path_des + folderFormat + str(group))
    if flag == 0:
        os.mkdir(path_des_subdir)
        flag = 1
    file_source = path_source + files[i - 1]
    file_des = path_des_subdir + files[i - 1]
    copy(file_source, file_des)

    if i % group_length == 0:
        flag = 0
        group = group + 1