【python】习题 1-5周

22秋季Python第1周作业

题目

1.Hello World

print("Hello World")

2.人生苦短，我学python

#方法一
name = input()
if len(name)==2:
    print("{}同学,人生苦短,我学python".format(name))
    print("{}大侠,学好python,走遍天下也不怕".format(name[0]))
    print("{}小盆友,学好python,你最帅".format(name[1]))
elif len(name)==3:
    print("{}同学,人生苦短,我学python".format(name))
    print("{}大侠,学好python,走遍天下也不怕".format(name[0]))
    print("{}小盆友,学好python,你最帅".format(name[1:3]))

#方法二
name = input()
print("{}同学,人生苦短,我学python".format(name))
print("{}大侠,学好python,走遍天下也不怕".format(name[0]))
print("{}小盆友,学好python,你最帅".format(name[1: ]))

[1:]表示选择了name[1～n-1]的数据

3.应声虫

a=input()
print(a)

4.Py的A+B

a=input()
a=int(a)
b=input()
b=int(b)
print(a+b)

5.摄氏温度转换华氏温度

c=input()
c=float(c)
print(c*1.8+32)

6.从键盘输入三个数到a,b,c中，按公式值输出

# a,b,c=map(int,input().split())
# print(b * b - 4 * a * c)

line=input()
a,b,c=line.split()
a=int(a)
b=int(b)
c=int(c)
print(b * b - 4 * a * c)

7.求三角形面积

a,b,c=map(int,input().split())
p=(a+b+c)/2
p=float(p)
s=(p*(p-a)*(p-c)*(p-b))**0.5
s=float(s)
print("{:.3f}".format(s))

8.输出乘法式子

a,b=map(int,input().split())
print("%s*%s=%d"%(a,b,a*b))

Python3一行输入多个&输入多行数据

一、input().split()用法
input() 一行输入多个需要与split()结合使用

#注意：split（）参数为空，默认一行输入多个时用空格隔开
username, passwd = input("请输入用户名，密码：").split()
#注意:input()的返回类型是str,如果是整数需要转化为int才可正常使用
print(username,passwd)

输入样例：
lilian 123456

二、str.split()用法

#str.split(str="", num=string.count(str))
#str是分隔符（默认为所有的空字符，包括空格、换行(\n)、制表符(\t)等），num是分隔次数
txt1 = "Google#Facebook#Runoob#Taobao"
x1 = txt1.split("#", 1)
print(x1)
txt2 = "Google#Facebook#Runoob#Taobao"
x2 = txt2.split("#", 2)
print(x2)

输出结果：
[‘Google’, ‘Facebook#Runoob#Taobao’]
[‘Google’, ‘Facebook’, ‘Runoob#Taobao’]

三、map()用法
map(function, iterable, …)

function – 函数
iterable – 一个或多个序列

返回值：
Python 2.x 返回列表。
Python 3.x 返回迭代器。
所以Python 3.x要加list()函数将迭代器转化为列表。

def f(x):
    return x*x
print(list(map(f, [1, 2, 3, 4, 5, 6, 7, 8, 9])))

输出结果：
[1, 4, 9, 16, 25, 36, 49, 64, 81]

#用匿名函数
print(list(map(lambda x: x ** 2, [1, 2, 3, 4, 5])))

输出结果：
[1, 4, 9, 16, 25]

9.输出漏斗图形

print("*********")
print(" *******")
print("  *****")
print("   ***")
print("    *")
print("   ***")
print("  *****")
print(" *******")
print("*********")

10.显示两句话

#1
s="Everything depends on human effort.\nJust do it."
print(s)

#2
print("Everything depends on human effort.")
print("Just do it.")

#3
print("""Everything depends on human effort.
Just do it.""")

11.输出日期

year=input()
mouth=input()
day=input()
print("%s-%s-%s"%(year,mouth,day))

12.计算两个整数的差

a,b=map(int,input().split())
print("s=%d"%(a-b))

13.菲姐游泳 - 实验3 简单的计算及输入输出 -《Python编程基础及应用实验教程》(高等教育出版社)

#方法一
h1,m1,h2,m2=map(int,input().split())
if(m1>m2):
    h2=h2-1
    m=m2-m1+60
    h=h2-h1
else:
    m=m2-m1
    h=h2-h1
print("%s:%s"%(h,m))

#方法二
array = list(input().split())
if (array[1]>array[3]):
    array[2]=int(array[2])-1
    m  = int(array[3]) - int(array[1]) + 60
    h = int(array[2]) - int(array[0])
else:
    m = int(array[3]) - int(array[1])
    h = int(array[2]) - int(array[0])
print("%s:%s"%(h,m),end="")

14.求出5的三次方的值是多少？

a=input()
a=int(a)
print(a*a*a)

22秋季Python第2周作业

题目

1 输出乘法式子

a,b=map(int,input().split())
print("%d*%d=%d"%(a,b,a*b))

2 输出字符矩形

print("@@@@@@@@@@@@@@@@@@@@")
print("@@@@@@@@@@@@@@@@@@@@")
print("@@@@@@@@@@@@@@@@@@@@")
print("@@@@@@@@@@@@@@@@@@@@")

3 鸡兔同笼（高教社，《Python编程基础及应用》习题3-7）

# 输入变量解决问题
f = eval(input())
h = eval(input())
chicken = f / 2 - h
rabbit = 2 * h - f / 2
print("{}".format(int(rabbit)))
print("{}".format(int(chicken)))

# 使用循环解决鸡兔同笼问题
f = eval(input())
h = eval(input())
chicken = 0
while True:
    rabbit = h - chicken  # 头的总数
    if 2 * chicken + 4 * rabbit == f:  # 脚的总数
        #         print('鸡有 {} 只, 兔有 {} 只'.format(chicken, rabbit))
        print("{}".format(int(chicken)))
        print("{}".format(int(rabbit)))

        break
    chicken += 1

4 身体质量指数（高教社，《Python编程基础及应用》习题6-3）

weight,high=map(float,input().split(","))
# print("{}".format(weight))
# print("{}".format(high))
result = weight / (high * high)
if result < 18:
    print("超轻")
elif result < 25:
    print("标准")
elif result < 27:
    print("超重")
else:
    print("肥胖")

5 输入姓名，问好，字符切片

name = input()
print("你好，{}同学。".format(name))
print("{}同学，很高兴认识你。".format(name[0]))
print("{}同学，我们交个朋友吧！".format(name[1: ]))

6 半圆弧的长度

注意python里面import math用法

import math
a=input()
a=float(a)
L=a*math.pi
# L=float(L)
# round(L,2)
print("L={:.2f}".format(L))

7 通过python实现，输入1个字符串，输出5个一样的字符串。

# 法1
s = input()
print(s, end="")
print(s, end="")
print(s, end="")
print(s, end="")
print(s, end="")
# python 3.x版本输出不换行格式为：print(x, end="") 。end="" 可使输出不换行。

# 法2
s = input()
print(s * 5, end="")

8 单词首字母大写

建议使用方法2
方法一：

try-except异常处理 ：

详情可看这篇文章 python异常处理try-except语句

方法二：
for line in sys.stdin读文件，按行处理

# 方法1
while True:
    try:
        s = input()
        arr = s.split()
        for i in range(0, len(arr)):
            arr[i] = arr[i].capitalize()
        s1 = " ".join(arr)
        print(s1)
    except:
        break

# 方法2
import sys

for line in sys.stdin:
    line = line.strip()  # 删除尾部的换行符
    print(line.title())
#     title函数：python中字符串函数，返回’标题化‘的字符串，就是单词的开头为大写，其余为小写。

9 字符统计

s=input()
ans=0
for i in s: 
    if i == 'p' or i == 'P':
        ans+=1
print(ans)

10 字符空格去除

s = input()

# replace(m,n)方法：将字符串里面的m替换为n。
print(s.replace(' ', ''))

# split(s，num)方法：split（s,num）
print(''.join(s.split()))

11 计算球体积

import math
r=input()
r=float(r)
v=4/3*math.pi*r*r*r
print("v={:.3f}".format(v))

12 对角线 - 实验3 简单的计算及输入输出 -《Python编程基础及应用实验教程》(高等教育出版社)

import math
a=input()
a=float(a)
b=input()
b=float(b)
c=math.sqrt(a*a+b*b)
print("对角度长度为:{:.1f}cm.".format(c))

13 游客检票 - 实验3 简单的计算及输入输出 -《Python编程基础及应用实验教程》(高等教育出版社)

输入样例:

180
300

输出样例:

原有排队游客份数:900.0, 每分钟新到游客份数:3.0, 10口同开需128.6分钟清零待检票游客.

m=int(input())
n=int(input())

x=2*m/(1-m/n)
y=(6*n-x)/n
z=x/(10-y)

print('原有排队游客份数:%.1f, 每分钟新到游客份数:%.1f, 10口同开需%.1f分钟清零待检票游客.'%(x,y,z))

14 橡皮泥 - 实验3 简单的计算及输入输出 -《Python编程基础及应用实验教程》(高等教育出版社)

# 方法1
import math

d1 = float(input())
d2 = float(input())
r1 = d1 / 2
r2 = d2 / 2
v1 = 4 / 3 * math.pi * r1 * r1 * r1
v2 = 4 / 3 * math.pi * r2 * r2 * r2
sumV = v1 + v2
print("正方体边长为:{:.2f}.".format(pow(sumV, 1 / 3)))

# 方法2
import math

a = eval(input())
b = eval(input())
c = 4 / 3 * 3.1415
print("正方体边长为:{:.2f}.".format(pow(c * pow((a / 2), 3) + c * pow((b / 2), 3), (1 / 3))))

15 单个身份证的校验 - 实验19 身份证校验 - 《Python编程基础及应用实验教程》 - 高教社

注意：要判断一下输入的是否有17位

quanzhong = (7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2)
#           Z: [0,1,2,3,4,5,6,7,8,9,10]
#           M: [1,0,X,9,8,7,6,5,4,3,2]
jiaoyanma = ('1','0','X','9','8','7','6','5','4','3','2')
sum = 0
sfz = input()
if sfz[:17].isdigit():
    for i in range(17):
        sum += int(sfz[i]) * quanzhong[i]

    if sfz[-1]==jiaoyanma[sum % 11]:
        print("正确")
    else:
        print("错误")
else:
    print("错误")

22秋季Python第3周作业

题目

01 2018我们要赢

# 1
print("2018")
print("wo3 men2 yao4 ying2 !")
# 2
print("""2018\nwo3 men2 yao4 ying2 !""")
# 3
print("""2018
wo3 men2 yao4 ying2 !""")

02 重要的话说三遍

# 1
print("I'm gonna WIN!")
print("I'm gonna WIN!")
print("I'm gonna WIN!")
# 2
print("""I'm gonna WIN!
I'm gonna WIN!
I'm gonna WIN!""")

03 交换a和b的值

a,b=map(int,input().split())
# print("a=%d,b=%d"%(b,a))
print("a={},b={}".format(b,a))

04 求圆面积

import math
r=float(input())

print("{:.6f}".format(r*3.14*r))

05 实数x的n倍

x,n=map(float,input().split())
print("y={:.6f}".format(x*n))

06 把字符串中的大写字母改成小写字母

# while True:
#     try:
#         s=input()
#         print(s.lower())
#     except:
#         break

import sys
for line in sys.stdin:
    line=line.strip()
    print(line.lower())

07 字符串的连接

s1=input()
s2=input()
s=s1+s2
print(s)

08 查找指定字符

【Python】字符串几个常用查找方法

s=input()
str=input()
if str.rfind(s)!=-1:
#     print("index = %d"%(str.rfind(s)))
#     print("index = {}".format(str.rfind(s)))
    print("index = {}".format(str.rindex(s)))
else:
    print("Not Found")

09 输出大写英文字母

s1 = input()
s2 = ''    #除去小写字母的字符串
s3 = ''    #除去重复字母的字符串
for i in s1:
    if ord('A') <= ord(i) <= ord('Z'):
        s2 += i
mylist = list(set(s2))       #用set()函数对s2去重，存储为一个列表
                             #由于set()函数是无顺序去重，应调回原来顺序
mylist.sort(key = s2.index)  #用s2的顺序排列列表

# print(s2)

for i in mylist:              #将列表的值存为字符串
    s3 += i
if s3 != '':                 #输出
    print(s3)
else:
    print("Not Found")

10 字符转换

# 方法一
s = input()
a = "".join(list(filter(str.isdigit, s)))
print(int(a))  # 注意后面需要以int格式输出，不然就会输出000123等格式。

# 方法二
s = input()
result = list()
M = list(('0', '1', '2', '3', '4', '5', '6', '7', '8', '9'))
for i in range(0, len(s)):
    if s[i] in M:
        result.append(s[i])
ans = "".join(result)
print(int(ans))

注意后面需要以int格式输出，不然就会输出000123等格式。

11 算术入门之加减乘除

输入样例1:

6 3

输出样例1:

6 + 3 = 9
6 - 3 = 3
6 * 3 = 18
6 / 3 = 2

输入样例2:

8 6

输出样例2:

8 + 6 = 14
8 - 6 = 2
8 * 6 = 48
8 / 6 = 1.33

# 方法一
a, b = map(float, input().split())
print("{:.0f} + {:.0f} = {:.0f}".format(a, b, a + b))
print("{:.0f} - {:.0f} = {:.0f}".format(a, b, a - b))
print("{:.0f} * {:.0f} = {:.0f}".format(a, b, a * b))
if a % b == 0:
    print("{:.0f} / {:.0f} = {:.0f}".format(a, b, a / b))
else:
    print("{:.0f} / {:.0f} = {:.2f}".format(a, b, a / b))

# 方法二
a, b = map(float, input().split())
print("%d + %d = %d" % (a, b, a + b))
print("%d - %d = %d" % (a, b, a - b))
print("%d * %d = %d" % (a, b, a * b))
if a % b == 0:
    print("%d / %d = %.0f" % (a, b, a / b))
else:
    print("%d / %d = %.2f" % (a, b, a / b))

12 统计大写辅音字母

# 方法1
s = input()
ans = list(filter(lambda x: x.isupper() and x not in ('A', 'E', 'I', 'O', 'U'), s))
print(len(ans))

# 方法2
s = input()
yuanyin = ['a', 'e', 'i', 'o', 'u']
ans = 0
for i in s:
    if i.lower() not in yuanyin and ord('A') <= ord(i) <= ord('Z'):
        ans += 1
print(ans)

# 方法3
s = input()
ans = ""
string = "AEIOU"
for i in range(len(s)):
    if s[i] >= 'A' and s[i] <= 'Z' and s[i] not in string:
        ans = ans + s[i]
print("{}".format(len(ans)))

13 字符串替换

s = input()
ans = ""
for i in s:
    if ord('A') <= ord(i) <= ord('Z'):
        ans += chr( 155 - ord(i) )
    else:
        ans += i
print(ans)

14 字符串转换成十进制整数

s = input()

s1 = ''
for ch in s:
    if ch != '#':
        s1 += ch
    else:
        break

s_sixteen = ''
index = 0
s_index = -1
for ch in s1:
    if ord('0') <= ord(ch) <= ord('9') or ord('a') <= ord(ch.lower()) <= ord('f'):
        s_sixteen += ch
        if s_index == -1:
            s_index = index
    index += 1

fuhao = 1
for index in range(s_index):
    if s1[index] == '-':
        fuhao = -1
        break
        
ans = 0
if s_sixteen != '':
    ans = fuhao * int(s_sixteen, 16)
print(ans)

15 然后是几点

start_time,lost_min = map(int, input().split())

start_h = start_time // 100
start_min = start_time % 100
start_sum = start_h * 60 + start_min 

now_sum = start_sum + lost_min 

now_h = now_sum // 60
now_min = now_sum % 60

# print("%d%02d" %(now_h,now_min))
print("{:01d}{:02d}".format(now_h,now_min))

Python中的//是向下取整的意思
a//b，应该是对除以b的结果向负无穷方向取整后的数
举例：
5//2=2（2.5向负无穷方向取整为2），同时-5//2=-3（-2.5向负无穷方向取整为-3）

22秋季Python第4周作业

题目

1 回文数

a[::-1]是将数组所有元素逆置

a=input()
b=a[::-1]
if a==b:
    print('yes')
else:
    print('no')

2 判断是否构成三角形

a,b,c=map(int,input().split())
if a + b <= c or a + c <= b or c + b <= a:
    print("NO")
else:
    print("YES")
    

3 整数平方根

# 直接0.5次方
x = float(input())
ans = float(x ** 0.5)
print("{:.6f}".format(ans))

# 使用指对数袖珍计算器
import math
x = float(input())
if x == 0:
    ans = 0
else:
    ans = float(math.exp(0.5 * math.log(x)))
    if (ans + 1) ** 2 <= x:
        ans = ans + 1
print("{:.6f}".format(ans))

# 二分法
x = float(input())
low, high, ans = 0, x, -1
while low <= high:
    mid = (low + high) // 2
    if mid * mid <= x:
        ans = mid
        low = mid + 1
    else:
        high = mid - 1
print("{:.6f}".format(ans))

# 牛顿迭代法
x = float(input())
if x == 0:
    ans = 0
else:
    C, x0 = float(x), float(x)
    while True:
        xi = 0.5 * (x0 + C / x0)
        if abs(x0 - xi) < 1e-7:
            break
        x0 = xi
    ans = float(x0)
print("{:.6f}".format(ans))

4 分支嵌套

x = float(input())
yes = 1
if 0 < x < 5:
    y = x * x + 1
elif x == 0:
    y = 0
elif -5 < x < 0:
    y = -x + 4
else:
    yes = 0
    print("No meaning")
if yes == 1:
    print("x={:.2f},y={:.2f}".format(x, y))

5 不合格的小球

a, b, c, d = map(int, input().split())
list = [a, b, c, d]
number = ['A', 'B', 'C', 'D']
index = 0
for i in range(3):
    if list[i] == list[i + 1]:
        index = list[i]
for j in range(4):
    if list[j] != index:
        print("{} {}".format(number[j], list[j]))

6 简单的猜数字游戏[1]

guess = int(input())
if guess>38:
    print("Too big!")
elif guess<38:
    print("Too small!")
else:
    print("Good Guess!")
    
'''
产生随机数  random.randint(start,end)
可以猜多次，直到才对了位置
如果猜错了给出提示
猜大了还是猜小了
'''
'''
# import random
# ran = random.randint(1,50)
# count = 0
# print('猜数字游戏：')
# while True:
#     #进入猜数字环节 while循环
#     guess = int(input('请输入您要猜的数字：'))
#     count = count + 1
#     if guess == ran:
#         print('恭喜你猜对了')
#         break
#     elif guess > ran:
#          print('猜大了')
#     else :
#         print('猜小了')
# print('你一共猜了%d'% count)
'''

7 求某月的天数

while True:
    try:
        y,m=input().split()
        y=int(y)
        m=int(m)
        list=[31,28,31,30,31,30,31,31,30,31,30,31]
        if y%400==0 or y%4 == 0 and y%100!=0:
            list[1]=29
        print(list[m-1])
    except:
        break

8 统计各类字符数量并输出字母

输入样例:

ABC xyz 123 ?!

输出样例:

abcXYZ
letters:6, digits:3, spaces:3, others:2.

s = input()
num, char, space, other = 0, 0, 0, 0      #分别统计数字、字母、空格、其他字符个数
s1=""
for i in s:
    #是否为数字
    if i.isdigit():
        num += 1
    #是否为字母
    elif i.isalpha():
        char += 1
        if "a"<= i <= "z":
            s1+=(i.upper())
        elif"A" <= i <= "Z" :
            s1+=(i.lower())
    elif i == ' ':
        space += 1
    else:
        other += 1
print(s1)
print("letters:{}, digits:{}, spaces:{}, others:{}.".format(char, num, space, other))

9 计算邮资

m, s = map(str, input().split())
m = int(m)
price = 0
# 如果字符是y，说明选择加急；如果字符是n，说明不加急。
if s == "n":
    if m <= 1000:
        price = 8
    if (m > 1000) and ((m % 500) > 0):
        a = ((m - 1000) // 500) + 1
        a = a * 4
        price = 8 + a
    if (m > 1000) and ((m % 500) == 0):
        a = (m - 1000) // 500
        a = a * 4
        price = 8 + a
        
if s == "y":
    if m <= 1000:
        price = 13
    if (m > 1000) and ((m % 500) > 0):
        a = ((m - 1000) // 500) + 1
        a = a * 4
        price = 8 + a + 5
    if (m > 1000) and ((m % 500) == 0):
        a = (m - 1000) // 500
        a = a * 4
        price = 8 + a + 5
print(price)

10 币值转换

# 方法一
a = input()
a = int(a)
s = []
n = ""
p = w = 1
zero = False
if len(str(a)) <= 9 and a >= 0:
    count = len(str(a))
    counts = len(str(a))
    while a % 10 == 0 and a > 0:
        a = a // 10
    s = str(a)
    for num, i in enumerate(s):
        if num < len(s) - 1:
            w = list(s)[num]
            p = list(s)[num + 1]
        if int(w) == 0 and int(p) == 0 and not count == 5:
            n += ""
            zero = True
        elif int(w) == 0 and not int(p) == 0 and zero == False and num < len(s) - 1:
            n += "a"
        elif count == 5 and int(i) == 0:
            n += "W"
        elif count == 9 and zero == False:
            n += chr(ord(i) + 49) + "Y"
        elif count == 5 and zero == False:
            n += chr(ord(i) + 49) + "W"
        elif (count == 4 or count == 8) and zero == False:
            n += chr(ord(i) + 49) + "Q"
        elif (count == 3 or count == 7) and zero == False:
            n += chr(ord(i) + 49) + "B"
        elif (count == 2 or count == 6) and zero == False:
            n += chr(ord(i) + 49) + "S"
        elif zero:
            n += "a"
            w = p = 1
            zero = False
        else:
            n += chr(ord(i) + 49)
        count -= 1
    if counts > 8 and int(list(s)[3]) == 0 and int(list(s)[2]) == 0 and int(list(s)[1]) == 0:
        n = n.replace("W", "")

print(n)

'''
# 方法2
def fun(a):  # a是一个由整数组成的数组
    num = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']
    flag = 1  # 高位没有零
    if len(a) == 4:
        if a[0] == '0':
            if a[1] == '0' and a[2] == '0' and a[3] == '0':
                return ''
            else:
                qianwei = 'a'
                flag = 0  # 高位已经有零
        else:
            qianwei = num[int(a[0])] + 'Q'
            if a[1] == '0' and a[2] == '0' and a[3] == '0':
                return qianwei

        if a[1] == '0':
            if flag == 0:
                baiwei = ''
            else:
                baiwei = 'a'
                flag = 0
        else:
            baiwei = num[int(a[1])] + 'B'
            flag = 1

        if a[2] == '0' and a[3] == '0':
            return qianwei + baiwei

        if a[2] == '0':
            if flag == 0:
                shiwei = ''
            else:
                shiwei = 'a'
                flag = 0
        else:
            shiwei = num[int(a[2])] + 'S'
            flag = 1
        if a[2] == '0' and a[3] == '0':
            return qianwei + baiwei + shiwei
        if a[3] == '0':
            gewei = ''
        else:
            gewei = num[int(a[3])]
            flag = 1
        return qianwei + baiwei + shiwei + gewei
    elif len(a) == 3:
        baiwei = num[int(a[0])] + 'B'
        if a[1] == '0' and a[2] == '0':
            return baiwei
        elif a[1] == '0' and a[2] != '0':
            return baiwei + 'a' + num[int(a[2])]
        elif a[1] != '0' and a[2] == '0':
            return baiwei + num[int(a[1])] + 'S'
        else:
            return baiwei + num[int(a[1])] + 'S' + num[int(a[2])]
    elif len(a) == 2:
        shiwei = num[int(a[0])] + 'S'
        if a[1] == '0':
            return shiwei
        else:
            return shiwei + num[int(a[1])]

    else:
        return num[int(a[0])]


n = input()
if len(n) <= 4:
    print(fun(n))
# elif len(n) > 4 and len(n) <= 8:
elif 4 < len(n) <= 8:
    n1 = n[len(n) - 4:]
    n2 = n[:len(n) - 4]
    print(fun(n2) + 'W' + fun(n1))
else:
    n1 = n[len(n) - 4:]
    n2 = n[len(n) - 8:len(n) - 4]
    n3 = n[:len(n) - 8]
    print(fun(n3) + 'Y' + fun(n2) + 'W' + fun(n1))
'''

11 分段函数3

x = int(input())
y = 0
if x >= 0:
    y = x + 3
else:
    y = x / 2
print("y={:.6f}".format(y))

12 从5个整数中找出最小的数。

import sys

for line in sys.stdin:
    a = line.split()
    a = [int(line) for line in a]
    print(min(a))

13 考试分数对应等级

a = int(input())
if 0 <= a < 60:
    print("-1")
elif 60 <= a < 90:
    print("0")
else:
    print("1")

14 日历

请编写程序，输入年份和月份，输出日历。

输入格式

第一行为整数n
后面有n行数据，每行包含两个整数y和m
其中：y为年份(1000≤y≤9999)，m为月份(1≤m≤12)

输出格式

这些月的日历(参考输出样例)

输入样例1

1
2017 6

输出样例1
(参见下图)

输入样例2

2
2020 5
2020 12

输出样例2
(参见下图)

要求：每行末尾不得有多余的空格，日历末尾不得有多余的空行。

提示：公元1年1月1日为星期一。

import calendar
# print(calendar.weekday(1, 1, 1))
# print(calendar.weekday(2017,6,1))
calendar.setfirstweekday(calendar.SUNDAY)
num = int(input())
for i in range(num):
    year, month = [int(x) for x in input().split()]
    # print(year, month)
    print(' ' * 5, end='')
    print("%4d年" % year, end='')
    print("%2d月"%month)
    print()
    print("日 一 二 三 四 五 六")

    rili = calendar.month(year, month, w=2, l=1)
    # print(rili)
    rili_lst = rili.split('\n')
    # print(rili_lst)
    for i in range(2, len(rili_lst)):
        if len(rili_lst[i]) > 0:
            print(rili_lst[i])

22秋季Python第5周作业

7-1 我是升旗手

python数组使用

n = input()
arr = input()
num = [int(n) for n in arr.split()]
# print(num)
print(max(num))

7-2 369寝室

a, b, c = map(int, input().split())
flag = 0
for i in range(1, 101):
    # print(i)
    A = a + i
    B = b + i
    C = c + i
    A %= 10
    B %= 10
    C %= 10
    if A == 0 or B == 0 or C == 0:
        continue
    if A % 3 == 0 and B % 3 == 0 and C % 3 == 0:

        if A != B and B != C and C != A:
            flag = i
            break

if flag==0:
    print("so sad!")
else:
    print(flag)

7-3 求e的值

n = float(input())
i = 1
e = 0.0
jc = 1.0
while jc > n:
    e = e + jc
    j = 1
    for k in range(1, i + 1):
        j = j * k
    jc = 1.0 / j
    i += 1
print("e={:.6f}".format(e))

7-4 斐波那契数

用常规做法，最后一个测试点会超时。
更高效的做法是：找出输出结果的规律，根据输入的n的值直接构造输出结果。列举如下：
n=7，结果是: no no yes no no no yes
n=11,结果是: no no yes no no no yes no no no yes
n=15,结果是: no no yes no no no yes no no no yes no no no yes
n=19的话，结果是多少？

# 6分答案
num = int(input())
flag = 0
for i in range(num):
    if i < 2:
        print("no ", end="")
    elif i >= 2:
        if i % 4 == 2:
            print("yes ", end="")
        else:
            print("no ", end="")

# 6分答案  ------时间超时
num = int(input())
for i in range(num):
    if i == 2 or (i - 2) % 4 == 0:
        print('yes', end=' ')
    else:
        print('no', end=' ')

用了for循环 时间复杂度O(n)还是会时间超时

#满分答案
Fibonacci = "yes no no no "
num = int(input())
if num == 1:
    print("no ", end="")
if num <= 2:
    print("no no ", end="")
elif num > 2:
    a = (num - 2)
    print("no no ", end="")
    x = a // 4
    if a % 4 == 0:
        print(Fibonacci*x)
    if a % 4 == 1:
        if x == 0:
            print(Fibonacci[0:4])
        else:
            print(Fibonacci*x+Fibonacci[0:4])
    if a % 4 == 2:
        if x == 0:
            print(Fibonacci[0:7])
        else:
            print(Fibonacci * x+Fibonacci[0:7])
    if a % 4 == 3:
        if x == 0:
            print(Fibonacci[0:10])
        else:
            print(Fibonacci * x+Fibonacci[0:10])

# num = int(input())
# if num == 1:
#     print("no ", end="")
# if num <= 2:
#     print("no no ", end="")
# elif num > 2:
#     a = (num - 2)
#     print("no no ", end="")
#     x = a // 4
#     if a % 4 == 0:
#         print("yes no no no " * x, end="")
#     if a % 4 == 1:
#         if x == 0:
#             print("yes ", end="")
#         else:
#             print("yes no no no " * x, end="")
#             print("yes ", end="")
#     if a % 4 == 2:
#         if x == 0:
#             print("yes no ", end="")
#         else:
#             print("yes no no no " * x, end="")
#             print("yes no ", end="")
#     if a % 4 == 3:
#         if x == 0:
#             print("yes no no ", end="")
#         else:
#             print("yes no no no " * x, end="")
#             print("yes no no ", end="")

# 方法2
n=input()
n=int(n)
a='no no yes no no no yes no '
b=[1,2,0,2,2,1,0,1]
x=n//8
def f(m):
    for i in range(m):
        if (b[i % 8]) == 0:
            print("yes ", end="")
        else:
            print("no ", end="")
if x<0:
    f(x)
else:
    print(a*x,end='')
    f(n%8)

7-5 求简单交错序列前N项和

n = int(input())
ans = 0
flag = 1
num = 1
for i in range(1, n + 1):
    ans += flag * 1.0 / num
    num += 3
    flag = -flag
print("sum = {:.3f}".format(ans))

7-6 求整数序列中出现次数最多的数

a = input().split() #在一行中输入多个数
i = int(a[0]) + 1   #确定第一个数字大小即是列表应有的长度
del a[i:]			#删除多余输入的数字
del a[0]			#删除第一个数字
                    #现在a中存储的即为要求序列

num = 0
MaxCount = 0
for i in a:         #从第一个数字开始遍历（第一个循环）
    count = 0
    for j in a:		#从第一个数字开始遍历（第二个循环）
        if j == i:  #如果两个数字相等，那么这个数字的数量加一
            count += 1
    if MaxCount < count:	#判断数量最多的数字并存储
        MaxCount = count
        num = i
print("{} {}".format(num,MaxCount))
# print(num, end = ' ')
# print(MaxCount)

7-7 求符合给定条件的整数集

a = int(input())
n = 0
b = a + 4
for i in range(a, b):
    for j in range(a, b):
        if i == j:
            continue
        for k in range(a, b):
            if k == i or k == j:
                continue
            n += 1
            # 换行
            if n < 6:
                print(i * 100 + j * 10 + k, end=" ")
            else:
                n = 0
                print(i * 100 + j * 10 + k)

也可以使用暴力解法 一共6种情况，直接输出

a = int(input())
if a==1:
    print("""123 124 132 134 142 143
213 214 231 234 241 243
312 314 321 324 341 342
412 413 421 423 431 432""")
elif a==2:
    print("""234 235 243 245 253 254
324 325 342 345 352 354
423 425 432 435 452 453
523 524 532 534 542 543""")
elif a==3:
    print("""345 346 354 356 364 365
435 436 453 456 463 465
534 536 543 546 563 564
634 635 643 645 653 654""")
elif a==4:
    print("""456 457 465 467 475 476
546 547 564 567 574 576
645 647 654 657 674 675
745 746 754 756 764 765""")
elif a==5:
    print("""567 568 576 578 586 587
657 658 675 678 685 687
756 758 765 768 785 786
856 857 865 867 875 876
""")
elif a==6:
    print("""678 679 687 689 697 698
768 769 786 789 796 798
867 869 876 879 896 897
967 968 976 978 986 987""")

7-8 画菱形

n = int(input())
for i in range(1, n + 1):
    for j in range(1, n - i + 1):
        print(" ", end="")
    for j in range(1, 2 * i - 1 + 1):
        print("*", end="")
    print("\n", end="")

for i in range(1, n - 1 + 1):
    for j in range(1, i + 1):
        print(" ", end="")
    for j in range(1, 2 * n - 1 - 2 * i + 1):
        print("*", end="")
    print("\n", end="")

7-9 求集合数据的均方差

import math

n = int(input())
arr = input()
num = [int(n) for n in arr.split()]
sum = 0
avg = 0.0
x = 0.0
# for i in num:
#     print(i)
for i in range(0, len(num)):
    # print(num[i])
    sum += num[i]
avg = sum * 1.0 / n
for i in range(0, len(num)):
    x += (num[i] - avg) * (num[i] - avg)
result = math.sqrt(x / n)
print("{:.5f}".format(result))

7-10 组合数的和

不知道为什么 但是是错误的

# 0
a = [int(i) for i in input().split()]
n = a[0]
result = 0
for i in range(1, n + 1):
    for j in range(1, n + 1):
        if j==i:
            continue
        else:
            result += a[i] * 10 +a[j]
print(result)

# 0
a = input().split()
sum = 0
sum2 = 0
for i in range(1, len(a)):
    sum += int(a[i])
for i in range(1, len(a)):
    sum2 += int(a[i]) * 10 * (len(a) - 2) + sum - int(a[i])
print(sum2)

终于答对了

# 10
import sys
num = list(map(int, sys.stdin.read().split()))
print(sum(num[1:] * (num[0] - 1) * 11))

第10题，输入有两行。输入样例改为：
3
2 5 8

# 10
n = int(input())
a = [int(i) for i in input().split()]
result = 0
for i in range(0, n ):
    for j in range(0, n ):
        if j==i:
            continue
        else:
            result += a[i] * 10 +a[j]
print(result)

7-11 输出素数之和

# 方法1
def isprime(n):
    if n <= 1:
        return False
    for i in range(2, n):
        if n % i == 0:
            return False
    return True


def f(n):
    count = 0
    s = 0
    while count < 10 and n > 1:
        if isprime(n):
            count += 1
            print(n, end=" ")
            s += n
        n -= 1
    print()
    return s


num = int(input())
print("sum = {}".format(f(num)))


# 方法2
import heapq

n = int(input())
sums = 0
nums = []
for i in range(2, n):
    for j in range(2, i):
        if i % j == 0:
            break
    else:
        sums += i
        nums.append(int(i))
maxnums = heapq.nlargest(10, nums)
total = sum(maxnums)
for i in maxnums:
    print(i, end=' ')
print()
print("sum = {:.0f}".format(total))

7-12 暴力小学(二年级篇)-求出2个三位数

count = 0
t = 0
n = int(input())
aa = {}
bb = {}
for a1 in range(1, 7):
    for a2 in range(1, 7):
        for a3 in range(1, 7):
            for b1 in range(1, 7):
                for b2 in range(1, 7):
                    for b3 in range(1, 7):
                        if ((a1 * 100 + a2 * 10 + a3 - b1 * 100 - b2 * 10 - b3 == n)
                                and a1 != a2 and a1 != a3 and a1 != b1 and a1 != b2
                                and a1 != b3 and a2 != a3 and a2 != b1 and a2 != b2
                                and a2 != b3 and a3 != b1 and a3 != b2 and a3 != b3
                                and b1 != b2 and b1 != b3 and b2 != b3):
                            aa[count] = a1 * 100 + a2 * 10 + a3
                            bb[count] = b1 * 100 + b2 * 10 + b3
                            count += 1
print(count)
for i in range(0, count):
    print("{}-{}".format(aa[i], bb[i]))

7-13 高空坠球

# 9
dis = []  # 距离
height = []  # 高度

h, time = map(int, input().split())

for i in range(1, time + 1):
    if i == 1:
        dis.append(h)
    else:
        dis.append(2 * h)
    h /= 2
    height.append(h)
print("{:.1f} {:.1f}".format(sum(dis), height[-1]))

这里9分是因为：非零返回了

# 10
height, n = map(int, input().split())
sum = 0
h = 0
for i in range(0, n + 1):
    if i == 0:
        sum = 0
        h = 0
    if i == 1:
        sum = height
        h = height / 2.0
    if i > 1:
        sum = sum + h * 2
        h = h / 2
print("{:.1f} {:.1f}".format(sum, h))

7-14 二分法求多项式单根

# 方法1
import math
a = list(float(x) for x in input().split())
b = list(float(x) for x in input().split())
while True:
    if b[1] - b[0] <= 0.01:
        break
    f1 = a[0] * pow(b[0], 3) + a[1] * pow(b[0], 2) + a[2] * b[0] + a[3]
    f2 = a[0] * pow(b[1], 3) + a[1] * pow(b[1], 2) + a[2] * b[1] + a[3]
    if f1 == 0:
        b[1] = b[0]
        break
    if f2 == 0:
        b[0] = b[1]
        break
    if f1 * f2 < 0:
        ans = (b[0] + b[1]) / 2
        f3 = a[0] * pow(ans, 3) + a[1] * pow(ans, 2) + a[2] * ans + a[3]
        if f3 == 0:
            break
        elif (f3 < 0 and f1 < 0) or (f3 > 0 and f1 > 0):
            b[0] = ans
        elif (f3 < 0 and f2 < 0) or (f3 > 0 and f2 > 0):
            b[1] = ans
ans = (b[0] + b[1]) / 2
print("%.2f" % ans)



# 方法2
a3, a2, a1, a0 = map(float, input().split())
a, b = map(float, input().split())


def f(x):
    res = a3 * x ** 3 + a2 * x ** 2 + a1 * x + a0
    return res


# 区间端点是根
if f(a) == 0:
    ans = a
elif f(b) == 0:
    ans = b
else:  # 判断f(a)f(b)的符号
    while b - a >= 0.01:
        if f((a + b) / 2) == 0:
            ans = (a + b) / 2
            break
        elif f((a + b) / 2) * f(a) > 0:
            a = (a + b) / 2
        else:
            b = (a + b) / 2
    else:
        ans = (a + b) / 2
print("%.2f" % ans)

7-15 天梯赛座位分配

N = int(input())  # 参赛的高校数 N （不超过100的正整数）
a = [int(i) for i in input().split()]  # 第二行给出 N 个不超过10的正整数，其中第 i 个数对应第 i 所高校的参赛队伍数
b = sorted(a)  # 将队伍数量由小到大排列
for i in range(N):
    if N == 1:
        print('#1')
        start = 1
        for i in range(a[0]):
            print(*range(start, start + 19, 2))
            start += 20
        break
    d_id = i + 1
    x = N
    num = 0
    finishSchoolNum = 0
    d1 = a[:i]
    d2 = a[i + 1:]
    jud = 0

    print('#{}'.format(d_id))
    for j in range(1, a[i] + 1):
        if j > b[finishSchoolNum]:
            if b[finishSchoolNum] in d1:
                d_id -= d1.count(b[finishSchoolNum])
            x -= b.count(b[finishSchoolNum])
            finishSchoolNum += b.count(b[finishSchoolNum])
        if x == 1:
            x = 2
            if b[-2] not in d2:
                jud = 1
        print(*range(num + d_id + jud, num + d_id + jud + x * 9 + 1, x))
        num += x * 10

7-16 统计一批学生的平均成绩与不及格人数

grade = list(map(int, input().split(" ")))
people = 0
sum = 0
n = 0
for i in grade:
    if i < 0:
        break
    n += 1
    sum += i
    if i < 60:
        people += 1
if n > 0:
    average = "%.2f" % (sum / n)
    print('Average =', average)
    print('Count =', people)
else:
    print("Average = 0.00")