(CTC解码)Modeified prefix-search decoding algorithm

最近写CTC,然后需要一个解码部分,看见这篇文章,网上pytorch版的CTC解码部分基本上都是基于这个版本,但是对于代码并不是很容易理解,研究了一下,顺便记录下来。


Algorithm.png

下面的代码基本上就是上面算法的复现,代码中增加了逐行的解释,代码中实际上没有语言模型部分。如果需要,可以比着葫芦画瓢,自己增加上。

"""
Author: Awni Hannun
This is an example CTC decoder written in Python. The code is
intended to be a simple example and is not designed to be
especially efficient.
The algorithm is a prefix beam search for a model trained
with the CTC loss function.
For more details checkout either of these references:
  https://distill.pub/2017/ctc/#inference
  https://arxiv.org/abs/1408.2873
"""

import numpy as np
import math
import collections

NEG_INF = -float("inf")

# 创建一个新的beam
def make_new_beam():
    fn = lambda : (NEG_INF, NEG_INF)
    return collections.defaultdict(fn)

# 因为代码中为了避免数据下溢,都采用的是对数概率,所以看起来比较繁琐
def logsumexp(*args):
    """
    Stable log sum exp.
    """
    if all(a == NEG_INF for a in args):
        return NEG_INF
    a_max = max(args)
    lsp = math.log(sum(math.exp(a - a_max)
                       for a in args))
    return a_max + lsp

def decode(probs, beam_size=10, blank=0):
    """
    Performs inference for the given output probabilities.
    Arguments:
      probs: The output probabilities (e.g. post-softmax) for each
        time step. Should be an array of shape (time x output dim).
      beam_size (int): Size of the beam to use during inference.
      blank (int): Index of the CTC blank label.
    Returns the output label sequence and the corresponding negative
    log-likelihood estimated by the decoder.
    """
    # T表示时间,S表示词表大小
    T, S = probs.shape
    # 求概率的对数
    probs = np.log(probs)

    # Elements in the beam are (prefix, (p_blank, p_no_blank))
    # Initialize the beam with the empty sequence, a probability of
    # 1 for ending in blank and zero for ending in non-blank
    # (in log space).
    # 每次总是保留beam_size条路径
    
    beam = [(tuple(), (0.0, NEG_INF))]

    for t in range(T): # Loop over time

        # A default dictionary to store the next step candidates.
        next_beam = make_new_beam()

        for s in range(S): # Loop over vocab
            p = probs[t, s]

            # The variables p_b and p_nb are respectively the
            # probabilities for the prefix given that it ends in a
            # blank and does not end in a blank at this time step.
            for prefix, (p_b, p_nb) in beam: # Loop over beam
                # p_b表示前缀最后一个是blank的概率,p_nb是非blank的概率
                # If we propose a blank the prefix doesn't change.
                # Only the probability of ending in blank gets updated.
                if s == blank:
                  # 增加的字母是blank
                  # n_p_b和n_p_nb第一n表示new是新创建的路径
                  n_p_b, n_p_nb = next_beam[prefix]
                  n_p_b = logsumexp(n_p_b, p_b + p, p_nb + p)
                  next_beam[prefix] = (n_p_b, n_p_nb)
                  continue

                # Extend the prefix by the new character s and add it to
                # the beam. Only the probability of not ending in blank
                # gets updated.
                end_t = prefix[-1] if prefix else None
                n_prefix = prefix + (s,)
                n_p_b, n_p_nb = next_beam[n_prefix]
                if s != end_t:
                  # 如果s不和上一个不重复,则更新非空格的概率
                  n_p_nb = logsumexp(n_p_nb, p_b + p, p_nb + p)
                else:
                  # 如果s和上一个重复,也要更新非空格的概率
                  # We don't include the previous probability of not ending
                  # in blank (p_nb) if s is repeated at the end. The CTC
                  # algorithm merges characters not separated by a blank.
                  n_p_nb = logsumexp(n_p_nb, p_b + p)

                # *NB* this would be a good place to include an LM score.
                next_beam[n_prefix] = (n_p_b, n_p_nb)

                # If s is repeated at the end we also update the unchanged
                # prefix. This is the merging case.
                if s == end_t:
                  n_p_b, n_p_nb = next_beam[prefix]
                  n_p_nb = logsumexp(n_p_nb, p_nb + p)
                  next_beam[prefix] = (n_p_b, n_p_nb)

        # Sort and trim the beam before moving on to the
        # next time-step.
        # 根据概率进行排序,每次保留概率最高的beam_size条路径
        beam = sorted(next_beam.items(),
                key=lambda x : logsumexp(*x[1]),
                reverse=True)
        beam = beam[:beam_size]

    best = beam[0]
    return best[0], -logsumexp(*best[1])

if __name__ == "__main__":
    np.random.seed(3)

    time = 50
    output_dim = 20

    probs = np.random.rand(time, output_dim)
    probs = probs / np.sum(probs, axis=1, keepdims=True)

    labels, score = decode(probs)
    print(labels)
    print("Score {:.3f}".format(score))

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