UVa 10066: The Twin Towers

最长公共子序列(LCS)问题,dp解决。

要注意每次输出结果后要空行!!!题目的例子上居然没空,害我WA了两次才找到原因 =--=

解题代码如下:

 

#include <iostream>

#include <cstdio>

#include <cstring>

#include <cstdlib>

#include <algorithm>



using namespace std;

#define max(a,b) ((a)>(b)?(a):(b))

#define maxn 105

int Tower1[maxn], Tower2[maxn];

int N1, N2;

int LongLen[maxn][maxn];

int dp(int i, int j)

{

	if(!i || !j) return 0;

	if(LongLen[i][j]>=0) return LongLen[i][j];

	if(Tower1[i]==Tower2[j]) return LongLen[i][j] = dp(i-1,j-1)+1;

	else return LongLen[i][j] = max( dp(i-1,j), dp(i,j-1));

}

int main()

{

	int Case = 0;

	while(cin >> N1 >> N2 && N1 && N2)

	{

		for(int i=1; i<=N1; i++) cin >> Tower1[i];

		for(int i=1; i<=N2; i++) cin >> Tower2[i];

		memset(LongLen,-1,sizeof(LongLen));

		printf("Twin Towers #%d\nNumber of Tiles : %d\n\n", ++Case, dp(N1,N2));

	}

	return 0;

}


 

 

你可能感兴趣的:(uva)