Question:
Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
For example, given array S = {-1 0 1 2 -1 -4}, A solution set is: (-1, 0, 1) (-1, -1, 2)
Solution:
1 class Solution { 2 public: 3 vector<vector<int>> threeSum(vector<int>& nums) { 4 vector< vector<int> > result; 5 if(nums.size()<3) 6 return result; 7 sort(nums.begin(),nums.end()); 8 const int target=0; 9 auto last=nums.end(); 10 for(auto i=nums.begin();i<last-2;i++) 11 { 12 auto j=i+1; 13 if(i>nums.begin() && *i==*(i-1)) continue; 14 auto k=last-1; 15 while(j<k) 16 { 17 if(*i+*j+*k<target) 18 {j++;while(*j==*(j-1) && j<k) ++j;} 19 else if(*i+*j+*k>target) 20 {k--;while(*k==*(k+1) && j<k) --k;} 21 else 22 { 23 vector<int> x; 24 x.push_back(*i); 25 x.push_back(*j); 26 x.push_back(*k); 27 result.push_back(x); 28 ++j; 29 --k; 30 while(*j==*(j-1) && *k==*(k+1) && j<k) ++j; 31 } 32 } 33 } 34 return result; 35 } 36 };