1. 在Eclipse中建立Maven工程
1.1 新建Maven工程
1.2 选择默认工作空间
1.3 选择 maven-archetype-webapp Archetype
1.4 填写Group id,Artifact id,package
1.5 生成的web工程初始目录结构
2. 添加工程依赖
2.1 用Maven POM Editor 打开pom.xml文件,在Dependencies中添加依赖包
2.2 在查询栏中输入“resteasy-jaxrs”,在查询结果中选择版本3.0.0
2.3 保存pom.xml后,manvn从中央代码仓库自动下载依赖包
3. REST Service
package com.example.rest.resteasy.service;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.core.Response;
@Path("/hello")
public class HelloWorldRestService {
@GET
@Path("/{param}")
public Response getName(@PathParam("param") String name) {
String result = "RESTEasy Hello World : " + name;
return Response.status(200).entity(result).build();
}
}
4. Rest Application
package com.example.rest.resteasy.app;
import java.util.HashSet;
import java.util.Set;
import javax.ws.rs.core.Application;
import com.example.rest.resteasy.service.HelloWorldRestService;
public class HelloWorldApplication extends Application {
private Set<Object> singletons = new HashSet<Object>();
public HelloWorldApplication() {
singletons.add(new HelloWorldRestService());
}
@Override
public Set<Object> getSingletons() {
return singletons;
}
}
5. web.xml
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>resteasy-servlet</servlet-name>
<servlet-class>
org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher
</servlet-class>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>com.example.rest.resteasy.app.HelloWorldApplication</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>resteasy-servlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
6. Run AS -> run jetty
在这个例子中,web请求“http://localhost:8080/resteasy-example/hello”将匹配HelloWorldRestService,“http://localhost:8080/resteasy-example/hello/{任意值}”将匹配到方法参数@PathParam 参数