java的简单测试类

java中的输入总是伴随着异常（这是我的个人见解），所以，用下面这个简单类，就简化了每次都要抛异常的问题。

<DIV class=cnblogs_Highlighter><PRE class=brush:java>import java.io.*;
public class Console {
/**Reads a single double from the keyboard. Stops execution in case of error.
@return double*/
public static double readDouble()  {
try  {
return Double.valueOf(readString().trim()).doubleValue();
}catch(NumberFormatException ne)
{
System.err.println("Console.readDouble:Not a double...");
System.exit(-1);
return 0.0;
}
}
/**Reads a single int from the keyboard. Stops execution in case of error.
@return int */
public static int readInt()  {
try  {
return Integer.valueOf(readString().trim()).intValue();
}catch(NumberFormatException ne)
{
System.err.println("Console.readInt:Not aninteger...");
System.exit(-1);
return -1;
}
}
/**Reads a String from the keyboard until RERUEN or ENTER key is pressed.
@return String */
public static String readString()  {
String string =new String();
BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
try  {
string=in.readLine();
}catch(IOException e)
{
System.out.println("Console.readString:Unknown error...");
System.exit(-1);
}
return string;
} }
</PRE>
</DIV>

测试代码：

<DIV class=cnblogs_Highlighter><PRE class=brush:java>
/**test the Console.java @author icecold */
public class ConsoleTest {
public static void main(String[] args)
{
System.out.print("Enter integer: ");
int i=Console.readInt();
System.out.print("Enter double: ");
double d=Console.readDouble();
System.out.println("Integer enered: "+i);
System.out.println("Double entered: "+d);
double x=i+d;
System.out.println(x);
} }
</PRE>
</DIV>