SQL练习

time2=DateDiff( "n",date1,date2)    
    '--Divided into the Hour or Minute or second    
    strmm2=""    
    '-Day    
    nd2=Int(ntime2/(24*60))    '天    
    If nd2>0 Then    
            strmm2=strmm2+cstr(nD2)+ "天/"    
    End If    
    nH2=Int((ntime2-nd2*24*60)/60)    '小时    
    If nH2>0 Then    
            strmm2=strmm2+Cstr(nH2)+ "小时/"    
    End If    
    nM2=ntime2-nd2*24*60-nH2*60        '分钟    
    If nM2>0 Then    
            strmm2=strmm2+Cstr(nM2)+ "分钟/"    
    End If    
    nS2=(ntime2-nd2*24*60-nH2*60-nM2)/60    '秒    
    If ns2>0 Then    
            strmm2=strmm2+Cstr(nS2)+ "秒"    
    End If    

    最后的结果是strmm2    

用一条SQL语句,将以上综合起来

SQL语句：

select
case when datediff(minute, '2008/11/11 13:23', '2008/11/11 19:23') < 24*60 then '' else
         convert( varchar, datediff(minute, '2008/11/11 13:23', '2008/11/11 19:23')/(24*60)) + ' 天' end +
case when datediff(minute, '2008/11/11 13:23', '2008/11/11 19:23') < 60 then '' else
         convert( varchar, datediff(minute, '2008/11/11 13:23', '2008/11/11 19:23')%(24*60)/60) + ' 小时 ' end +
convert( varchar, datediff(minute, '2008/11/11 13:23', '2008/11/11 19:23')%60) + ' 分钟'