【分享】今日某公司的电话面试题

【分享】今日某公司的电话面试题

写一个函数，输出前N个数（从7开始），这N个数满足如下3个条件中的任意一个
1.整出7
2.各位上的数字之和整除7，(比如34)
3.任意位上包含数字7


附我的代码：

void  printN( int  n)
{

    
     int  c = 0 ;
     int  i = 7 ;
     do  
    {
         if (i % 7   == 0 )
        {
            printf( " %d\n " ,i);
            c ++ ;
        }
         else
        {
             int  j = i % 10 ;
             int  k = j;
             int  s = k;
             int  p = 10 ;
             while (k<i)
            {

                 if (j == 7 )
                {
                    printf( " %d\n " ,i);
                    s = 0 ;
                    c ++ ;
                     break ;

                }
                 else
                {
                    j = ((i - k) / p) % 10 ;
                    s += j;
                    k = j * p + k;
                    p *= 10 ;


                }
            }
             if (s && s % 7 == 0 )
            {


                printf( " %d\n " ,i);
                c ++ ;
            }
            

        }
        i ++ ;
    }  while  (c < n);
}