每天一道算法_4_Hangover

此系列刚开始两天就被十一假期打断了，去山西玩了几天，今天刚回来，为了弥补一下心里的貌似隐隐作痛的愧疚感，挑了个简单的练练手，权当给自己补上一刀。

今天的题目是 Hangover，如下：

 

Description

How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 +... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below.

Input

The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.

Output

For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples.

Sample Input

1.00
3.71
0.04
5.19
0.00

Sample Output

3 card(s)
61 card(s)
1 card(s)
273 card(s)

 

代码如下：

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;


public class Hangover {
	
	public static void main(String args[]){
		List<Float> list = new ArrayList<Float>();
		Scanner scanner = new Scanner(System.in);
		int all = scanner.nextInt();
		while(all > 0){
			list.add(scanner.nextFloat());
			all --;
		}
		for(int i = 0; i < list.size(); i ++){
			float f = list.get(i);
			int count = 1;
			float j=2,sum=0;
			for(; sum + (1/j) < f; j ++){
				count ++;
				sum = sum+ (1/j);
			}
			System.out.println(count + " card(s)");
		}
	}
}

 

输入输出如下：

4 1.00 3.71 0.04 5.19
3 card(s)
61 card(s)
1 card(s)
273 card(s)

由于输入的时候弄了半天没想出合适的用0.00结尾的方法，就用了开头先输入一个整数，表示后面要输入的整数个数，然后依次输入的方法，

相信你能看懂。

 

作者：jason0539

微博：http://weibo.com/2553717707

博客：http://blog.csdn.net/jason0539（转载请说明出处）