HDU 3278 Puzzle

题意：水平移动一行或者一列字母。使中间的8个字母相同要多少步？

思路：把每一种字母分别考虑，到到每一种状态步数的最小值就是答案；

好开心，刷到榜首了。。第一次榜首有名啊！！！

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <queue>

using namespace std;
int que[1<<24];
short visit[1<<24];
int tmp[5],c;
int inline col1(int k,int s)
{
    c = -1;
    for(int i=0; i<4; i++)
    {
        c -= (1<<(i*6+k));
        tmp[i]=s&(1<<(i*6+k));
    }
    s=s&c;
    tmp[0]<<=18;
    tmp[1]>>=6;
    tmp[2]>>=6;
    tmp[3]>>=6;
    s=s+tmp[0]+tmp[1]+tmp[2]+tmp[3];
    return s;
}
int inline col2(int k,int s)
{
    c = -1;
    for(int i=0; i<4; i++)
    {
        c -= (1<<(i*6+k));
        tmp[i]=s&(1<<(i*6+k));
    }
    s=s&c;
    tmp[0]<<=6;
    tmp[1]<<=6;
    tmp[2]<<=6;
    tmp[3]>>=18;
    s=s+tmp[0]+tmp[1]+tmp[2]+tmp[3];
    return s;
}
int inline row1(int k,int s)
{
    c = 63<<(k*6);
    int tmp = c&s;
    s -= tmp;
    int t = tmp&(1<<(k*6));
    tmp -= t;
    tmp>>=1;
    tmp +=(t<<5);
    return s+tmp;
}
int inline row2(int k,int s)
{
    c = 63<<(k*6);
    int tmp = c&s;
    s -= tmp;
    int t = tmp&(1<<(k*6+5));
    tmp -= t;
    tmp<<=1;
    tmp +=(t>>5);
    return s+tmp;
}
void init()
{
    int rear=0,fron=0;
    que[rear++]=124800;
    visit[124800] = 1;
    while(rear>fron)
    {
        int e = que[fron++],t;
        for(int i=0; i<6; i++)
        {
            t = col1(i,e);
            if(!visit[t])
            {
                visit[t] = visit[e]+1;
                que[rear++] = t;
            }
            t = col2(i,e);
            if(!visit[t])
            {
                visit[t] = visit[e]+1;
                que[rear++] = t;
            }
        }
        for(int i=0; i<4; i++)
        {
            t = row1(i,e);
            if(!visit[t])
            {
                visit[t] = visit[e]+1;
                que[rear++] = t;
            }
            t = row2(i,e);
            if(!visit[t])
            {
                visit[t] = visit[e]+1;
                que[rear++] = t;
            }
        }
    }
}
int main()
{
    freopen("in.txt","r",stdin);
    int cas,T = 1;
    scanf("%d",&cas);
    init();
    while(cas--)
    {
        int b=0,g=0,w=0;
        char a[20];
        for(int i=0; i<4; i++)
        {
            scanf("%s",a);
            for(int j=0; j<6; j++)
                if(a[j]=='W')
                    w+=(1<<(i*6+j));
                else if(a[j]=='G')
                    g+=(1<<(i*6+j));
                else
                    b+=(1<<(i*6+j));
        }
        printf("Case %d: %d\n",T++,min(visit[b],min(visit[g],visit[w]))-1);
    }
    return 0;
}