preg_match_all 获取图片地址的方法

 $sqlpic="SELECT * FROM news_base as a, news_content as b  where a.news_id=b.id and a.cid=12 order by b.id DESC limit 6";
 $querypic=$db->query($sqlpic);
 while($rowpic_news=$db->fetch_array($querypic)){
  //获取图片地址delete(s,i,n);
      $str=$rowpic_news[8];
      preg_match_all("/\<img.*?src\=\"(.*?)\"[^>]*>/i", $str, $match);
      
      //print_r($match);
        /////////////////////////////////////
  $pic_news[]=array("title"=>$rowpic_news[1],"id"=>$rowpic_news[0],"picurl"=>$match[1][0]);
 }