HDU 2114 Calculate S(n) (立方和的计算)

Calculate S(n)

Time Limit: 10000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1897    Accepted Submission(s): 713

Problem Description

Calculate S(n).

S(n)=1 ³ +2 ³ +3 ³ +......+n ³ .

 

 

Input

Each line will contain one integer N(1 < n < 1000000000). Process to end of file.

 

 

Output

For each case, output the last four dights of S(N) in one line.

 

 

Sample Input

1

2

 

 

Sample Output

0001

0009

解题：

       运用数学公式：1³ +2³ +3³ +……+n³ =[n(n+1)/2]²

#include <iostream> #include <iomanip> using namespace std; int main() { __int64 sum,n; while (cin>>n) { sum=0; n%=10000; sum=(n*(n+1)/2)*(n*(n+1)/2)%10000; cout<<setfill('0')<<setw(4)<<sum<<endl; } return 0; }