hdu 4006 求第K大的数

The kth great number

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65768/65768 K (Java/Others)
Total Submission(s): 3775 Accepted Submission(s): 1583

Problem Description

Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round Xiao Ming can choose to write down a number, or ask Xiao Bao what the kth great number is. Because the number written by Xiao Ming is too much, Xiao Bao is feeling giddy. Now, try to help Xiao Bao.

Input

There are several test cases. For each test case, the first line of input contains two positive integer n, k. Then n lines follow. If Xiao Ming choose to write down a number, there will be an " I" followed by a number that Xiao Ming will write down. If Xiao Ming choose to ask Xiao Bao, there will be a "Q", then you need to output the kth great number.

Output

The output consists of one integer representing the largest number of islands that all lie on one line.

Sample Input

   
   
   
   

    
    
    
    8 3 I 1 I 2 I 3 Q I 5 Q I 4 Q
   
   
   
   

Sample Output

 

  
  
  
  

   
   
   
   1 2 3 
   
   
   
   
 
    Hint 
   
   
   
   
   
 
    Xiao Ming won't ask Xiao Bao the kth great number when the number of the written number is smaller than k. (1=<k<=n<=1000000). 题意： I m添加数 m Q 询问第 k大的数 思路 ：set 控制集合的大小为k 或者用优先队列  
   
   
   
   
   
 
    代码： 
   
   
   
   
   
 
    
#include<stdio.h>
#include<iostream>
#include<set>
using namespace std;
int main()
{
	int n,i,j,m,k;
	while(scanf("%d %d",&n,&k)!=EOF)
	{
		 multiset<int>s;
		 multiset<int>::iterator it;
		 for(i=0;i<n;i++)
		 {
			 char a[2];
			 scanf("%s",a);
			 if(a[0]=='I')
			 {
				 scanf("%d",&m);
				 s.insert(m);
				 if(s.size()>k)
					 s.erase(s.begin());
			 }
			 else
			 {
				 printf("%d\n",*s.begin());
			 }
		 }
	}
	return 0;
}
 
    
 
   
   
   
   
   
 
    优先队列 做法 
   
   
   
   
   
 
    代码： 
   
   
   
   
   
 
    
#include<iostream>
#include<cstdio>
#include<queue>
#include<vector>
using namespace std;
struct cmp
{
   bool operator()(int a,int b)
   {
      return a>b;
   }
};
priority_queue<int,vector<int>,cmp> q;
int main()
{
   int n,k,p;
   char s[3];
   while(scanf("%d%d",&n,&k)!=EOF)
   {
     while(!q.empty())q.pop();
      while(n--)
      {
         scanf("%s",s);
         if(s[0]=='I')
         {
            scanf("%d",&p);
            q.push(p);
            if(q.size()>k)q.pop();
         }
         else
         {
            printf("%d\n",q.top());
         }
      }
   }
   return 0;
}