hdu 2057

C中存在十六进制的输入输出（%X，%x）。

这里用__int64的类型。输入输入出格式就是（%I64x,%I64X）。由于%I64X，不能输出

负数，所以负数的输出要做处理。

HDU 2057 A + B Again（十六进制的数相加） 
  
  
  
  

  
  
  
  

   
   
   
   
A+B Again(HDU2057)
   
   
   
   
经典例子 2009-10-07 11:18:55 阅读234 评论2  字号：大中小 订阅
   
   
   
   
 
    
Problem Description
 
    
 
     There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it ! 
    
 
    
Input
 
    
 
     The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15. 
    
 
    
Output
 
    
 
     For each test case,print the sum of A and B in hexadecimal in one line. 
    
 
    
Sample Input
 
    
 
     
+A -A
+1A 12
1A -9
-1A -12
1A -AA
 
    
 
    
Sample Output
 
    
 
     
0
2C
11
-2C
-90
 
     
//////////////////////////////////////////////////////////////
 
    
 
   
  
  
  
  

#include<stdio.h>
int main()
{
 __int64 a,b;
 for (;scanf("%I64x%I64x",&a,&b)!=EOF;)
 {
     printf(a+b<0?"-%I64X\n":"%I64X\n",a+b<0?-a-b:a+b);
 }
 return 0;
}