UVa 10205 Stack 'em Up (模拟)
10205 - Stack 'em Up
Time limit: 3.000 seconds
http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=1146
A standard playing card deck contains 52 cards, 13 values in each of four suits. The values are named 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King, Ace. The suits are named Clubs, Diamonds, Hearts, Spades. A particular card in the deck can be uniquely identified by its value and suit, typically denoted <value> of <suit>. For example, "9 of Hearts" or "King of Spades". Traditionally a new deck is ordered first alphabetically by suit, then by value in the order given above.
The Big City has many Casinos. In one such casino the dealer is a bit crooked. She has perfected several shuffles; each shuffle rearranges the cards in exactly the same way whenever it is used. A very simple example is the "bottom card" shuffle which removes the bottom card and places it at the top. By using various combinations of these known shuffles, the crooked dealer can arrange to stack the cards in just about any particular order.
You have been retained by the security manager to track this dealer. You are given a list of all the shuffles performed by the dealer, along with visual cues that allow you to determine which shuffle she uses at any particular time. Your job is to predict the order of the cards after a sequence of shuffles.
Input
The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.Input consists of an integer n <= 100, the number of shuffles that the dealer knows. 52n integers follow. Each consecutive 52 integers will comprise all the integers from 1 to 52 in some order. Within each set of 52 integers, i in position j means that the shuffle moves the ith card in the deck to position j.
Several lines follow; each containing an integer k between 1 and n indicating that you have observed the dealer applying the kth shuffle given in the input.
Output
For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.Assume the dealer starts with a new deck ordered as described above. After all the shuffles had been performed, give the names of the cards in the deck, in the new order.
Sample Input
1 2 2 1 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 52 51 52 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 1 1 2
Output for Sample Input
King of Spades 2 of Clubs 4 of Clubs 5 of Clubs 6 of Clubs 7 of Clubs 8 of Clubs 9 of Clubs 10 of Clubs Jack of Clubs Queen of Clubs King of Clubs Ace of Clubs 2 of Diamonds 3 of Diamonds 4 of Diamonds 5 of Diamonds 6 of Diamonds 7 of Diamonds 8 of Diamonds 9 of Diamonds 10 of Diamonds Jack of Diamonds Queen of Diamonds King of Diamonds Ace of Diamonds 2 of Hearts 3 of Hearts 4 of Hearts 5 of Hearts 6 of Hearts 7 of Hearts 8 of Hearts 9 of Hearts 10 of Hearts Jack of Hearts Queen of Hearts King of Hearts Ace of Hearts 2 of Spades 3 of Spades 4 of Spades 5 of Spades 6 of Spades 7 of Spades 8 of Spades 9 of Spades 10 of Spades Jack of Spades Queen of Spades Ace of Spades 3 of Clubs
直接模拟。
完整代码：
/*0.012s*/
#include<bits/stdc++.h>
using namespace std;
const char* suit[4] = {"Clubs", "Diamonds", "Hearts", "Spades"};
const char* value[4] = {"Jack", "Queen", "King", "Ace"};
char s[5];
int code[105][53], deck[53], tmp_deck[53];
int main()
{
int T, n, x, i, j;
scanf("%d", &T);
while (T--)
{
scanf("%d", &n);
for (i = 1; i <= n; ++i)
for (j = 1; j <= 52; ++j)
scanf("%d", &code[i][j]);
getchar();
for (i = 1; i <= 52; ++i) deck[i] = i;
while (gets(s) && s[0])
{
sscanf(s, "%d", &x);
for (i = 1; i <= 52; ++i)
tmp_deck[i] = deck[code[x][i]];
memcpy(deck, tmp_deck, sizeof(deck));
}
for (i = 1; i <= 52; ++i)
{
x = (deck[i] - 1) % 13;
if (x < 9) printf("%d", x + 2);
else printf("%s", value[x % 9]);
printf(" of ");
puts(suit[(deck[i] - 1) / 13]);
}
if (T) putchar(10);
}
return 0;
}