函数指针

 http://blog.chinaunix.net/u2/82249/showart_1958364.html

1  定义一个函数指针

且不论语法，有两种不同形式的指针函数: 一个是指向普通的C函数的指针和C++的静态成员函数，另外一个是指向C++的非静态成员函数的指针。这两者的基本区别是所有指向非静态成员函数的指针都 需要这个隐含定义：指向本类的一个This指针。注意：这两种函数指针彼此不兼容。

既然一个函数指针实际上和一个变量没有什么区别，定义它的时候也就没有什么特殊。下面的例子中我们定义3个函数指针，名字是pt2Function , pt2Member 和 pt2ConstMember . 它们指向的函数，输入一个 float 和两个char 类型的变量并返回一个 int 类型的变量. 对于C++程序例子，我们的指针指向的的函数，是一个叫做 TMyClass 的类的非静态成员函数。



// 1 define a function pointer and initialize to NULL
int (*pt2Function)(float , char , char ) = NULL; // C
int (TMyClass::*pt2Member)(float , char , char ) = NULL; // C++
int (TMyClass::*pt2ConstMember)(float , char , char ) const = NULL; // C++


2 函数调用规范

通常你不需要考虑一个函数的调用规范：编译器缺省的使用__cdecl， 如果你不特别指出用哪个的话。调用规范告诉编译器如何传递参数以及如何产生函数名。一些其他的调用规范可以举例为：__stdcall , __pascal 和__fastcall . 注意：使用不同调用规范的函数指针彼此不兼容。


// 2 define the calling convention
void __cdecl DoIt(float a, char b, char c); // Borland and Microsoft
void DoIt(float a, char b, char c) __attribute__((cdecl )); // GNU GCC


3 为函数指针分派一个地址

将函数的地址分派给函数指针很容易，在函数名字之前冠以取址符&就可以了。


// 3 assign an address to the function pointer
// Note: Although you may ommit the address operator on most compilers
// you should always use the correct way in order to write portable code.

// C
int DoIt (float a, char b, char c){ printf("DoIt/n" ); return a+b+c; }
int DoMore(float a, char b, char c)const { printf("DoMore/n" ); return a-b+c; }

pt2Function = DoIt; // short form
pt2Function = &DoMore; // correct assignment using address operator


// C++
class TMyClass
{
public :
int DoIt(float a, char b, char c){ cout << "TMyClass::DoIt" << endl; return a+b+c;};
int DoMore(float a, char b, char c) const
{ cout << "TMyClass::DoMore" << endl; return a-b+c; };

/* more of TMyClass */
};

pt2ConstMember = &TMyClass::DoMore; // correct assignment using address operator
pt2Member = &TMyClass::DoIt; // note: <pt2Member> may also legally point to &DoMore


4 比较函数指针

你可以和通常方式一样使用比较符号(==, !=)。下面的例子中我们检查变量 pt2Function 和 pt2Member ，它们分别指向的函数 DoIt 和 TMyClass::DoMore . 如果指向正确就会输出代表争取的字符串。


// 4 comparing function pointers

// C
if (pt2Function >0 ){ // check if initialized
if (pt2Function == &DoIt)
printf("Pointer points to DoIt/n" ); }
else
printf("Pointer not initialized!!/n" );


// C++
if (pt2ConstMember == &TMyClass::DoMore)
cout << "Pointer points to TMyClass::DoMore" << endl;


5  使用函数指针调用函数

在C语言中我们可以通过 * 符号来调用函数指针，也可以不使用函数名而代以函数指针的名字。C++使用两个符号 * 和 ->* 来调用类的非静态函数指针。如果呼叫在其他成员函数中发生，那么就得加上this指针。


// 5 calling a function using a function pointer
int result1 = pt2Function (12 , 'a' , 'b' ); // C short way
int result2 = (*pt2Function) (12 , 'a' , 'b' ); // C

TMyClass instance1;
int result3 = (instance1.*pt2Member)(12 , 'a' , 'b' ); // C++
int result4 = (*this .*pt2Member)(12 , 'a' , 'b' ); // C++ if this-pointer can be used

TMyClass* instance2 = new TMyClass;
int result4 = (instance2->*pt2Member)(12 , 'a' , 'b' ); // C++, instance2 is a pointer
delete instance2;


6  如何像传递一个参数一样传递函数指针

你可以在调用一个函数的时候把函数指针当作参数来传递。在回调函数中尤其要使用到这个技术。下边这个例子演示了如何把指针传递给一个函数，这个函数使用一个 float 和两个 char 类型的参数并有一个int类型的返回值。


//------------------------------------------------------------------------------------
// 6 How to Pass a Function Pointer

// <pt2Func> is a pointer to a function which returns an int and takes a float and two char
void PassPtr(int (*pt2Func)(float , char , char ))
{
int result = (*pt2Func)(12 , 'a' , 'b' ); // call using function pointer
cout << result << endl;
}

// execute example code - 'DoIt' is a suitable function like defined above in 2.1-4
void Pass_A_Function_Pointer()
{
cout << endl << "Executing 'Pass_A_Function_Pointer'" << endl;
PassPtr(&DoIt);
}


7  如何返回一个函数指针

看上去有点怪，但是一个函数指针可以作为一个函数的返回值。下面的例子中提供了两种把函数指针作为返回值的解决方案。这个函数输入两个float 类型的参数，返回一个float 类型的值。


//------------------------------------------------------------------------------------
// 7 How to Return a Function Pointer
// 'Plus' and 'Minus' are defined above. They return a float and take two float


// Direct solution: Function takes a char and returns a pointer to a
// function which is taking two floats and returns a float. <opCode>
// specifies which function to return
float (*GetPtr1(const char opCode))(float , float )
{
if (opCode == '+' )
return &Plus;
else
return &Minus; // default if invalid operator was passed
}


// Solution using a typedef: Define a pointer to a function which is taking
// two floats and returns a float
typedef float (*pt2Func)(float , float );

// Function takes a char and returns a function pointer which is defined
// with the typedef above. <opCode> specifies which function to return
pt2Func GetPtr2(const char opCode)
{
if (opCode == '+' )
return &Plus;
else
return &Minus; // default if invalid operator was passed
}


// Execute example code
void Return_A_Function_Pointer()
{
cout << endl << "Executing 'Return_A_Function_Pointer'" << endl;

// define a function pointer and initialize it to NULL
float (*pt2Function)(float , float ) = NULL;

pt2Function=GetPtr1('+' ); // get function pointer from function 'GetPtr1'
cout << (*pt2Function)(2 , 4 ) << endl; // call function using the pointer


pt2Function=GetPtr2('-' ); // get function pointer from function 'GetPtr2'
cout << (*pt2Function)(2 , 4 ) << endl; // call function using the pointer
}


8  如何使用函数指针数组

使用函数指针数组非常有意思，这个技术提供了一种从索引中选择函数的方法。实现的语法看上去很复杂，经常导致理解错误。下面的例子中我们可以看到两种定义和使用函数指针数组的方法。前一种使用 typedef ，后一种直接定义数组。使用哪一种全凭你的兴趣。

//------------------------------------------------------------------------------------
// 8 How to Use Arrays of Function Pointers

// C ---------------------------------------------------------------------------------

// type-definition: 'pt2Function' now can be used as type
typedef int (*pt2Function)(float , char , char );

// illustrate how to work with an array of function pointers
void Array_Of_Function_Pointers()
{
printf("/nExecuting 'Array_Of_Function_Pointers'/n" );

// define arrays and ini each element to NULL, <funcArr1> and <funcArr2> are arrays
// with 10 pointers to functions which return an int and take a float and two char

// first way using the typedef
pt2Function funcArr1[10 ] = {NULL};

// 2nd way directly defining the array
int (*funcArr2[10 ])(float , char , char ) = {NULL};


// assign the function's address - 'DoIt' and 'DoMore' are suitable functions
// like defined above in 1-4
funcArr1[0 ] = funcArr2[1 ] = &DoIt;
funcArr1[1 ] = funcArr2[0 ] = &DoMore;

/* more assignments */

// calling a function using an index to address the function pointer
printf("%d/n" , funcArr1[1 ](12 , 'a' , 'b' )); // short form
printf("%d/n" , (*funcArr1[0 ])(12 , 'a' , 'b' )); // "correct" way of calling
printf("%d/n" , (*funcArr2[1 ])(56 , 'a' , 'b' ));
printf("%d/n" , (*funcArr2[0 ])(34 , 'a' , 'b' ));
}


// C++ -------------------------------------------------------------------------------

// type-definition: 'pt2Member' now can be used as type
typedef int (TMyClass::*pt2Member)(float , char , char );

// illustrate how to work with an array of member function pointers
void Array_Of_Member_Function_Pointers()
{
cout << endl << "Executing 'Array_Of_Member_Function_Pointers'" << endl;

// define arrays and ini each element to NULL, <funcArr1> and <funcArr2> are
// arrays with 10 pointers to member functions which return an int and take
// a float and two char

// first way using the typedef
pt2Member funcArr1[10 ] = {NULL};

// 2nd way of directly defining the array
int (TMyClass::*funcArr2[10 ])(float , char , char ) = {NULL};


// assign the function's address - 'DoIt' and 'DoMore' are suitable member
// functions of class TMyClass like defined above in 2.1-4
funcArr1[0 ] = funcArr2nd use an array of function pointers in C and C++. The first way uses a typedef, the second way directly defines the array. It's up to you which way you prefer.

[ 1 ] = &TMyClass::DoIt;
funcArr1[ 1 ] = funcArr2[ 0 ] = &TMyClass::DoMore;
/* more assignments */

// calling a function using an index to address the member function pointer
// note: an instance of TMyClass is needed to call the member functions
TMyClass instance;
cout << (instance.*funcArr1[ 1 ])( 12 , 'a' , 'b' ) << endl;
cout << (instance.*funcArr1[ 0 ])( 12 , 'a' , 'b' ) << endl;
cout << (instance.*funcArr2[ 1 ])( 34 , 'a' , 'b' ) << endl;
cout << (instance.*funcArr2[ 0 ])( 89 , 'a' , 'b' ) << endl;
}