DML(Data Manipulation Language)语句 on Oracle

DML语句(select + inser update delete)

--insert

insert into tablename values(col1value,col2value···); --可以插入特定字段 insert into dept2 (deptno,dname) values(60,'game2') --可以插入整张表 insert into dept1 (select * from dept2)

--update

update tablename set col1name=value1,col2name=value2··· where···

--delete

delete from tablename delete from tablename where···

--select

select * from tablename; select col1name,col2name from tablename; select col1name,col2name*12 from tablename; select col1name,col2name*12 "another name" from tablename;--anothername里有特殊字符，用双引号括起来,双引号可以保持别名的格式 desc dual; --空表，用来算数学表达式 select sysdate from dual; select colmame1||colname2 --|| 字符串连接符 --''单引号括起来的是字符串，若字符串内有单引号则用两个单引号代替一个单引号 --去除重复项，distinct修饰多个列时保证查询结果对这几个列的组合是不重复的 select distinct colname from tablename; --value 为字符串时加'' --比较运算符：<,>,不等于<>,between···and···,<=,>=; --逻辑运算符：and,or，not --其他判断 ：is null,is not null,in(value1,value2,value3)等于其中之一，not in() --比较日期时日期字符串要按标准格式写 select * from tablename where colname = value; --模糊查询 like 通配符 %零个或多个 _代表一个字母 \转义字符 ···like '%$%%' escape '$' --自己指定转义字符为$ ···order by colname1 desc,colname2 asc;--desc降序的 默认升序asc;先按colmname1降序，相同的再用colmname2升序排

常用sql函数：

单行函数

lower(colname) upper(cloname) substr(colname,NUM1,NUM2) --从第NUM1位开始取 NUM2位 chr(ASCII) ascii('CHARACTER') ROUND(DECIMALS)-- ROUND(小数,四舍五入到第几位) to_char(colname,'$99,999.9999') --9代表一位数字，但是这位上没有数字时不显示；0也代表一位数字，该位没数字时用0补； L代表本地货币 to_char(colname,'YYYY-MM-DD HH:MI:SS') to_char(colname,'YYYY-MM-DD HH24:MI:SS') to_date('1988-10-24 12:34:56','YYYY-MM-DD HH24:MI:SS') to_number('$1,250.00',"$9,999.99") nvl(colname,0) --若conname为null，则变为0

组函数：

--多行函数!!!!!!!!!!!!!!!!!!!!!!!! max(colname) min(colname) avg(colname) sum(colname) count(*)--一共多少条记录 count(colname)--只计算不是空值的 count(distinct colname)--只计算不重复的 group by colname group by colname1,colname2-- 按这俩的组合分组!!!!!!! 出现在select 列表中的字段如果不是出现在组函数里，那么必须存在于group by子句里!!!!!!! having where对行操作，having对组操作，分组后再having select···from···where···group by··having··order by··· --where后为筛选元组的条件，group by为分组条件，having后为筛选分组的条件，order by为排序条件

子查询

select ename,sal from emp where sal =(select max(sal) from emp);

--自连接（把一张表当两张表用）

select e1.ename,e2.ename from emp e1,emp e2 where e1.mgr = e2.empno;--92版 select e1.ename,e2.ename from emp e1 join emp e2 on (e1.mgr = e2.empno);--99版

--交叉连接

select ename,dname from emp,dept;--92版 select ename,dname from emp cross join dept;--99版

--等值连接

select ename,dname from emp,dept where emp.deptno = dept.deptno;--92版 select ename,dname from emp join dept on (emp.deptno = dept.deptno);--99版 select ename,dname from emp join dept using (deptno);--不推荐用

--非等值连接

select ename,sal,grade--99版 from emp e join salgrade s on (e.sal between s.losal and s.hisal); select ename,dname,grade from emp e join dept d on (e.deptno=d.deptno) join salgrade s on (e.sal between s.losal and s.hisal) where ename not like '_A%';

--外连接
--左外连接：

select e1.ename,e2.ename from emp e1 left join emp e2 on (e1.mgr=e2.empno);

--右外连接：

select ename,dname from emp e right join dept d on (e.deptno=d.deptno);

--全外连接

select ename,dname from emp e full join dept d on (e.deptno=d.deptno);

--基于Oracle示例表的子查询练习
--求部门中那些人薪水最高

select ename,sal,emp.deptno from emp join (select max(sal) max_sal,deptno from emp group by deptno) t on (t.max_sal = emp.sal and emp.deptno = t.deptno);

--部门平均薪水的等级

select deptno,avg_sal,grade from salgrade join (select avg(sal) avg_sal,deptno from emp group by deptno) t on (t.avg_sal>salgrade.losal and t.avg_sal<salgrade.hisal);

--部门平均的薪水等级

select deptno,avg(grade) from emp e join salgrade s on (e.sal between s.losal and s.hisal) group by deptno; select deptno,avg(grade)from ( select deptno,ename,sal,grade from emp e join salgrade s on (e.sal between s.losal and s.hisal) )group by deptno;

--雇员中有哪些人是经理人

select distinct e2.ename from emp e1 join emp e2 on (e1.mgr=e2.empno);

--求普通员工时要注意了，not in不行，子查询里有空值，空值代表任意值

select ename from emp where empno in (select distinct mgr from emp); select ename from emp where empno not in (select distinct mgr from emp where mgr is not null)

--不准用组函数，求薪水的最高值

select distinct e1sal from( select distinct e1.sal e1sal,e2.sal e2sal from emp e1 left join emp e2 on (e1.sal<e2.sal) )where e2sal is null; select distinct e1.sal from emp e1 left join emp e2 on (e1.sal<e2.sal) where e2.sal is null; select distinct sal from emp where sal not in ( select distinct e1.sal e1sal from emp e1 join emp e2 on (e1.sal<e2.sal) );

--求平均薪水最高的部门的部门编号

select deptno,avgsal from (select deptno,avg(sal) avgsal from emp group by deptno) where avgsal= (select max(avgsal) from (select deptno,avg(sal) avgsal from emp group by deptno) );

--组函数嵌套，最多两层

select deptno,avgsal from (select deptno,avg(sal) avgsal from emp group by deptno) where avgsal= (select max(avg(sal)) from emp group by deptno);

--求平均薪水最高的部门的部门名称

select dname from dept where deptno = ( select deptno from (select deptno,avg(sal) avgsal from emp group by deptno) where avgsal= (select max(avgsal) from (select deptno,avg(sal) avgsal from emp group by deptno) ) )

--求平均薪水的等级最低的部门的部门名称

select dname from dept where deptno =( select deptno from ( select deptno,grade from (select deptno,avg(sal) avg_sal from emp group by deptno) t join salgrade s on (t.avg_sal between s.losal and hisal) )where grade =( select min(grade) from( select deptno,grade from (select deptno,avg(sal) avg_sal from emp group by deptno) t join salgrade s on (t.avg_sal between s.losal and hisal) ) ) ) select d.deptno,dname,avg_sal,grade from ( select deptno,avg_sal,grade from (select deptno,avg(sal) avg_sal from emp group by deptno) t join salgrade s on (t.avg_sal between s.losal and hisal) ) t join dept d on (t.deptno=d.deptno) where grade =( select min(grade) from( select deptno,grade from (select deptno,avg(sal) avg_sal from emp group by deptno) t join salgrade s on (t.avg_sal between s.losal and hisal) ) ) select dname from( select t.deptno,dname,grade from (select deptno,avg(sal) avg_sal from emp group by deptno) t join salgrade s on (t.avg_sal between s.losal and s.hisal) join dept d on (t.deptno=d.deptno) )where grade=( select min(grade) from( select t.deptno,dname,grade from (select deptno,avg(sal) avg_sal from emp group by deptno) t join salgrade s on (t.avg_sal between s.losal and s.hisal) join dept d on (t.deptno=d.deptno) ) )

--创建视图

grant create table,create view to scott; create view V$_dept_sal_info as( select t.deptno,dname,grade from( (select deptno,avg(sal) avg_sal from emp group by deptno) t join salgrade s on (t.avg_sal between s.losal and s.hisal) join dept d on (t.deptno=d.deptno) ) ) select dname from V$_dept_sal_info where grade=(select min(grade) from V$_dept_sal_info2)

--求部门经理人中平均薪水最低的部门名称(思考题)

select dname from dept where deptno=( select deptno from ( select deptno,avg(sal) avg_sal from ( select empno,ename,deptno,sal from emp where empno in (select e2.empno from emp e1 join emp e2 on e1.mgr=e2.empno) )group by deptno )where avg_sal=( select min(avg(sal)) from ( select empno,ename,deptno,sal from emp where empno in (select e2.empno from emp e1 join emp e2 on e1.mgr=e2.empno) )group by deptno ) )

--求比普通员工的最高薪水还要高的经理人名称

select ename from emp where empno in(select distinct mgr from emp where mgr is not null) and sal > ( select max(sal) from emp where empno not in (select distinct mgr from emp where mgr is not null) )

--求薪水最高的前五名雇员
--结果集中存在伪字段rownum，行号，只能和< <=一块用

select ename from (select ename,sal from emp order by sal desc） where rownum < 6

--求薪水最高的第六到第十名雇员

select ename,sal,r from ( select ename,sal,rownum r from (select ename,sal from emp order by sal desc) ) where r>=6 and r<=10

--练习：求最后入职的五名员工

select ename,to_char(hiredate,'YYYY_MM_DD HH24:MI:SS') from (select ename,hiredate from emp order by hiredate desc) where rownum<=5

--<的话直接用就行了
--面试题：比较效率

select * from emp where deptno = 10 and ename like '%A%'; select * from emp where ename like '%A%' and deptno = 10;

--有3个表S,C,SC S(SNO,SNAME) C(CNO,CNAME,CTEACHER) SC(SNO,CNO,SCGRADE)
--找出没选过“黎明”老师的所有学生姓名

select disctinct s.sno,s.sname from s join sc on (s.sno=sc.sno) join c on(c.cno=sc.cno) where cteacher<>'黎明'

--列出两门以上（含两门）不及格学生姓名及平均成绩

select sname,avg_g from s join( select sno,avg(scgrade) avg_g from sc where scgrade<60 group by sno having count(cno)>=2 ) t on (s.sno=t.sno)

--既学过1号课程又学过2号课程的所有学生的姓名

select sname from s where sno in ( select sno from sc where cno=2 and sno in (select distinct sno from sc where cno=1) )