Python 获取当前目录下所有文件夹的大小

Python 获取当前目录下所有文件夹的大小。方便一目了然的去删除大文件目录

python 2.7下实现

#!/usr/bin/python
#-*- coding:gbk -*-
import urllib2
import urllib
import os
import shutil
homedir = os.getcwd()
from os.path import join, getsize

'''
获取当前文件夹，和文件夹大小
放在要统计的文件夹下
'''
FOLDER_LIST=[]

def getdirsize(dir):  
   size = 0L  
   for root, dirs, files in os.walk(dir):  
      size += sum([getsize(join(root, name)) for name in files])  
   return size

def getFileSize(size):
   if size/1024>1:
      if size/(1024*1024)>1:
         return '%0.2fMB' %float(size/(1024*1024))
      else:
         return '%0.2fKB' %float(size/1024)
   else:
      return '%0.2fKB' %float(size/1024)

def sort(A,num):
    for i in range(len(A)):
        (A[i][0],A[i][num])=(A[i][num],A[i][0])
    A.sort(reverse=True)
    for i in range(len(A)):
        (A[i][0],A[i][num])=(A[i][num],A[i][0])

for i in os.listdir('.'):
    if os.path.isdir(i):
       fileSize = getdirsize(unicode(homedir+'\\'+i,'gbk'))
       FOLDER_LIST.append([homedir+'\\'+i,fileSize])
       
       print homedir+'\\'+i+'\t文件大小:%s' %(getFileSize(float(fileSize)))

sort(FOLDER_LIST,1)
print '*********************排序后*********************'
for arr in FOLDER_LIST:
   print arr[0]+'\t文件大小:%s' %(getFileSize(float(arr[1])))
   print '---------------------------------------------------------'

os.system('pause')