UVa 11292&HDU1902 The Dragon of Loowater （贪心）

The Dragon of Loowater

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1113    Accepted Submission(s): 490

Problem Description

Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. 
The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance. 

One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom. 

The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height." 

Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp! 

 

Input

The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres. 
The last test case is followed by a line containing: 
0 0

 

Output

For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line: 
Loowater is doomed!

 

Sample Input

   
   
   
   

    
    
    
    2 3
5
4
7
8
4
2 1
5
5
10
0 0
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    11
Loowater is doomed!
   
   
   
   

 

Author

Ond鴈j Lhot醟

 

Source

2008-1杭电公开赛(非原创)

原题链接：http://acm.hdu.edu.cn/showproblem.php?pid=1902

题意：你的王国有一条n个头的龙，你希望雇佣骑士来把它们杀死（即砍下所有头）。村里有m个骑士课雇佣，一个能力值为 x 的骑士可以砍掉恶龙一个直径不超过 x 的头，且需支付 x 个金币。如何雇佣骑士才能砍掉恶龙的所有头。且支付的金币最少？注意，一个骑士只能砍一个头，且不能雇佣两次。

思路：两骑士的能力，和龙头按从小到大排序，，一次进行就可以了。。

AC代码：

#include<cstdio>
#include<algorithm>
using namespace std;

const int maxn = 20000 + 5;
int A[maxn],B[maxn];
int main()
{
    int n,m;
    while(scanf("%d%d",&n,&m)!=EOF&&n&&m)
    {
        for(int i=0; i<n; i++)
            scanf("%d",&A[i]);
        for(int i=0; i<m; i++)
            scanf("%d",&B[i]);
        sort(A,A+n);
        sort(B,B+m);

        int cur = 0;
        int cost = 0;
        for(int i=0; i<m; i++)
        {
            if(B[i]>=A[cur])
            {
                cost+=B[i];
                if(++cur == n)
                    break;
            }
        }
        if(cur<n){
            printf("Loowater is doomed!\n");
        }
        else{
            printf("%d\n",cost);
        }
    }
    return 0;
}