HDU-4464-Browsing History （2012 ACM/ICPC成都现场赛！）

Browsing History

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3065    Accepted Submission(s): 1692

Problem Description

One day when you are going to clear all your browsing history, you come up with an idea: You want to figure out what your most valued site is. Every site is given a value which equals to the sum of ASCII values of all characters in the URL. For example aa.cc has value of 438 because 438 = 97 + 97 + 46 + 99 + 99. You just need to print the largest value amongst all values of sites.
Things are simplified because you found that all entries in your browsing history are of the following format: [domain], where [domain] consists of lower-case Latin letters and “.” only. See the sample input for more details.

 

Input

There are several test cases.
For each test case, the first line contains an integer n (1 ≤ n ≤ 100), the number of entries in your browsing history.
Then follows n lines, each consisting of one URL whose length will not exceed 100.
Input is terminated by EOF.

 

Output

For each test case, output one line “Case X: Y” where X is the test case number (starting from 1) and Y is a number indicating the desired answer.

 

Sample Input

   
   
   
   

    
    
    
    1
aa.cc
2
www.google.com
www.wikipedia.org
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    Case 1: 438
Case 2: 1728
   
   
   
   

 

Source

2012 Asia Chengdu Regional Contest

 

水题不解释....

AC代码：

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;

int main()
{
	int n, k = 1;
	char a[105];
	while(~scanf("%d", &n))
	{
		int ans=0;
		n--;
		scanf("%s", a);
		for(int i=0; i<strlen(a); i++)
		{
			ans+=a[i];
		}
		while(n--)
		{
			scanf("%s", a);
			int tmp = 0;
			for(int i = 0; i<strlen(a); i++)
			{
				tmp += a[i];
			}
			if(tmp>ans) ans = tmp;
		}
		printf("Case %d: %d\n", k++, ans);
	}
	return 0;
}