【LeetCode从零单刷】Symmetric Tree

题目:

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).

For example, this binary tree is symmetric:

    1
   / \
  2   2
 / \ / \
3  4 4  3

But the following is not:

    1
   / \
  2   2
   \   \
   3    3
解答:

最开始非常脑残地希望补全二叉树,然后利用1,2,4,8个节点之间的关系来比较。结果越来越复杂。

还是那句话:碰上树,能递归就递归,不能递归就栈、队列。这次的递归要点:某节点的左子树的左子树 = 右子树的右子树,左子树的右子树 = 右子树的左子树。

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool compare(TreeNode* left, TreeNode* right)
    {
        if (!left && !right)    return true;
        if((!left && right) || (left && !right) || (left->val != right->val))   return false;
        return compare(left->left, right->right) && compare(left->right, right->left);
    }
    
    bool isSymmetric(TreeNode* root) {
        if (root == NULL || (!root->left && !root->right))   return true;
        else return compare(root->left, root->right);
    }
};

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