关于EnumerateObjectsUsingBlock和for-in之间的较量

遍历一个数组看谁快

参赛选手ForLoop,For - in,enumerateObjectsUsingBlock这个三个方法:

NSMutableArray *test = [NSMutableArray array]; for (int i = 0; i < 1000000; i ++) {
        [test addObject:@(i)];
    }

    __block int sum = 0; double date_s = CFAbsoluteTimeGetCurrent(); for (int i = 0; i < test.count; i ++) {
        sum += [test[i] integerValue];
    } double date_current = CFAbsoluteTimeGetCurrent() - date_s; NSLog(@"Sum : %d ForLoop Time: %f ms",sum,date_current * 1000);


    sum = 0;
    date_s = CFAbsoluteTimeGetCurrent(); for (NSNumber *num in test) {
        sum += [num integerValue];
    }
    date_current = CFAbsoluteTimeGetCurrent() - date_s; NSLog(@"Sum : %d For-in Time: %f ms",sum,date_current * 1000);


    sum = 0;
    date_s = CFAbsoluteTimeGetCurrent();
    [test enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
        sum += [obj integerValue];
    }];
    date_current = CFAbsoluteTimeGetCurrent() - date_s; NSLog(@"Sum : %d enumrateBlock Time: %f ms",sum,date_current * 1000);

最后输出如下:


打印输出
  • For-in方法最快速

    结论:

    当只是遍历一个数组的时候使用For-in会比较快速, 推荐使用For-in遍历数组.

通过Value查找Index看谁快

假如现在我们要查找一个Value, 这个Value 值是100001, 找出它的index (数组的序列号).

那么现在我们来比较一下
参赛选手For - in,enumerateObjectsUsingBlock,enumerateObjectsWithOptions这个三个方法: (ForLoop已经不再继续讨论了)

NSMutableArray *test = [NSMutableArray array]; for (int i = 0; i < 10000000; i ++) {
        [test addObject:@(i + 10)];
    } //For-in __block NSInteger index = 0; double date_s = CFAbsoluteTimeGetCurrent(); for (NSNumber *num in test) { if ([num integerValue] == 9999999) {
            index = [test indexOfObject:num]; break;
        }
    } double date_current = CFAbsoluteTimeGetCurrent() - date_s; NSLog(@"index : %ld For-in Time: %f ms",(long)index,date_current * 1000); //enumerateObjectsUsingBlock index = 0;
    date_s = CFAbsoluteTimeGetCurrent();
    [test enumerateObjectsUsingBlock:^(id num, NSUInteger idx, BOOL *stop) { if ([num integerValue] == 9999999) {
            index = idx;
            *stop = YES;
        }
    }];
    date_current = CFAbsoluteTimeGetCurrent() - date_s; NSLog(@"index : %ld enumerateBlock Time: %f ms",(long)index,date_current * 1000); //enumerateObjectsWithOptions index = 0;
    date_s = CFAbsoluteTimeGetCurrent();
    [test enumerateObjectsWithOptions:NSEnumerationConcurrent usingBlock:^(id num, NSUInteger idx, BOOL *stop) { if ([num integerValue] == 9999999) {
            index = idx;
            *stop = YES;
        }
    }];
    date_current = CFAbsoluteTimeGetCurrent() - date_s; NSLog(@"index : %ld enumerateObjectsWithOptions Time: %f ms",(long)index,date_current * 1000);

最后输出如下图:


打印输出
  • enumerateObjectsWithOptions方法最快速

    结论:

    通过Value查询index的时候, 面对大量的数组推荐使用enumerateObjectsWithOptions的并行方法.
    For-in和enumerateObjectsWithOptions方法这里我比较喜欢第二种写法简洁直观.

现在咱们要遍历字典

这里我们比较一下使用For-in和enumerateKeysAndObjectsUsingBlock这个两个方法:

NSDictionary *testDictionary = @{ @"Auther" : @"yyyyy", @"Game" : @"Dota", @"App" : @"dddddd", @"Market" : @"AppStore" }; //For - in NSMutableArray *forInArry = [NSMutableArray array]; double date_s = CFAbsoluteTimeGetCurrent(); NSArray *keys = [testDictionary  allKeys]; for (NSString *key in keys) { NSString *Value = testDictionary[key];
        [forInArry addObject:Value];
    } double date_current = CFAbsoluteTimeGetCurrent() - date_s; NSLog(@"index : %ld For-in Time: %f ms",(long)index,date_current * 1000); //enumerateKeysAndObjectsUsingBlock date_s = CFAbsoluteTimeGetCurrent(); NSMutableArray *enumArry = [NSMutableArray array];
    [testDictionary enumerateKeysAndObjectsUsingBlock:^(id key, id obj, BOOL *stop) {
        [enumArry addObject:obj];
    }];
    date_current = CFAbsoluteTimeGetCurrent() - date_s; NSLog(@"index : %ld For-in Time: %f ms",(long)index,date_current * 1000); NSLog(@"ForInArr: %@",forInArry); NSLog(@"enumArry: %@",enumArry);

打印输出:

关于EnumerateObjectsUsingBlock和for-in之间的较量_第1张图片
打印输出
  • enumerateKeysAndObjectsUsingBlock胜出

    结论:

    当我们想遍历字典类型的时候, 推荐使用enumerateKeysAndObjectsUsingBlock
    不仅仅是因为速度快, 更是因为代码更优雅和直观.


文/南国青天(简书作者)
原文链接:http://www.jianshu.com/p/ef3f1731a353
著作权归作者所有,转载请联系作者获得授权,并标注“简书作者”。

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