经典的函数式线段树题目,存下代码备忘。
#include <iostream> #include <cstdio> #include <cstdlib> #include <cmath> #include <queue> #include <algorithm> #include <vector> #include <cstring> #include <stack> #include <cctype> #include <utility> #include <map> #include <string> #include <climits> #include <set> #include <string> #include <sstream> #include <utility> #include <ctime> #include <bitset> using std::priority_queue; using std::vector; using std::swap; using std::stack; using std::sort; using std::max; using std::min; using std::pair; using std::map; using std::string; using std::cin; using std::cout; using std::set; using std::queue; using std::string; using std::stringstream; using std::make_pair; using std::getline; using std::greater; using std::endl; using std::multimap; using std::deque; using std::unique; using std::lower_bound; using std::random_shuffle; using std::bitset; using std::upper_bound; using std::multiset; typedef long long LL; typedef unsigned long long ULL; typedef unsigned UN; typedef pair<int, int> PAIR; typedef multimap<int, int> MMAP; typedef LL TY; typedef long double LF; const int MAXN(100010); const int MAXM(55); const int MAXE(200010); const int MAXK(6); const int HSIZE(13131); const int SIGMA_SIZE(26); const int MAXH(20); const int INFI((INT_MAX-1) >> 1); const ULL BASE(31); const LL LIM(1e13); const int INV(-10000); const LL MOD(1000000007); const double EPS(1e-7); const LF PI(acos(-1.0)); template<typename T> inline void checkmax(T &a, T b){if(b > a) a = b;} template<typename T> inline void checkmin(T &a, T b){if(b < a) a = b;} template<typename T> inline T ABS(const T &a){return a < 0? -a: a;} struct EDGE { int v, next; } edge[MAXE]; int first[MAXN], rear; void init(int n) { memset(first, -1, sizeof(first[0])*(n+1)); rear = 0; } void insert(int u, int v) { edge[rear].v = v; edge[rear].next = first[u]; first[u] = rear++; } struct LCA { int E[MAXN*2], dep[MAXN*2], pos[MAXN]; int back; int table[MAXH][MAXN*2]; void init() { back = 0; dfs(1, 0, -1); for(int i = 1; i <= back; ++i) table[0][i] = i; for(int i = 1; (1 << i) <= back; ++i) for(int j = 1; j+(1 << i)-1 <= back; ++j) table[i][j] = comp(table[i-1][j], table[i-1][j+(1 << (i-1))]); } void dfs(int u, int d, int f) { E[++back] = u; dep[back] = d; pos[u] = back; for(int i = first[u]; ~i; i = edge[i].next) if(edge[i].v != f) { dfs(edge[i].v, d+1, u); E[++back] = u; dep[back] = d; } } inline int comp(int a, int b) {return dep[a] < dep[b]? a: b;} int query(int a, int b) { a = pos[a]; b = pos[b]; if(a > b) swap(a, b); int len = b-a+1, temp = 0; while((1 << temp) <= len) ++temp; --temp; return E[comp(table[temp][a], table[temp][b-(1 << temp)+1])]; } } lca; int root[MAXN]; int ls[MAXN*36], rs[MAXN*36], sum[MAXN*36]; int back; void build(int l, int r, int &rt) { rt = ++back; sum[rt] = 0; if(l == r) return; int m = (l+r) >> 1; build(l, m, ls[rt]); build(m+1, r, rs[rt]); } void change(int prt, int &rt, int l, int r, int num) { rt = ++back; ls[rt] = ls[prt]; rs[rt] = rs[prt]; sum[rt] = sum[prt]+1; if(l == r) return; int m = (l+r) >> 1; if(num <= m) change(ls[prt], ls[rt], l, m, num); else change(rs[prt], rs[rt], m+1, r, num); } int fa[MAXN]; int query(int frt, int lrt, int rrt, int l, int r, int rk, int fval) { if(l == r) return l; int m = (l+r) >> 1; int sm = sum[ls[lrt]]+sum[ls[rrt]]-2*sum[ls[frt]]; if(fval >= l && fval <= m) sm += 1; if(rk <= sm) return query(ls[frt], ls[lrt], ls[rrt], l, m, rk, fval); else return query(rs[frt], rs[lrt], rs[rrt], m+1, r, rk-sm, fval); } int arr[MAXN], tab[MAXN], N; void dfs(int u, int f) { fa[u] = f; change(root[f], root[u], 1, N, arr[u]); for(int i = first[u]; ~i; i = edge[i].next) if(edge[i].v != f) dfs(edge[i].v, u); } int main() { int n, m; while(~scanf("%d%d", &n, &m)) { for(int i = 1; i <= n; ++i) { scanf("%d", arr+i); tab[i-1] = arr[i]; } sort(tab, tab+n); N = unique(tab, tab+n)-tab; for(int i = 1; i <= n; ++i) arr[i] = lower_bound(tab, tab+N, arr[i])-tab+1; init(n); int u, v; for(int i = 1; i < n; ++i) { scanf("%d%d", &u, &v); insert(u, v); insert(v, u); } lca.init(); back = 0; build(1, N, root[0]); dfs(1, 0); int rk; for(int i = 0; i < m; ++i) { scanf("%d%d%d", &u, &v, &rk); printf("%d\n", tab[query(root[lca.query(u, v)], root[u], root[v], 1, N, rk, arr[lca.query(u, v)])-1]); } } return 0; }