XPath 获取两个node中间的HTML Nodes
//div[@id="Recipe"]//h5[contains(text(),"Ingredients")]/following-sibling::p[count(.|//div[@id="Recipe"]//h5[contains(text(),"Method")]/preceding-sibling::p) = count(//div[@id="Recipe"]//h5[contains(text(),"Method")]/preceding-sibling::p)]
In XPath 1.0 one way to do this is by using the Kayessian method for node-set intersection:
$ns1[count(.|$ns2) = count($ns2)] The above expression selects exactly the nodes that are part both of the node-set $ns1 and the node-set $ns2.
To apply this to the specific question -- let's say we need to select all nodes between the 2nd and 3rd h3 element in the following XML document:
<html> <h3>Title T31</h3> <a31/> <b31/> <h3>Title T32</h3> <a32/> <b32/> <h3>Title T33</h3> <a33/> <b33/> <h3>Title T34</h3> <a34/> <b34/> <h3>Title T35</h3> </html> We have to substitute $ns1 with:
/*/h3[2]/following-sibling::node() and to substitute $ns2 with:
/*/h3[3]/preceding-sibling::node()Thus, the complete XPath expression is:
/*/h3[2]/following-sibling::node() [count(.|/*/h3[3]/preceding-sibling::node()) = count(/*/h3[3]/preceding-sibling::node()) ]We can verify that this is the correct XPath expression:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:template match="/"> <xsl:copy-of select= "/*/h3[2]/following-sibling::node() [count(.|/*/h3[3]/preceding-sibling::node()) = count(/*/h3[3]/preceding-sibling::node()) ] "/> </xsl:template> </xsl:stylesheet>When this transformation is applied on the XML document presented above, the wanted, correct result is produced:
<a32/> <b32/>II. XPath 2.0 solution:
Use the intersect operator:
/*/h3[2]/following-sibling::node() intersect /*/h3[3]/preceding-sibling::node()