【2-sat】 HDOJ 1815 Building roads

注意二分的上界可以达到1200000。。。

#include <iostream>  
#include <queue>  
#include <stack>  
#include <map>  
#include <set>  
#include <bitset>  
#include <cstdio>  
#include <algorithm>  
#include <cstring>  
#include <climits>  
#include <cstdlib>
//#include <cmath>
#include <time.h>
#define maxn 1005
#define maxm 3000005
#define eps 1e-10
#define mod 998244353
#define INF 999999999
#define lowbit(x) (x&(-x))
#define mp mark_pair
#define ls o<<1
#define rs o<<1 | 1
#define lson o<<1, L, mid  
#define rson o<<1 | 1, mid+1, R
//#pragma comment (linker,"/STACK:102400000,102400000")
typedef long long LL;
//typedef int LL;
using namespace std;
LL powmod(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base%mod;base=base*base%mod;b/=2;}return res;}
//void scanf(int &__x){__x=0;char __ch=getchar();while(__ch==' '||__ch=='\n')__ch=getchar();while(__ch>='0'&&__ch<='9')__x=__x*10+__ch-'0',__ch = getchar();}
// head

int h[maxn], next[maxm], v[maxm];
int low[maxn], dfn[maxn], ins[maxn];
int n, m1, m2, x1, y1, x2, y2;
struct point
{
	int x, y;
}po[maxn];
struct node
{
	int k1, k2;
}p1[maxn], p2[maxn];
int d[2][maxn];
int flag[maxn];
stack<int> s;
int cnt, dist, dfs_clock, c;

void scanf(int &x)
{
	x = 0;
	int ok = 0;
	char ch = getchar();
	while(ch == ' ' || ch == '\n') ch = getchar();
	if(ch == '-') ch = getchar(), ok = 1;
	while(ch >= '0' && ch <= '9') x = x*10 + ch - '0', ch = getchar();
	if(ok) x = -x;
}
void addedges(int u, int vv)
{
	next[cnt] = h[u], h[u] = cnt, v[cnt] = vv, cnt++;
}
void read(void)
{
	scanf(x1), scanf(y1), scanf(x2), scanf(y2);
	for(int i = 1; i <= n; i++) scanf(po[i].x), scanf(po[i].y);
	for(int i = 1; i <= m1; i++) scanf(p1[i].k1), scanf(p1[i].k2);
	for(int i = 1; i <= m2; i++) scanf(p2[i].k1), scanf(p2[i].k2);
}
void handle(void)
{
	for(int i = 1; i <= n; i++) {
		d[0][i] = abs(po[i].x - x1) + abs(po[i].y - y1);
		d[1][i] = abs(po[i].x - x2) + abs(po[i].y - y2);
	}
}
void init(void)
{
	cnt = c = dfs_clock = 0;
	dist = abs(x1 - x2) + abs(y1 - y2);
	memset(h, -1, sizeof h);
	memset(ins, 0, sizeof ins);
	memset(low, 0, sizeof low);
	memset(dfn, 0, sizeof dfn);
	memset(flag, 0, sizeof flag);
}
inline int abs(int a, int b)
{
	int tmp = a - b;
	if(tmp > 0) return tmp;
	else return -tmp;
}
void tarjan(int u)
{
	low[u] = dfn[u] = ++dfs_clock;
	s.push(u), ins[u] = 1;
	for(int e = h[u]; ~e; e = next[e])
		if(!dfn[v[e]]) {
			tarjan(v[e]);
			low[u] = min(low[u], low[v[e]]);
		}
		else if(ins[v[e]]) low[u] = min(low[u], dfn[v[e]]);
	if(low[u] == dfn[u]) {
		int tmp = s.top(); s.pop(), ins[tmp] = 0, ++c;
		while(tmp != u) {
			flag[tmp] = c;
			tmp = s.top(); s.pop(), ins[tmp] = 0;
		}
		flag[tmp] = c;
	}
}
bool check(int x)
{
	init();
	int dis;
	for(int i = 1; i <= m1; i++) {
		addedges(2*p1[i].k1, 2*p1[i].k2+1);
		addedges(2*p1[i].k1+1, 2*p1[i].k2);
		addedges(2*p1[i].k2, 2*p1[i].k1+1);
		addedges(2*p1[i].k2+1, 2*p1[i].k1);
	}
	for(int i = 1; i <= m2; i++) {
		addedges(2*p2[i].k1, 2*p2[i].k2);
		addedges(2*p2[i].k1+1, 2*p2[i].k2+1);
		addedges(2*p2[i].k2, 2*p2[i].k1);
		addedges(2*p2[i].k2+1, 2*p2[i].k1+1);
	}
	for(int i = 1; i <= n; i++)
		for(int j = i+1; j <= n; j++) {
			dis = d[0][i] + d[0][j];
			if(dis > x) addedges(2*i, 2*j+1), addedges(2*j, 2*i+1);
			dis = d[1][i] + d[1][j];
			if(dis > x) addedges(2*i+1, 2*j), addedges(2*j+1, 2*i);
			dis = d[0][i] + d[1][j] + dist;
			if(dis > x) addedges(2*i, 2*j), addedges(2*j+1, 2*i+1);
			dis = d[1][i] + d[0][j] + dist;
			if(dis > x) addedges(2*i+1, 2*j+1), addedges(2*j, 2*i);
		}
	for(int i = 2; i <= (n<<1) + 1; i++) if(!dfn[i]) tarjan(i);
	for(int i = 1; i <= n; i++) if(flag[2*i] == flag[2*i+1]) return false;
	return true;
}
void work(void)
{
	int bot = 0, top = 12000000, mid, res = -1;
	while(top >= bot) {
		mid = (top+bot)>>1;
		if(check(mid)) top = mid-1, res = mid;
		else bot = mid+1;
	}
	if(~res) printf("%d\n", res);
	else printf("-1\n");
}
int main(void)
{
	while(scanf("%d%d%d", &n, &m1, &m2)!=EOF) {
		read();
		handle();
		work();
	}
	return 0;
}


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