USACO 1.4 Prime Palindromes

构造所有回文再判断。 时间不完美。

Executing...
   Test 1: TEST OK [0.024 secs, 3504 KB]
   Test 2: TEST OK [0.027 secs, 3504 KB]
   Test 3: TEST OK [0.027 secs, 3504 KB]
   Test 4: TEST OK [0.024 secs, 3504 KB]
   Test 5: TEST OK [0.024 secs, 3504 KB]
   Test 6: TEST OK [0.024 secs, 3504 KB]
   Test 7: TEST OK [0.057 secs, 3504 KB]
   Test 8: TEST OK [0.065 secs, 3504 KB]
   Test 9: TEST OK [0.059 secs, 3504 KB]


/*
TASK:pprime
LANG:C++
*/
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <algorithm>
using namespace std;

int a[12];
int Q[800] = {0, 11, 0x7fffffff},tail=2;

void check(int t)
{
	int tmp = 0;
	for (int i = 1; i <= t; ++ i)	tmp = tmp * 10 + a[i];
	for (int j = 2; j <= sqrt(tmp); ++ j)
		if (!(tmp % j))	return;
	Q[++tail] = tmp;
}

void init()
{
	int tmp, t, j;
	for (int i = tmp = 3; i != 10000; tmp = ++ i)
	{
		t = 0;	
		while (tmp)
		{
			a[++t] = tmp % 10;
			tmp /= 10;		
		}
		if (!(a[t]&1))	continue;
		for (j = 1; j <=  t / 2; ++ j)	swap(a[j],a[t - j + 1]);
		for (j = 1; j < t; ++ j)	a[t + j] = a[t - j];	
		check(t * 2 - 1);
		for (j = 1; j <= t; ++ j)	a[t + j] = a[t - j + 1];
		check(t * 2);
	}
	sort(Q + 1, Q + 1 + tail);
}

int main()
{
	freopen("pprime.in","r", stdin);
	freopen("pprime.out", "w", stdout);
	ios::sync_with_stdio(false);
	init();
	int L, R;
	cin >> L >> R;
	for (int i = 1; ; ++ i)	
		if(Q[i]>=L)
		{
			L = i;
			break;	
		}
	cout<<Q[L]<<endl;
	while (Q[L + 1] <= R)	cout<<Q[++L]<<endl;
	return 0;	
}


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